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Thank you..pls. share it to other Φ6 enthusiasts.

love it sir!!

The description about the subsequent motion of a positive charge being circular happens only when the charge has emerged away from the parallel plates but the magnetic field outside the plates remains as is.

Only a coherent wave with a wavelength comparable to the size of the aperture demonstrates diffraction patterns. A water wave has relatively long wavelength thus diffraction was not observed.

The single-slit experiment done in a ripple tank with water shows a single wave with no interference whatsoever. Oddly, the same experiment done with light produces a fringe pattern. The idea of light being a wave should've been destroyed right there. Unfortunately, to save the wave dogma, Huygens had to invent his famous Huygens Principle as an ad hoc mathemagical solution, forcing a wave interference where it did not exist.

Glad to have you in my channel. Pls. find electronics-related videos in my Physics playlist. ❤

good day sir kulong, I was your grade 7 student during your last year stay in kisay and the videos you post here are very informative and aligned with what I am currently taking in UP Diliman. hoping for more videos related to electronics and physics and I'm hoping that your channel will grow much further!

Erratum: Towards the end of the video the narrator inadvertently called the mass M as the mass of the planet. He actually meant the mass of the star.

Lapsus lingua: There's a typo error in getting the value for alpha α₂ of rod 2. Instead of writing 0.0650 cm for the ΔL it should have been 0.0350 cm. My apology...

ERRATUM: The formula for the normal force at point B was inadvertently written as m(vₜₐₙ² - g) which should have been m(vₜₐₙ²/r - g). Sorry for this typo error.

Thank you po sir 🫡

ERRATUM: The computed maximum acceleration for Q-3 should be 10. m/s² (NOT 8.5 x 10⁻³). Sorry for this error.

Whether or not the coconut has been picked up by someone is an irrelevant assumption. Logic and correct Φ6 concepts is what matters.

ERRATUM: In explaining the ans. to question (d) I inadvertently typed and mentioned N as the symbol for the final activity when the correct symbol should have been A.

In question 1 the given condition that the linear velocity changes, it assumes only the magnitude of the velocity is changing but NOT the direction of velocity.

Congrats. Very good explanation

Lapsus lingua: Sorry for inadvertently saying " the flow speed is inversely proportional to the cross-sectional area of the FLOW SPEED (should have been flow tube).❤😊

But that is assuming that no one picked up the coconut after it has fallen. Haha. For me this problem is just wrong

panoorin niyo po si sir, matagal na po experience sa teaching at magaling po siyang guro.

ang galing niyo pong guro sir!

A more valid reason why letter A. 55 g (in Q-2) is the correct answer following the rule for addition: The given quantity (20. g) has no decimal place while the other given quantity (35.00 g) has 2 decimal places so their sum should be rounded to the nearest whole number (no decimal place). The reason given by the narrator ("since 20. g has 2 sigfig, the sum must also have 2 sigfig") is just a coincidence. If the given quantities were 135.00 g + 20. g then their sum (155.00 g) when rounded to the nearest whole number (without a decimal) would be 155 g and NOT 160 g (2 sigfig).

Lapsus Lingua: While describing the meaning of d₂ in Problem 2, the author inadvertently called 6.96 x 10⁸ m as radius of the earth (he actually meant radius of the sun).

Lapsus lingua: While explaining the right-hand slap rule in Example 3, I inadvertently said that when the velocity vector v⃗ (thumb) doesn't make a 90⁰ angle with the magnetic field vector B⃗ , the component of the magnetic force F⃗ perpendicular to the v⃗ and B⃗ vectors is to be considered. This is incorrect. I should have said the perpendicular component of either v⃗ or B⃗ must be chosen. The B⃗ and v⃗ are NOT necessarily perpendicular to each other. If the angle θ between them is not equal to 90⁰ we still need to find the sin value of θ which results to a force F as implied in the formula; F = B⃗ q x v⃗ sin θ . The resulting force is ALWAYS perpendicular to both B⃗ and v⃗. It is B⃗ or v⃗ that may or may not be perpendicular to each other but the resulting force (provided the angle θ is not 0⁰ or 180⁰) is the one that is always directed perpendicular to the other 2 vectors.

Sorry for inadvertently saying that 1 Bq equals 3.7 x 10⁻¹⁰ Ci. What is right is: 1 Bq equals the reciprocal of 3.7x10¹⁰ Ci or 2.7 x 10⁻¹¹ Ci.

Thanks for the reminder. It is highly appreciated.

Sorry for this error: the vertical displacement equation given in the table should be: Δy = v₀y(t) + 1/2 gt² (NOT Δy=v₀y² +1/2 gt²)

THank you po sirr! Laking tulong po!

Sorry for the typo error in the given: g = -10 m/s²