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21) ABC is an isosceles triangle with AB = AC. Draw AP ⊥ BC to show that ∠B = ∠C. #Class IX #Math
5) ABC is an isosceles triangle with AB = AC. Draw AP ⊥ BC to show that
∠B = ∠C.
มุมมอง: 17

วีดีโอ

19) Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR4:0219) Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR
19) Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR
มุมมอง 169 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex: 7.2 3. Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of Δ PQR (see Fig. 7.40). Show that: (i) Δ ABM ≅ Δ PQN (ii) Δ ABC ≅ Δ PQR
20) BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the2:5220) BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the
20) BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the
มุมมอง 279 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex: 7.3 4) BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.
18) AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC2:4918) AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC
18) AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC
มุมมอง 299 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex: 7.3 2) AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC (ii) AD bisects ∠ A.
17) ΔABC and ΔDBC are two isosceles triangles on same base BC & vertices A & D are on same side BC6:5617) ΔABC and ΔDBC are two isosceles triangles on same base BC & vertices A & D are on same side BC
17) ΔABC and ΔDBC are two isosceles triangles on same base BC & vertices A & D are on same side BC
มุมมอง 69 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex:7.1 1) Δ ABC and Δ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that (i) Δ ABD ≅ Δ ACD (ii) Δ ABP ≅ Δ ACP (iii) AP bisects ∠ A as well as ∠ D. (iv) AP is the perpendicular bisector of BC.
16) Show that the angles of an equilateral triangle are 60° each. Ex:7.2 #Class IX #Math #CBSE1:5416) Show that the angles of an equilateral triangle are 60° each. Ex:7.2 #Class IX #Math #CBSE
16) Show that the angles of an equilateral triangle are 60° each. Ex:7.2 #Class IX #Math #CBSE
มุมมอง 359 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex:7.2 8. Show that the angles of an equilateral triangle are 60° each.
13) ABC and DBC are two isosceles triangles on same base BC (see Fig. 7.33). Show that ∠ABD = ∠ACD.3:2213) ABC and DBC are two isosceles triangles on same base BC (see Fig. 7.33). Show that ∠ABD = ∠ACD.
13) ABC and DBC are two isosceles triangles on same base BC (see Fig. 7.33). Show that ∠ABD = ∠ACD.
มุมมอง 189 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex:7.2 5. ABC and DBC are two isosceles triangles on the same base BC (see Fig. 7.33). Show that ∠ABD = ∠ACD.
09.07.05 NCERT Ex: 7.3 solution #Class IX #Math #CBSE Ch:7 Triangles18:0409.07.05 NCERT Ex: 7.3 solution #Class IX #Math #CBSE Ch:7 Triangles
09.07.05 NCERT Ex: 7.3 solution #Class IX #Math #CBSE Ch:7 Triangles
มุมมอง 2212 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles 09.07.05 NCERT Ex: 7.3 solution
15) ABC is a right angled triangle in which ∠A = 90°and AB = AC. Find ∠B and ∠C. Ex:7.2 #ClassIX3:3215) ABC is a right angled triangle in which ∠A = 90°and AB = AC. Find ∠B and ∠C. Ex:7.2 #ClassIX
15) ABC is a right angled triangle in which ∠A = 90°and AB = AC. Find ∠B and ∠C. Ex:7.2 #ClassIX
มุมมอง 5012 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles
14) ΔABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB.5:0114) ΔABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB.
14) ΔABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB.
มุมมอง 2812 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex:7.2 6) ΔABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB (see Fig. 7.34). Show that ∠ BCD is a right angle.
2) Olympiad Qs - Find area of green rectangle. #ClassVIII #Math #CBSE Ch:10 Mensuration5:142) Olympiad Qs - Find area of green rectangle. #ClassVIII #Math #CBSE Ch:10 Mensuration
2) Olympiad Qs - Find area of green rectangle. #ClassVIII #Math #CBSE Ch:10 Mensuration
มุมมอง 3714 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles
12) ABC is a triangle in which altitudes BE & CF to sides AC & AB are equal (see Fig. 7.32). Show4:4412) ABC is a triangle in which altitudes BE & CF to sides AC & AB are equal (see Fig. 7.32). Show
12) ABC is a triangle in which altitudes BE & CF to sides AC & AB are equal (see Fig. 7.32). Show
มุมมอง 2414 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles 4) ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see Fig. 7.32). Show that (i) Δ ABE ≅ Δ ACF (ii) AB = AC, i.e., ABC is an isosceles triangle.
11) ABC is isosceles triangle in which altitudes BE & CF are drawn to equal sides AC & AB respective2:3411) ABC is isosceles triangle in which altitudes BE & CF are drawn to equal sides AC & AB respective
11) ABC is isosceles triangle in which altitudes BE & CF are drawn to equal sides AC & AB respective
มุมมอง 3814 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex:7.2 3) ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see Fig. 7.31). Show that these altitudes are equal.
10) In ΔABC, AD is perpendicular bisector of BC (Fig. 7.30). Show that ΔABC is isosceles triangle2:2310) In ΔABC, AD is perpendicular bisector of BC (Fig. 7.30). Show that ΔABC is isosceles triangle
10) In ΔABC, AD is perpendicular bisector of BC (Fig. 7.30). Show that ΔABC is isosceles triangle
มุมมอง 2814 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex:7.2 2) In Δ ABC, AD is the perpendicular bisector of BC (see Fig. 7.30). Show that Δ ABC is an isosceles triangle in which AB = AC.
9) In an isosceles triangle ABC, with AB = AC, bisectors of ∠B & ∠C intersect each other at O.3:569) In an isosceles triangle ABC, with AB = AC, bisectors of ∠B & ∠C intersect each other at O.
9) In an isosceles triangle ABC, with AB = AC, bisectors of ∠B & ∠C intersect each other at O.
มุมมอง 4114 ชั่วโมงที่ผ่านมา
#Class IX #Math #CBSE #NCERT Ch:7 Triangles Ex: 7.2 1) In an isosceles triangle ABC, with AB = AC, the bisectors of ∠ B and ∠ C intersect each other at O. Join A to O. Show that : (i) OB = OC (ii) AO bisects ∠ A
1) Olympiad Qs. Find area of Square divided in 6 equal part. #ClassVIII #Math Ch:10 Mensuration3:131) Olympiad Qs. Find area of Square divided in 6 equal part. #ClassVIII #Math Ch:10 Mensuration
1) Olympiad Qs. Find area of Square divided in 6 equal part. #ClassVIII #Math Ch:10 Mensuration
มุมมอง 2314 ชั่วโมงที่ผ่านมา
1) Olympiad Qs. Find area of Square divided in 6 equal part. #ClassVIII #Math Ch:10 Mensuration
1) Olympiad Qs - find sum of all angles. (5x5 square) #ClassVIII #Math #CBSE Ch:3 Understanding3:321) Olympiad Qs - find sum of all angles. (5x5 square) #ClassVIII #Math #CBSE Ch:3 Understanding
1) Olympiad Qs - find sum of all angles. (5x5 square) #ClassVIII #Math #CBSE Ch:3 Understanding
มุมมอง 4214 ชั่วโมงที่ผ่านมา
1) Olympiad Qs - find sum of all angles. (5x5 square) #ClassVIII #Math #CBSE Ch:3 Understanding
09.07.04 NCERT Ex 7.2 solution #Class IX #Math #CBSE Ch:7 Triangles18:2609.07.04 NCERT Ex 7.2 solution #Class IX #Math #CBSE Ch:7 Triangles
09.07.04 NCERT Ex 7.2 solution #Class IX #Math #CBSE Ch:7 Triangles
มุมมอง 4816 ชั่วโมงที่ผ่านมา
09.07.04 NCERT Ex 7.2 solution #Class IX #Math #CBSE Ch:7 Triangles
7) AB is line segment & P is its mid-point. D and E are pts on same side of AB such that ∠BAD = ∠ABE2:527) AB is line segment & P is its mid-point. D and E are pts on same side of AB such that ∠BAD = ∠ABE
7) AB is line segment & P is its mid-point. D and E are pts on same side of AB such that ∠BAD = ∠ABE
มุมมอง 3416 ชั่วโมงที่ผ่านมา
7) AB is line segment & P is its mid-point. D and E are pts on same side of AB such that ∠BAD = ∠ABE
6) In Fig. 7.21, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. #Class IX #Math Ch:7 Triangles2:516) In Fig. 7.21, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. #Class IX #Math Ch:7 Triangles
6) In Fig. 7.21, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. #Class IX #Math Ch:7 Triangles
มุมมอง 3316 ชั่วโมงที่ผ่านมา
6) In Fig. 7.21, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. #Class IX #Math Ch:7 Triangles
5) Line l is bisector of angle ∠A & B is point on l. BP & BQ are perpendicular from B to arm of ∠A2:215) Line l is bisector of angle ∠A & B is point on l. BP & BQ are perpendicular from B to arm of ∠A
5) Line l is bisector of angle ∠A & B is point on l. BP & BQ are perpendicular from B to arm of ∠A
มุมมอง 4319 ชั่วโมงที่ผ่านมา
5) Line l is bisector of angle ∠A & B is point on l. BP & BQ are perpendicular from B to arm of ∠A
4) l & m are parallel lines intersected by another pair of parallel lines p & q. Show ΔABC ≅ ΔCDA.2:194) l & m are parallel lines intersected by another pair of parallel lines p & q. Show ΔABC ≅ ΔCDA.
4) l & m are parallel lines intersected by another pair of parallel lines p & q. Show ΔABC ≅ ΔCDA.
มุมมอง 3219 ชั่วโมงที่ผ่านมา
4) l & m are parallel lines intersected by another pair of parallel lines p & q. Show ΔABC ≅ ΔCDA.
3) AD and BC are equal perpendiculars to a linesegment AB (see Fig. 7.18). Show that CD bisects AB.2:213) AD and BC are equal perpendiculars to a linesegment AB (see Fig. 7.18). Show that CD bisects AB.
3) AD and BC are equal perpendiculars to a linesegment AB (see Fig. 7.18). Show that CD bisects AB.
มุมมอง 2919 ชั่วโมงที่ผ่านมา
3) AD and BC are equal perpendiculars to a linesegment AB (see Fig. 7.18). Show that CD bisects AB.
2) ABCD is quadrilateral in which AD = BC & ∠DAB = ∠CBA (see Fig. 7.17). Prove that(i) Δ ABD ≅ Δ BAC2:452) ABCD is quadrilateral in which AD = BC & ∠DAB = ∠CBA (see Fig. 7.17). Prove that(i) Δ ABD ≅ Δ BAC
2) ABCD is quadrilateral in which AD = BC & ∠DAB = ∠CBA (see Fig. 7.17). Prove that(i) Δ ABD ≅ Δ BAC
มุมมอง 4219 ชั่วโมงที่ผ่านมา
2) ABCD is quadrilateral in which AD = BC & ∠DAB = ∠CBA (see Fig. 7.17). Prove that(i) Δ ABD ≅ Δ BAC
09.07.03 NCERT Ex:7.1 solution #Class IX #Math #CBSE Ch:7 Triangles23:2409.07.03 NCERT Ex:7.1 solution #Class IX #Math #CBSE Ch:7 Triangles
09.07.03 NCERT Ex:7.1 solution #Class IX #Math #CBSE Ch:7 Triangles
มุมมอง 2321 ชั่วโมงที่ผ่านมา
09.07.03 NCERT Ex:7.1 solution #Class IX #Math #CBSE Ch:7 Triangles
8.03.01 Classification of quadrilaterals - Based on side & diagonal Ch:8 Understanding Quadrilateral12:418.03.01 Classification of quadrilaterals - Based on side & diagonal Ch:8 Understanding Quadrilateral
8.03.01 Classification of quadrilaterals - Based on side & diagonal Ch:8 Understanding Quadrilateral
มุมมอง 3821 ชั่วโมงที่ผ่านมา
8.03.01 Classification of quadrilaterals - Based on side & diagonal Ch:8 Understanding Quadrilateral
08.03.02 Area of quadrilaterals #Class VIII #Math #CBSE6:2008.03.02 Area of quadrilaterals #Class VIII #Math #CBSE
08.03.02 Area of quadrilaterals #Class VIII #Math #CBSE
มุมมอง 51วันที่ผ่านมา
08.03.02 Area of quadrilaterals #Class VIII #Math #CBSE
10.10.01 Different parts of circle #Class X #Math #CBSE Ch:10 Circles4:0610.10.01 Different parts of circle #Class X #Math #CBSE Ch:10 Circles
10.10.01 Different parts of circle #Class X #Math #CBSE Ch:10 Circles
มุมมอง 32วันที่ผ่านมา
10.10.01 Different parts of circle #Class X #Math #CBSE Ch:10 Circles
08.12.03 factorization using algebraic identity a^2-b^2 = (a+b)(a-b) #Class VIII #Math #CBSE38:2908.12.03 factorization using algebraic identity a^2-b^2 = (a+b)(a-b) #Class VIII #Math #CBSE
08.12.03 factorization using algebraic identity a^2-b^2 = (a+b)(a-b) #Class VIII #Math #CBSE
มุมมอง 29วันที่ผ่านมา
08.12.03 factorization using algebraic identity a^2-b^2 = (a b)(a-b) #Class VIII #Math #CBSE
13) ABC is triangle right angled at C. A line through mid-point M of hypotenuse AB & parallel to BC3:2313) ABC is triangle right angled at C. A line through mid-point M of hypotenuse AB & parallel to BC
13) ABC is triangle right angled at C. A line through mid-point M of hypotenuse AB & parallel to BC
มุมมอง 152วันที่ผ่านมา
13) ABC is triangle right angled at C. A line through mid-point M of hypotenuse AB & parallel to BC

ความคิดเห็น

  • @user-ru6ny4ql1
    @user-ru6ny4ql1 4 นาทีที่ผ่านมา

    ❤

  • @PrithwirajSen-nj6qq
    @PrithwirajSen-nj6qq วันที่ผ่านมา

    Extend AD & BC as they intersect at P Then 🔺 PAB & 🔺 PDC are similar Then PA /PD = PB /PC > (PD+AD)/PD =( PC +BC) /PC > 1+ AD/PD = 1+ BC/PC > AD /PD =BC /PC > PD/PC=AD/BC=1 Hence PD =PC PD +AD =PC +BC PA = PB Hence in 🔺 PAB ang PAB = ang PBA In trapezium ang DAB = ang CBA--(1) Again ang CBA + ang BCD = 180 degs >ang DAB + ang BCD =180 degs ( using relation 1) These angles are opposite angles of the trapezium. Hence the trapezium is cyclic.

  • @PrithwirajSen-nj6qq
    @PrithwirajSen-nj6qq 2 วันที่ผ่านมา

    Third Method Join OB. Triangle OBC isosceles 🔺 as OA =OB (both r radii) Hence ang OAB=ang OBA --(1) Triangle OBC is also isosceles 🔺 OB=OA(both r radii ) Hence Ang OBC = ang OCB--(2) OABC quadrilateral. AOB=90 degs Hence OCB +OBC +OBA+OAB=360-90=270 degs > 2 ang ABC=270 degs ang ABC =135 degs

  • @asratwani
    @asratwani 2 วันที่ผ่านมา

    Sir important questions exmplxx sir

  • @asratwani
    @asratwani 2 วันที่ผ่านมา

    Aw sir

  • @charansinghrawat8165
    @charansinghrawat8165 2 วันที่ผ่านมา

    Thanks you bhaya❤😊

  • @charansinghrawat8165
    @charansinghrawat8165 2 วันที่ผ่านมา

    Maja aaa gaya

  • @kalpananegi1285
    @kalpananegi1285 2 วันที่ผ่านมา

    Thanks yar❤❤

  • @boomaprabakar924
    @boomaprabakar924 2 วันที่ผ่านมา

    Thank you sir, clearly understood

  • @boomaprabakar924
    @boomaprabakar924 2 วันที่ผ่านมา

    Clearly explained sir,thank you

  • @dhanyaprasad3993
    @dhanyaprasad3993 5 วันที่ผ่านมา

    Very nice class

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

    • @asratwani
      @asratwani 2 วันที่ผ่านมา

      Aw ap thk hoo sir ap kaha sy hooo sir please imp questions for exm 2024 Nov

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @CBSE.classes5632
    @CBSE.classes5632 6 วันที่ผ่านมา

    th-cam.com/play/PLXRaddUU-c8GqL0CMAD7Z9elR49CxCoCw.html Class IX - Ch:7 "Triangles"

  • @PrithwirajSen-nj6qq
    @PrithwirajSen-nj6qq 7 วันที่ผ่านมา

    May I request u to pay a look in problem 1 Pl see the starting of ' proof ' portion where u wrote which is waiting to be proved. This may be omitted. Problem 6. There r 3 angles in vertex C which is the vertex of three triangles and makes three angles in point C These angles may be denoted properly to segregate the three angles at point C. Otherwise I like it.

    • @CBSE.classes5632
      @CBSE.classes5632 7 วันที่ผ่านมา

      Good points I will definitely implement then in next video.

    • @PrithwirajSen-nj6qq
      @PrithwirajSen-nj6qq 7 วันที่ผ่านมา

      @CBSE.classes5632 thanks .Go on.

  • @PrithwirajSen-nj6qq
    @PrithwirajSen-nj6qq 7 วันที่ผ่านมา

    Please check. U did not prove BD=AC But u proved AD= BC which is a given condition. Moreover in case of congruent triangles, how will we determine the corresponding sides and angles, requires to be clarified.

    • @CBSE.classes5632
      @CBSE.classes5632 7 วันที่ผ่านมา

      yes . . 2nd last statement shall be "Thus BD = AC" Rest related "how will we determine the corresponding sides and angles" . . I will add the explanation in future videos

  • @kumarl5785
    @kumarl5785 8 วันที่ผ่านมา

    How did you get 5

    • @CBSE.classes5632
      @CBSE.classes5632 7 วันที่ผ่านมา

      In Qs - its given that circle radius is 5m

  • @a.k.studyclasses2479
    @a.k.studyclasses2479 8 วันที่ผ่านมา

    ❤❤❤❤

  • @cyruschang1904
    @cyruschang1904 8 วันที่ผ่านมา

    4α + 2(40°) = 360° 4α = 280° α = 70°

  • @wasimahmad-t6c
    @wasimahmad-t6c 8 วันที่ผ่านมา

    65

  • @PrithwirajSen-nj6qq
    @PrithwirajSen-nj6qq 8 วันที่ผ่านมา

    U said that AB is the common tangent of the circles. It is the common chord.

  • @GouthamV-gl5zf
    @GouthamV-gl5zf 9 วันที่ผ่านมา

    😊

  • @himadrikhanra7463
    @himadrikhanra7463 10 วันที่ผ่านมา

    We have to form scissors by drawing line , don't have pen & paper , most probably either 270 ^0 or 90 ^0 ?

    • @CBSE.classes5632
      @CBSE.classes5632 10 วันที่ผ่านมา

      From 1st look - its clear that ans is between 90 - 180

  • @divyanshusharma4244
    @divyanshusharma4244 11 วันที่ผ่านมา

    Nice explain

  • @Itsgmaer82
    @Itsgmaer82 11 วันที่ผ่านมา

    ❤

  • @HarshitSahu-i4y
    @HarshitSahu-i4y 12 วันที่ผ่านมา

    Awesome🎉

  • @SanjayYadav-tq6qd
    @SanjayYadav-tq6qd 14 วันที่ผ่านมา

    Thank you😊😊

  • @TyyylerDurden
    @TyyylerDurden 15 วันที่ผ่านมา

    Construct a full circle from the equal quarters, and you will get an octagon. An angle in octagon = 135.

    • @CBSE.classes5632
      @CBSE.classes5632 15 วันที่ผ่านมา

      Great . . We will have to just consider a specific case where red and green line segments are equal in length - and then octagon will be regular.

  • @TyyylerDurden
    @TyyylerDurden 16 วันที่ผ่านมา

    r= 4 * root 2

  • @kavyakavyaa4571
    @kavyakavyaa4571 17 วันที่ผ่านมา

    🎉tq

  • @priyankajain3515
    @priyankajain3515 18 วันที่ผ่านมา

    Very nice explanation

  • @DhjjhvfrFgkgfjfj
    @DhjjhvfrFgkgfjfj 20 วันที่ผ่านมา

    Very nice

  • @markrjsarong9072
    @markrjsarong9072 22 วันที่ผ่านมา

    Thank you sir🙏

  • @ManojKumar-e3h5c
    @ManojKumar-e3h5c 24 วันที่ผ่านมา

    3 power 350 is greater

  • @ManojKumar-e3h5c
    @ManojKumar-e3h5c 24 วันที่ผ่านมา

    5 power32 is greater answer

  • @amarrathaur2189
    @amarrathaur2189 หลายเดือนก่อน

    सर किस बुक से आप पढ़ाते हो बताएं

  • @kavitajharsi6216
    @kavitajharsi6216 หลายเดือนก่อน

    Thank u so much sir

  • @VanshAsolkar
    @VanshAsolkar หลายเดือนก่อน

    😢😢 aagya smaj sir 😊

  • @AnimeFan-d3v
    @AnimeFan-d3v หลายเดือนก่อน

    Thank you so much tomorrow is my exam snd you helped me 😅

  • @RupinderkaurRupinderkaur-ju1mw
    @RupinderkaurRupinderkaur-ju1mw หลายเดือนก่อน

    Thank a alot

  • @VidhiVidhi-q1j
    @VidhiVidhi-q1j หลายเดือนก่อน

    Thanks

  • @rishabbanerjee6516
    @rishabbanerjee6516 หลายเดือนก่อน

    ❤

  • @MushirfShah
    @MushirfShah 2 หลายเดือนก่อน

    Nice