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Thanks for this, the simplified formula in 3:51 helped a lot. I realized I could actually use variants of this formula to solve the rest of the equations. ex: for the beads and cm questions I did: 306 - 40s = 210 - 24s (s representing segments) Since the solution wanted cm, I multiplied the solution for segments by 5 to find the answer.

Thank you very much!

you just gained a new subscriber. the downside of khan academy is that it always jumps on practice questions without even talking about the overview context of the lessons, formulas, and key points. we have to do it by ourselves. it shouldn't be a problem, only i'm a little bit dumb so i'm stuck. thank you sir !!

Excellent , Thank you very much 😊

Doing the Khan Academy course, Algebra one 'Comparing linear rates word problems,' spooked me and some people out according to the Khan comments. Looking through the lens D=R*T , I can now transfer the wording into something that I understand.

I just learned this at school and I forgot the proof, you're a life saver thank you dude

Thank you, and i didnt even watch the video yet, sal needs to fix that unit

Thank you so much man! This problem pissed me off but your video is very helped!!!

i tried this method fir g(x)=0.5cos(1/3x+2pi/3)-2 and it did not work finding the period gave me 3/4pi which was incorrect anyway u could walk me through this one step by step? not sure where im getting confused at

thank u

literally made me understand everything

Wow this cleared everything up for me. My brain just wasn’t grasping this on Khan’s website for some reason

what

thank you so much litterally been getting this wrong for over 3 days now!

This helped me a lot, thanks!

12:27 why is it not 13T + 9.5T? The total cost is 13 + 9.5 right?

Thank you very much.

tysm this video is rly helpful for my math test!! keep it up

Thank you!😄

thanks man!!!

Thanks a ton, i forgot d=r×t. Made these problems very simple

you needa get a better mic dude

Thank you so much for this! ive been struggling on rate conversion for so long and it wasnt until i found this that i understood it so much easier! wish i found it sooner this really helped. <3

nice vid good job hahahahahahaahhah come in my home for free candy my kids

Thank you Sir for this beautiful course.

Thank you so much for doing these videos ! Hope you won't stop !

Thank you so so much !

this was rlly helpful way more helpful than the khan accademt video for this section thank you!!

this was rlly helpful way more helpful than the khan accademt video for this section thank you!!

Fascinating

Idk why, but khan academy doesn’t seem to have a video explaining the phase shift. Thanks for the clarification

I HAVE BEEN STUCK ON THIS ACTIVITY FOR SO LONG. I haven’t watched the video yet, but i hope it helps. the one video example we khan gave us didn’t help enough.

This really helped, thank you so much!

Why dont you have to times the like terms in the brackets?

Do you really need to put plus or minus the period since n can be any integer negative or positive?

Thank you so much! Truly appreciate your help. May God bless you

You're an absolute lifesaver, thanks mate ❤

Thanks!

... Good day sir Khan, We could also rewrite 75 & 85 as follows ... 75 = 5 * 15 & 85 = 5 * 17 , so instead of working with the big numbers, we first reduce them applying the GCD (= 5) ... now we can follow your systematic procedure with 15 and 17 , trying to find X ... so 17^2 - 15^2 = 64 = X^2 ... X = 8 ... of course not forgetting the factor 5 ... finally writing the solution as 5 * 8 , 5 * 15 , 5 * 17 ... 40 , 75 , 85 ... the (multiple) triplet of 8 , 15 , 17 ... just an idea, making calculations a bit easier?! ... thank you sir for the clear explanation ... best regards, Jan-W

... Good day sir Khan, I often tend to connect formulas in math, so not needing to memorize too much, especially regarding trig. topics ... so for me Pythagoras' c^2 = a^2 + b^2 is a special case of the COSINE rule c^2 = a^2 + b^2 - 2*a*b*COS(Gamma) , where Angle(Gamma), the angle opposite side c, = 90 deg. ... so 2*a*b*COS(90 deg.) = 0 ... giving us c^2 = a^2 + b^2 ... nice and clear presentation sir ... best regards, Jan-W

Could you make a video on justify triangle congruence please?

thank you

i swear you explain trig so much easier than khan

thank you so much

thank you so much for your videos dude

This was super helpful! Thank you!

thank you bro i'm still having trouble but this helped

Best video 🎉 you the 🐐

This really helped, thanks!

Thank you. I just saw a word problem on Khan academy's site that threw me into cold shiver. It literally is like a mathematical voodoo, with the teacher going from simple equations to linear equations and word problems with no formulas or explanations whatsoever. It brought me to tears. Thank you for taking the time to break it down. And bring some hope .... I really do appreciate your help.