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Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

comment I was having

@user-tv6rp4sh2b Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

@user-hj9yj6pl8i www.emtalk.com/mscalc.php

Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

he created another rectangle to extend the original feeder to decrease the overall impedance, from my understanding

have you found?

The current for that 2ohms will be zero so it will be(2×0)

Current isn't entering the 2ohms below ... Current is only moving along the side of the circuit

Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

This is most likely too late, but this may help others. Generally, you want the "gap" denoted as "g" to be g > 2 * microstrip width. For a more detailed approximation of the gap, Mohammad Abdul Matin wrote a paper called "A design rule for inset-fed rectangular microstrip patch antenna". It provides (general) insights on the approximations emtalk used (most likely) to generate those values.

This was done in ADS

The total resistance without the 2 ohms, is gonna be Rth = (2//3)+(2//2)

Hi @Zara !! You can use emtalk to carry out this process. Link here: www.emtalk.com/mscalc.php

@@kinemarc Thanks

Looking at the loop which contains the 2 ohm you’re talking about, you’ll realize that that loop was open and that no current flows through that loop . So basically, you cannot write a KVL equation without a current flowing through the resistor. i.e., V = IR

I still don't get it, it doesn't make sense

Can you be specific with the particular question you're talking about? You can use the time stamp to help me know the particular question.

I'm glad it helped.

Welcome 🙏🏽

@Ledwaba Welcome🙏🏽

Hi @Anis there's no formula to use in finding the width and length of the substrate but depending on your patch size and feedline size, you then pick an appropriate size to accommodate them. Read from here with regards to the gap's length and width. www.researchgate.net/post/Formal_equation_for_finding_the_Width_and_Gap_calculation_for_CPW_fed_patch_antenna. I hope this helps.

@@kinemarc what abou length and width for connector, konnector and t junction . what formula did you use to calculate ? i know you use calculator online (emtalk) did you have formula that i can calculate ?

@@anisnajibah4265 I used emtalk to calculate the length and width depending on the impedance value

@Eddie Mensah, if you take a look at the question well you find out that in finding the total resistance(RN), the other path is not short circuit but it is an open circuit Look at it from this way 1. Place a voltage source between the terminals from which I was finding the total resistance 2. Now if that voltage source produces current, you will see that it will split between the 4ohm and 6ohm. 3. Now since there will be different current through the 4ohm and 6ohm resistors, it makes the be in parallel not series