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Also learn Unit Load Method. Procedure is almost same as that of Castiglianos Method. Only last one step changes

All the best for your Exam

Ok sir thank u

Anna small help moment distribution problem lo stiffness.k formula ela thiskovali Anna intermediate support ki

If far end is fixed, then K = I/L and If far end is hinged, then K = 0.75*I/L or (3/4)*(I/L)

Mostly derivations are not asked in exams. You just focus more on numerical problems. And if you have time then go for derivations.

I revisited the problem and found nothing wrong in it. All the values were substituted as per the formula. If you still not able to get clarity, please feel free to comment again with your doubt.

@@AbhishekCivilTech ok

In SA-2 there are few more topics left like Suspension Bridges(Problems on Girders) and also matrix methods(Stiffness and Flexibility). Let me complete those as well

Super! I am also thinking to start the same subject that you are asking for. Coming soon!!

Glad to hear that from you

If there are any calculation mistakes, ignore it and follow the procedure. Thanks for Watching

I though of making those calculations as well. But video becomes much lengthy and it may go for 2 parts. So please follow the same procedure that was followed for P0 forces. Thanks for Watching

You can follow same process for that member as well

So glad to hear that. All the best.

If there are any calculation mistakes please ignore them and follow the procedure. Thanks for Watching.

If you want to solve manually, you can go for matrix methods like Matrix Inversion Method, Gauss Jordan Method, Cramers Method. or You can use scientific calculator and using mode option, selecting appropriate format of equation like ax+by+cz=d. You enter coefficient values. I will make a video soon you will get more clarity. Thanks for watching

Thank you very much. I will certainly make more videos

Yes, We should consider one load only. Because another load is acting on the joint, not on the member AB. If it is acting on the member then we should consider that as well. The load which is acting on the joint does not produce any moment because in first step we assume Joint B as Fixed Support. Hope your doubt got cleared. Thanks for Watching

Bro It is similar to the calculation of P0-Forces. I have explained calculation of P0-Forces joint by joint. Similarly take each joint separately and resolve them to get P1 forces in individual members. Nothing new in it.

Thank you

Thank you so much 🙂

Welcome 😊

Yes. Because it is also a column and it is also subjected to sway

Thanks for Watching

So glad to help you. Thanks for Watching

Thank you very much

SA2

SA-2

SA-2

While calculating redundant forces, we should consider combined action of P and P1 forces.

Its a calculation mistake. But the procedure is same. Thanks for Watching

At point E, the vertical shear is 120KN. So we dont consider 80KN.

Thanks a lot

At the supports or joints we will get -ve moments. At mid spans we will get +ve moments. Thanks for Watching.

Very happy to see Power Stars reply in my channel

Need some promotion for my channel in your next movie launch event

There is no 90KN load in the frame. I think you are asking about 80KN load. That load is acting exactly on the joint. So we dont have any moment due to 80KN load. Thanks for Watching.

Hello.

Thanks For Watching

In scientific calculator you can solve the equations by entering the values of coefficients

Thanks for Watching

Thanks for Watching

Thank You very much and I will definitely try

Thanks for Watching

No, because for Cantilever one end must be fixed. We are not having any fixed support in the given truss. Thanks for Watching

Glad it was helpful!

1. Divide the frame into 3 members 2. Calculate the Reactions at each end based on given loads and calculated moments using equilibrium equations. 3. Then using the reactions calculate the shear forces at various points on that member 4. Then draw the Shear Force Diagram as usual like you draw for Simply Supported beam

Thanks a lot 😊

Welcome

Thank You very much

So nice of you

Yes, You are right. Its 15KN. Thank You for identifying the mistake. But procedure is more important in examination

Glad to hear that