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Can i use single transistor?

Thanks a lot

Are you on Instagram? Kindly if I have any questions related to any topic Can I ask there?

Good Stuff. One question. How do we control the gate of the MOSFET. Do we use some MCU for this job. Also if the load changes then there needs to be some feedback system to change the duty cycle of the MOSFET. How do we apply Laplace Transform to this circuit. Asking this because a interviewer asked me this question. Can you Please make a video on these Topics. Thanks

Thanks

Great video. Does it make a difference on how the transformer is wound?

Hi, from a practical point of view, the video is very good, the ideas are correct. But you missed the correct way to add those impedances. You can't add the capacitive impedance and the resistive impedance. Impedance is a complex value, so the correct value is Z = sqrt(Z_c^2 + R^2).

This is insane how useful I found your channel right now. I started to work on the PS project and this came out in the search bar. Oh boy, this was so detailed, I could not find any reference how to design something like this on the youtube before, this is extremely helpful. Thank you!

Snubber circuit wasn't mentioned 15:48 but your explanation is very good I hope you do a project with low voltage input like 40 vdc to explain the work with oscilloscope wave form capture.

Where do we get the term "flyback" from? Something to do with tubes, you think?

that seems like a great playlist Thank you

You should build a ZVS flyback circuit and describe the process as you go and show the variables in design. The ZVS circuit is so cool.

Clap your diodes if you have a variac!

Really good, that was very helpful

Very Helpful. Thx. Will watch several times to internalize. Cheers.

This was really insightful; helped me out for my knowledge and understanding.

For eagle eyed viewers, who else noticed that there is a bookmark / folder called "Nicolas Cage Nudes" during the theory of operations section from 13: 00 mins in lol

You are a natural born teacher! You are incredibly smart, eloquent and have a comfortable way of explaining difficult concepts. You are a lucky young man, you are going to have a bright future.

Thank you bro.. I hope you will do video about forward converters also. I checked almost all your videos and i think you like flyback topology more than others. 😅 is that true?

Thank you for making this video!

Great Video!

No, that's not the only reason! The main issue isn't ESR but rather ESL. When a component (like a CPU) switches rapidly, the parasitic inductance in the capacitor can limit the inrush current that the capacitor would otherwise supply. This means that if the component demands a large amount of current very quickly, the inductance can prevent the current flow, effectively making the capacitor invisible to the load - it’s as if the capacitor isn’t there at all! To address this, we use multiple capacitors in parallel, which reduces the total ESL because parallel inductances combine to lower the overall inductance. Additionally, smaller-value capacitors like 1uF, 0.56uF, and 0.1uF are often used together instead of a single large capacitor because lower-valued capacitors generally have less inductance. So their combination ensures better performance across a wide range of frequencies!

My favorite phrase, I use it regularly: "Not Exactly"....

Nice explanation ,😊

I vaguely remember something about the capacitor obsorbing ripple peaks as it charges, then filling ripple troughs as it discharges! 🤔

Very clear explanation. I might have missed you mentioning it, but it's worth noting that, in general, esr is inversely related to capacitance. So even though using two smaller capacitors in parallel reduces total esr because they are in parallel, the esr of each of the smaller capacitors, other things being equal, will be larger than the esr of a single cap with the same total capacitance.

Thank You^^

Galvanic isolation?

It is very important to realize that in power supplies with capacitive filtering the input current is not some phase-shifted sinusoid but high-amplitude sort of "rounded spikes" occurring ONLY when the instantaneous input voltage exceeds the voltage held on the filter capacitor. During most of the AC cycle there is zero input current. A simple concept such as phase angle doesn't really come into play in the "bad" power factor but the objective is still to have current that is sinusoidal in phase with the voltage. Reverse recovery time in the output diode of the PFC converter is extremely important and likely to be the parameter that most limits the field of choices. Active PFC circuits require what appears to be paradoxical behavior. The average input current must be inversely proportional to the average input voltage but the instantaneous input current must be directly proportional to the input voltage.

The reflected output voltage comes from only one effect - true transformer "action" that is dependent on the ratio of the input and output winding turns. The reflected voltage magnitude is constant as long as current is flowing in the output winding. There is another phenomenon that is the result of imperfect magnetic coupling between the inductor charging winding (input) and the discharge winding (output). This is called "leakage inductance" and can be modeled, in simple terms, as a small inductor in series with the input winding but not magnetically coupled to anything else. It is this inductance that results in a very high voltage "spike" when the switch turns off. The current through it _does_ "try" to remain constant (equal to the current just before the switch turns off), but since there is nowhere for the stored energy to go that current causes a very high voltage. Again, it has nothing to do with reflected voltage. A "snubber" is used to limit the magnitude of the spike voltage in most practical designs. When the switch turns off you get three distinct voltages at the drain of the MOSFET switch. First you get a high-magnitude narrow spike due to the leakage inductance. Then the reflected secondary voltage appears (it actually started as soon as the FET turned off, but it is sort of "hidden" by the big spike. The reflected voltage will remain nearly constant until all of the energy stored in the inductor ("transformer") has been discharged. The voltage across the output winding is held nearly constant by the voltage on the output capacitor, which changes only a very small amount in any one switching cycle. The reflected voltage is added to or "stacked on top" of the input supply voltage. This stacked voltage is the main consideration when it comes to the voltage rating of the FET. Once the stored energy has been discharged, the FET drain voltage drops back to the voltage on the input filter capacitor. Typically there is some high frequency "ringing" due to resonance between FET and "stray" capacitances and the inductances. If the inductor is not fully discharged before the FET turns ON again, the voltage at the drain remains equal to the "stacked" voltages. Management of the reflected voltage is often a significant consideration in the turns ratio of the inductor ("transformer"). The main consideration in turns ratio is the determination of the inductances required, not input to output voltage ratio. You certainly do not take the approach used for a true transformer. I prefer to think of the magnetic component as an inductor with a charging winding and a discharging winding, not as a "transformer" (though it behaves as such when you really don't want it to) or as a "coupled inductor" because there is no "coupling" between input and output windings in terms of actual power delivery. "Transformer" is a convenient but misleading short word.

This was great! thank you for taking the time.

Thanks a lot!

Nice topic

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Adult content don't make adults better. Meditating the word of GOD does. JESUS CHRIST loves us.

Your content is promising. I clicked doubtedly, but remained voluntarily. Keep up sir bro. You gonna make it far🫡

I'm trying to learn electronics. Quick question...at time 2:02, what is the purpose of C11 and wouldn't C11 act as a short to an AC input?? Perhaps C11 is chosen to have a high capacitive reactance at 60 HZ and act as virtual open? I quickly figured Xc and came up with approximately 2850 ohms (which could be wrong). Which doesn't seem very high. Either way, what is its purpose?? Thanks in advance!

pls share the ti topologies.pdf

My brother was about to tear out plaster - which is very heavy - so there being like four rooms I convinced him to make a mobile unit we could knock the plaster into and move it to a window and slide it out to a dumpster saving us lots of lifting and WORK since that ceiling plaster was POTENTIALIZED some 100 years ago

Gravity is a "Physics " word - that's for sure Flat Water and flat oceans and flat lakes on a Curved ball floating in a vacuum with Helicopters that can only fly about 3 miles up because there is not enough DENSITY to provide lift - and if DENSITY goes down with altitude where does that stop ? eventually a dome of nothingness

Thanks for a great video... One question what simulation software do you use?

What are the number of Primary Windings to Secondary Windings needed to start with an Input Voltage of 6 Volts to obtain an Output Voltage of 60.000 Volts?

Explained very well. Great video

Thank you so much for an eloquently explained lecture on this topic, you made it so easy to understand and digest 😃

I think that when the voltage is stepped up besides turns ratio being the effect of it, that the primary coil itself can have a high BEMF due to the ramp up time being larger than the ramp down time and that as well can effect the secondary BEMF.

great breakdown.

As we're talking about beginners theory class, I'd have also mentioned the damper diode, which would protect the driver from counter-EMF from when it swtiches off. More advanced, there were gate turn-off models in use, where gate voltage turned off the drive, otherwise the driver defaulted in conduction and a no-drive condition would result in overcurrent on the driver. Fortunately, such drivers were quite rare in actual production, as far as I recall, only present in one model Philco television and Sony televisions for a number of years, but not in any other form of flyback circuit in industrial usage.

Thank you for the explanation; you made the Flyback circuit so much easier to understand.

Thanks. Good info; especially the part about this type of converter being more or less failsafe if the MOSFET or similar were to fail short.

Thanks for the video, great information, but at 5:09 your bridge rectifier schematic is wrong. You have the ground and DC voltage output mixed up with the AC input. At 10:10 you show the "surge diode," along with the incorrectly drawn bridge. The surge diode would cause current to bypass the inductor every time the FET is ON.