วีดีโอ

Iit kanpur

we want a series of all topics of IQOM

Yup i will clear ❤

Thank you sir

👍👍👍👍👍👍👍👍

It's not correct

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Definitely yes 💯

Fill IOQM then clear Then clear RMO then appear INMO

How to apply for these exams

Sir cutoff

Definitely Not 😅

*75°* is the answer of last question

Please make more vidios

30

love from russia😊 it is amazing ❤

Sir 1st question mai a,b ko change karke bhi toh question satisfy hai so, answer becomes 2 times 6 = 12. ????

At 45:29 the solutions 3rd case give the pair (1003,3) which is same as the pair found from first case while sir saide that there is no solutions from 3rd case while we have got the pair this is different that it was same😅 meanwhile the solution remains the same😅😂😂😂😂

34:52 you did wrong sir

Sir can u tell me how did u get the reciprocal of 1st qn starting

Today is bbefore nmtc exam i am watching this like 6 hours bfore exam, give my commrnt a like so i go to lvl 2 by luck somehow :)

So for the first question, is the answer 1 or 45?

Sir, please upload more videos on this series. We look forward to watching your awesome videos.

Harris Jason Allen George Wilson Kimberly

43:50, after dividing 2 on both sides, cubing both sides = (x/2 + 1/2)^3 = [x3(x3 + 3x2 - 3x)]/8 = 2x-1 => x3(x3 + 3x2 + 3x) = 16x -8 => x3(x3 + 3x2 - 3x) -16x + 9. since 9 has 6 factors '1'; '-1'; '3'; '-3'; '9'; '-9'. when f(1) = 1(1 + 3 + 3) -16 + 9, it is = 0. x will have 9 values, on of them is x=1, and (x-1) is a factor, so you can use long division to calculate other roots but it is not necessary.

D

30

42:00 This is always true for A = B = C, and the only different case will be (1, -1/2, -2).

Loved the last problem sir!

I'm watching from Nigeria. Though i'm preparing for 2025 olympiad but to be candid this video is very helpful. Thanks..

27:00 In this problem, we don't even need to check the cases with 3 and 5, because the difference between the factors (a+7b) and (a-7b), is 14b, and so Difference between the factors we are making should also be greater than or equal to 14 The 100 0's, 100 1's and 100 2's was an excellent question! HW Question: 11 divides EEFF (Since alternating difference of sum of digits, is 0), but 11 doesn't divide AB or CD (since A-B, and C-D both are non-zero due to A,B,C,D being distinct, and they are surely not multiples of 11 since they are digits)

the answer is: 4i + 3j + 3k

Sir pls give answers 🙏 😔

Can a dropper write this exam

Sir why are you not making sessions anymore in this channel😢. It has been more than 2 weeks ,please start making new sessions.

Sir combinatorics please, u haven't taught combi completely on main channel as well. And it is the part that troubles us the most so sir please start combi and complete it fully

Very easy

Very easy

Very easy

This problem is very easy. Purely board level question.

Lectures are best but they are lacking something

Sir where is Notes and Assignment in the description??😅😅

21:09 How can you take r², r⁴ ... common?!😅😮

such an easy problem.if u are training us for ioqm please upload harder problems.I dont expect ioqm gives these questions.

Please upload harder problems. These are very easy

You are which teacher. I am unable to recognise the sound. Are you Praveen sir?