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Dr. Stephen G. Prilliman
United States
เข้าร่วมเมื่อ 4 พ.ย. 2011
20 years of experience teaching #GenChem and #APChem.
Simple analogy for induced dipoles in molecules (origin of London dispersion forces)
Simple analogy for induced dipoles in molecules (origin of London dispersion forces)
มุมมอง: 10
วีดีโอ
Making a scatter graph and line of best fit with Google Sheets
มุมมอง 29K2 ปีที่แล้ว
How to make graphs of data and find the line of best fit using Google Sheets (part of the Google Docs suite). How to display the equation for the line of best fit. To see how to do this with MS Excel: th-cam.com/video/xPllgp12uY4/w-d-xo.html
Acetic acid with addition of sodium acetate
มุมมอง 2.5K2 ปีที่แล้ว
Acetic acid with addition of sodium acetate
The equilibrium expression and the equilibrium constant, K
มุมมอง 742 ปีที่แล้ว
Introduction to the meaning and use of the equilibrium expression and interpreting the value of K. #GeneralChemistry #GenChem
Atomic level kinetics and Enthalpy diagram (including activation energy)
มุมมอง 622 ปีที่แล้ว
Atomic level kinetics and Enthalpy diagram (including activation energy)
Solving equilibrium problems with the Small x approximation
มุมมอง 1.5K2 ปีที่แล้ว
Solving equilibrium problems with the Small x approximation
Introduction to kinetics and instantaneous rate
มุมมอง 772 ปีที่แล้ว
Using tangent lines to find the instaneous rate of a reaction
Calculating change in Enthalpy (DeltaH) using tabulated valued (DeltaHac and DeltaHf)
มุมมอง 772 ปีที่แล้ว
Calculating change in Enthalpy (DeltaH) using tabulated valued (DeltaHac and DeltaHf)
Enthalpy and how to calculate it from experimental data
มุมมอง 1182 ปีที่แล้ว
Enthalpy and how to calculate it from experimental data
Bond energy, estimating change of energy during a reaction
มุมมอง 1332 ปีที่แล้ว
Bond energy, estimating change of energy during a reaction
Valence shell electron pair repulsion (VSEPR)
มุมมอง 1202 ปีที่แล้ว
Valence shell electron pair repulsion (VSEPR)
Ionization energy practice (Episode 3 of Ionization Energy trilogy)
มุมมอง 462 ปีที่แล้ว
Ionization energy practice (Episode 3 of Ionization Energy trilogy)
Pairing energy. First Ionization energy Part 2
มุมมอง 372 ปีที่แล้ว
Pairing energy. First Ionization energy Part 2
Reactions and molarity: using solutions concentration during reactions
มุมมอง 492 ปีที่แล้ว
Reactions and molarity: using solutions concentration during reactions
THANK YOU
thanks buddy.
tysm
thanks for this clear tutorial. one detail: the intercept value is negative. b= -.0476
am kenyan and i liked it thank u
Not science. Using tables. No direct measurement of H+ concentration.
❤❤
thisw was AMAZINGGGG THANKSSS
THANK YOU VERY MUCH YOU'RE THE ONLY ONE THAT EXPLAINS IT FAST AND CLEARLY❤
just saved my grade
What the fuck is this there's no explanation nothing goddammit pls if there was a problem reupload the video
Thanks
How does the last one have dipole dipole if the center does not have any lone pairs?
Lone pairs on the central atom are often but not always present in a molecule with a permanent dipole moment. H2CO has a dipole because H and O have different electronegativies. Since O has a greater electronegativitiy than H, it draws shared electrons toward it more strongly from the C than do the H atoms. This means there is greater electron density on the O side of the molecule, creating a dipole moment. Hope that helps!
Nice and clear - thanks!
Just awesome dude!!!!
Thanks!!
okay but what if its office 365 excel? i am having the hardest time even finding similar options and tabs needed and the value inputs seem to not let me add values exither. and these wierd red blue and purple boxes appear around some of my selected values.
My understanding is that the Office 365 version of Excel does not support this function. I usually recommend my students who only have Office 365 access use Google sheets for this instead. See this video for Sheets instructions: th-cam.com/video/rJXz1qVYFu4/w-d-xo.html
@@dr.stepheng.prilliman8726 thanks! i installed the desktop app and it works great!
I think that's my problem.. I use cold tap water(boston) then Ph to 6.4... feed the plants that..
House plants are outside my expertise but I will say that the water you add to the plants will warm to room temperature so you won't have a temperature effect. But the acid to base balance of the water remains the same (acidic, in your case) regardless of the temperature.
thanks so much!
Thank you, this was helpful!
Can you give the reaction plz?
When we write a reaction equation for this we treat this as the dissociation of acetic acid: HCH3COOH (aq) <=> H+ (aq) + CH3COO-(aq) From a Le Chatelier perspective you would say that the addition of sodium acetate increases the acetate (CH3COO-) concentration, and to relieve that addition of a product the reaction goes in reverse. Going in reverse also uses up H+ ions, therefore the pH increases.
thankyou
Thank you
I’m hoping this helps, I have a chemistry final tomorrow. one of the subjects I couldn’t comprehend was intermolecular forces.
It's a tough subject, hoping the video was helpful!
Amazing video! It's clarity and conciseness allowed me to understand every part of it.
Awesome, thanks!
thank you.. you may have little viewer but i am one very grateful viewer :D
Thank you!
Thank you so much, I was struggling on my AP Chem test, but now I understand!
Glad to help! There are lots more chemistry videos on my channel.
Thanks buddy..❤❤
Error warning! The half life in the first problem should have been 126 years, not 12.6 y. Sorry, y'all, it's really hard to see the decimal on my calculator.
IF the water is not acidic at that temperature then what is the purpose of doing this calculation? What does a pH of 6.3 represent here then if it is not acidity? Please explain!
Only at 25 Celsius is 7 the dividing line between acidic and basic. As temperature increases and water autoionized more, the dividing line between acidic and basic decreases. So if you get a result of 6.3 from this calculation, it means that pH below 6.3 is acidic and pH above 6.3 is basic at that temperature.
@@dr.stepheng.prilliman8726 Now I understand. Thank you!
PPPPPPPPPRRRRRRRRRIIIIIIIIIIIIILLLLLLLLLLMMMMMMAAAAAAAAAAANNNNNN!!!!!!!!!!!!!!!!!!!!!
Very helpful
Thank you
thanks, hello grade 7 members. 7 asia?
same
Thank you so much! <3
In the practice problem I flipped the final temperature for Cu and H2O. I will put up a replacement video at Some point. Eventually.
Hi Dr. Prilliman, for the last practice problem, I got 108mL CuCl2 instead of what you got, 97L CuCl2 and I solved it the same way you did. I am not sure where I went wrong, can you explain how you got it? Thanks!
Thank you, very helpful
Very helpful thank you
Is it expected to just know how to go from m to cm and mg to g for the last two problems? I'm having a hard time getting started on all conversions and stoichometry problems but once the ball is rolling I'm fine.
Yes, you need to know the following prefixes: kilo-, centi-, milli-, micro- and nano-. Anything else I will provide on quizzes/exams.
"What Excel calls a trend line and everyone else in the world calls a best-fit line..." The shade thrown here, intentional or not, is legendary. Thank for the video!
Thank you! You're video is the only one that actually shows how you can find the y= equation from your graph, thank you!
that plus sign doesn't come up for me?
Thank you so much for this!
Helps ALOT!!
Thanks! this helped
thanks for this, I was wondering what was up with the fact that the pH and pOH both appear to be disagreeing when solving for these at different temperatures and now it makes complete sense. basically, the scale itself is changing and the neutral point is no longer 7 at non standard temperatures.
thank you, this is very helpful
Thank u for this ❤ keep it up
Thank you, this helped me with my homework assignment!