วีดีโอ

bros jacked asl teaching this

Nice explanation keep up the good work bruh...

You a smart cookie

ur channel inspired to make my own channel and i just wanna say thanks i guess

I’m cooked

Lmao good video

thank you, i thought this video was a click-bait but it actually meaning to me as a fresher

nice perspective

Let x(t)=<rcost,rsint,r> where r, the radius of the helix path that the particle travels, varies with time. v(t) = x'(t) = <r'cost-rsint, r'sint+rcost, r'> Since speed is the magnitude of velocity, we have |v(t)| = sqrt((r'cost-rsint)^2+(r'sint+rcost)^2+(r')^2)). After expanding the brackets and simplifying, |v(t)| = sqrt(2(r')^2+r^2). Plugging in r = e^t and integrating with respect to time yields a total distance of sqrt3*(e^4-1).

good video!

That shit s easy. I dont like the kind of way that Logarithmic Differentiation is applied in most cases tho. I just do sin(x)^cos(x)=e^(cos(x)*ln(sin(x)) wich is easy with Chainrule and not as "formula feeling" if you know what i mean

do sin(x^cos(x)) next

ı think there is not a difficulty in this question. its very easy for uinversty level.

Since the graph must intersect with the horizontal line at a single point, we know that y = c is a tangent line to y = f(x) = -x^2+9x-100. Furthermore, the slope of the tangent line is 0. Thus, f'(x)= -2x + 9 set 0 -> x = 9/2. Finally, c = f(9/2)= -319/4.

Another funny way of arriving at the same answer is to say ∫a^xdx is equal to the definite integral from 0 to x ∫a^tdt plus some constant and then use Riemann sums and geometric sum for the latter

do a trig sub next :3

Good job that problem would’ve taken me a trip through desmos.

so lost i wont even bother to understand

Should I make a video about another example of a Taylor Series? Let me know below 👇

2x speed goes crazy

👍🏻

keep it up

these are the types of proofs you see in movies

Sorry, I was late to class I was stuck in a bunch of traffic above your short

Where did you get that chalkboard? I NEED IT

Based

I like to solve this integral by letting I = integral of exp(x)*exp(ix)*dx Integrating this function is trivial, and after a few algebraic manipulations you get that the Re(I) is the integral of exp(x)cosx and the Im(I) is the integral of exp(x)sinx IBP is faster but I like how we solve two integrals in one go!

Alright thanks

cool video but write larger or put the board in a better position it's kinda hard to read

The u-substitution seems a bit unnecessary in this case. I think you can solve the integral using the fact that dy/dx e^log(2)x = log(2)e^log(2)x and reversing that operation on e^log(2)x to get the answer. Great video and explination nonetheless!

ooh thats pretty cool

Nice video bro! keep it up

Try to speak clearly next time as possible rest of it good

Thank u for making me understand about the concept if ur wondering I am still in Lowe class but it actually made everything clear for me some how I understood everything *we always Learn anew thing every miniute*

great video, I sense no nervousness in your presentation. However, I feel like you're going too fast with the explanation. you have a good understanding of what you present, but you have to put yourself in the learner's shoes. you should frequently stop for a little bit to let the viewer digest what you have just said. you should use arrows/gestures to show what you are doing instead of just saying it. all in all, wonderful video and you should keep up the good work.

Nice video, spoken very clearly

HOLY CRAP DUDE U SAVED MY LIFE KEEP IT UP

You can also use sinx=2tan(x/2)/(1+tan²(x/2)) and substitute tan(x/2) as t..... Btw really enjoyed the video your black board gives a proper class vibes mann ✨ Keeep it up also take some Physics things like rotation n all if possible 😭

Thanks mann🤌

By the transitive property: a = c. Furthermore, c = a by the symmetric property of equality. Step-by-step explanation is easy to follow.

Thanks Joachim Descartes Peiper

perfect. Great video!

This video was like a lifeline thrown into stormy seas-I was drowning in equations, gasping for clarity, and suddenly, there it was, pulling me back to the surface. It was like someone flipped a light switch in a dark room, illuminating every problem I struggled with. The answers came flooding in like a long-awaited rain in a desert, quenching my thirst for understanding. Watching it felt like finding the missing puzzle piece that completed the whole picture, and now everything made sense. It didn’t just save me from my math exam; it felt like a superhero swooping in at the last second, just before the deadline crashed down on me.

I like your funny words magic man.