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Dremph
เข้าร่วมเมื่อ 4 เม.ย. 2018
This is the channel of Dr. Eric M. Hernandez (www.emhernandez.com). In this channel you will find instructional videos (related to my job as a professor) and classical guitar performances (one of my hobbies).
Stiffness Matrix - The Basics
Prof. Hernandez discusses the basic ideas behind the formation of the stiffness matrix. The concepts are illustrated using ideal springs.
มุมมอง: 119
วีดีโอ
An inverse problem in Statics and it's connection to Heron's formula
มุมมอง 1389 หลายเดือนก่อน
This video presents the problem of finding the angles among three forces of known magnitude in order to achieve equilibrium. This problem is solved using Heron's formula.
Por qué colapsaron los muros del tunel?...un experimento simple nos da la respuesta.
มุมมอง 35311 หลายเดือนก่อน
El Prof. Dr. Eric Hernandez nos presenta un simple experimento que demuesta los efectos de la presion hidraulica y como reducirlos.
Derivative of the moment equation is NOT the shear.
มุมมอง 285ปีที่แล้ว
Derivative of the moment equation is NOT the shear.
A simple yet surprising problem in Structural Analysis
มุมมอง 78ปีที่แล้ว
A simply supported beam subject to uniformly distributed bending moments.
STRUCTURAL SYSTEMS explained in five levels of difficulty by Eric M. Hernandez
มุมมอง 1773 ปีที่แล้ว
In this short video Prof. Hernandez explains the concept of "structural systems" in five levels of difficulty.
EQUILIBRIUM - Explained in five levels of difficulty by Eric M. Hernandez
มุมมอง 1153 ปีที่แล้ว
In this short video, Prof. Hernandez explains the concept of equilibrium in five increasing levels of difficulty. If you are interested in cool equilibrium projects, check out his video using JENGA blocks th-cam.com/video/kLO3SgNOPqQ/w-d-xo.html.
Simpson's Paradox in Structural Analysis
มุมมอง 3473 ปีที่แล้ว
In this video, Prof. Hernandez constructs a simple example of Simpson's paradox in Structural Analysis.
Vals Criollo (Rafael Landestoy) interpreted by Eric M. Hernandez
มุมมอง 1013 ปีที่แล้ว
Vals Criollo (Rafael Landestoy) interpreted by Eric M. Hernandez
Cancion del Emperador - Luys de Narvaez (1538) interpreted by Eric Hernandez
มุมมอง 433 ปีที่แล้ว
Cancion del Emperador - Luys de Narvaez (1538) interpreted by Eric Hernandez
"Guardame..." (Luys de Narvaez,1530) interpreted by Eric Hernandez
มุมมอง 1264 ปีที่แล้ว
"Guardame..." (Luys de Narvaez,1530) interpreted by Eric Hernandez
Which beam has the largest deformation...simply supported or elastic catenary?
มุมมอง 2434 ปีที่แล้ว
This lectures compares the deformation of a simply supported beam and a catenary.
How long can a cantilever be?
มุมมอง 3504 ปีที่แล้ว
Solution by Prof. Eric Hernandez (www.emhernandez.com)
Solved Problem in Structural Analysis - Vertical Deformation in Inclined Cantilever
มุมมอง 2964 ปีที่แล้ว
Solved Problem in Structural Analysis - Vertical Deformation in Inclined Cantilever
Recursive Solutions to State-Space Models
มุมมอง 1144 ปีที่แล้ว
Recursive Solutions to State-Space Models
State-Space Models in Structural Dynamics
มุมมอง 3604 ปีที่แล้ว
State-Space Models in Structural Dynamics
Design of RC Column using a Normalized Interaction Diagram
มุมมอง 2.3K4 ปีที่แล้ว
Design of RC Column using a Normalized Interaction Diagram
Response of MDOF Systems to External Time-Varying Loading using Modal Analysis (see description)
มุมมอง 4474 ปีที่แล้ว
Response of MDOF Systems to External Time-Varying Loading using Modal Analysis (see description)
Response of MDOF Systems - Initial Conditions
มุมมอง 4144 ปีที่แล้ว
Response of MDOF Systems - Initial Conditions
Interaction of Axial and Flexure in RC Members - Part 2
มุมมอง 3984 ปีที่แล้ว
Interaction of Axial and Flexure in RC Members - Part 2
Axial and Flexure Interaction in RC members - Part 1
มุมมอง 2734 ปีที่แล้ว
Axial and Flexure Interaction in RC members - Part 1
Modal Analysis of MDOF Systems - Part 2
มุมมอง 1.1K4 ปีที่แล้ว
Modal Analysis of MDOF Systems - Part 2
Modal analysis of MDOF Systems - Part 1
มุมมอง 2.7K4 ปีที่แล้ว
Modal analysis of MDOF Systems - Part 1
Development length of rebar in RC members - EXAMPLE
มุมมอง 6364 ปีที่แล้ว
Development length of rebar in RC members - EXAMPLE
Development Length of Rebar in RC members
มุมมอง 1884 ปีที่แล้ว
Development Length of Rebar in RC members
Critical Sections for Shear and Torsion in RC members
มุมมอง 9K4 ปีที่แล้ว
Critical Sections for Shear and Torsion in RC members
EXAMPLE - Design of RC beam for combined flexure, shear and torsion - Part 2
มุมมอง 1.4K4 ปีที่แล้ว
EXAMPLE - Design of RC beam for combined flexure, shear and torsion - Part 2
EXAMPLE - Design of RC beam for combined flexure, shear and torsion - Part 1
มุมมอง 2K4 ปีที่แล้ว
EXAMPLE - Design of RC beam for combined flexure, shear and torsion - Part 1
This is an excellent summary of the key pillars of Beam Theory, even for seasoned professionals, in a very concise delivery format, thank you Dr. Hernandez and hope that you continue distilling out similar content in the future!
@@yasirshah8468 Thank you!
About "c" that you are referring to in f(c), is it the location of the neutral axis in the strain diagram?
Hey, are these two deflection eqn found definitely right?
The correct answer for the tip deflection is simply the deflection at b + angle(at b)*a,. This is true because the end portion of the deflected shape is simple a straight line. This comes out to = Pb^3/3EI + Pab^2/2EI. If you plug in x=a+b on the equation for the deflection of the end portion, you get this answer. Did you try that?
Theres a mistake in your integration at 3.42
Yes, you are correct, but I actually realize (in real time) that I have a mistake and fix it in 8:40...Good eye!
@@dremph5611 Ah! i see, great pickup!
En vaalkaiyai kaapathiviteergal aiyyaa
Thank you Dremph... Possibly the best explanation out there...no BS...just logic. Thanks
I am studying system identification and I found the 2 videos regarding state-space models of yours super helpful!!
Thank you! Glad to hear they were useful.
THANK YOU
Interesting indeed!
Good presentation
If there were 3 legs, would all 3 be considered for torsional At/s?
If there were 3 legs, would all 3 be considered for torsional At/s?
Depends on the location. Since this reinforcement is designed to resist torsion, the reinforcement near the perimeter is more effective than the reinforcement near the center. Personally, I would only account for it if it is on the perimeter.
Sir your videos are great....Sir i have a doubt that what is the purpose of using logarithm in calculation....?
Thanks a lot sir . The video is very informative . A small doubt sir. Like if we need to find the value of A i.e., cross sectional area ..., We can use the derived formula , but we also need to know the value of Integration constant. How to find it sir.
Great explanation.
❤
Weight
🤯
you are the best
Av including all legs or only the outers legs???
Av is the shear reinforcement (regardless of its location). It must adhere to the definition/requirements of shear reinforcement.
Thank you
can you share the code?
thank you very much
Not sure for shear. Critical Section is inclined, as shear stresses, in italian classical text, not vertical. Max Shear stress is at the centre of rectangular section, so your critical section should be at d/2 not at d. More you must consider that max shear stress at the centre is 1.5 times mean value. Where i wrong?
This must be from some other code I'm guessing. ACI code says to take critical section at distance d
Thanks
This is what I was searching for..... amazing
Thank you sir,
Thank You Sir for Sharing!
How about if do moment in terms of y
Thank you so much. That was grate.
Thanks
you just saved my life.
great sir👍
Sir can you please make some videos on polar moment of inertia.
Can you name the text book?
Anil K. Chopra , Dynamics of Structures
Why is Torsion- Vu x e ??
I just saw this, apologies for the (very) late reply. It is because "e" is the eccentricity that exists between the externally applied force and the internal shear force resisting that force.
Thank you for this!
Thank you!...
Aoh should be equal to 174.25 in2 not 200.5 in2.
Hi! Thanks for the lecture :) I do have a question though, why is it @2:35 the Tt = 3.94 then @6:21 it became 4.55?
Awesome
1.Can you please tell that what if i takes a critical section for shear at the point of max. Shear force. Is the design wrong or it is only uneconomical but ok. 2.what should be the critical section if the beam is over hang from one side with 2 supports and a udl over the whole span.
Instead of providing only the corner bars can I provide reinforcing bars in the inner side as well? will that be able to resist the applied torsion?
did you find the answer?
Profesor que libro está usando?
No es un solo, he tomado informacion de varios. Te puedo mandar una lista por email.
Muy buen interpretación Eric.
Am I understanding it correctly that for the equation for determining transverse reinforcing you use the center line of that transverse reinforcement to determine area and for longitudinal reinforcement equation you use the outer edge of the transverse reinforcement to determine area?
To determine the longitudinal torsion reinforcement the formula includes ph, which is the perimeter of the center line of transverse reinforcement.