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Shem Thompson
เข้าร่วมเมื่อ 26 เม.ย. 2012
วีดีโอ
How to solve Rotational Kinematics problems
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02 10a FLIP Intro to Spliting up forces final
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Solving force problems with two unknowns in each equation
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Solving Force Problems with a known diagonal force
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Solving Force problems with an unknown diagonal force
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Solving Force problems with an unknown diagonal force
Yes
4:05 potential divider
Best Explanation
tanga amp wag kana magturo HAHAHAHA
Dead cat
Sir it is diameter but you taken radius
Sorry sir but your answer is wrong that should be a -2.89 angular acceleration
Very helpful
Thanks for the great lecture. Perfect explanation indeed
How I can know it's a static fiction???
Neet
19:13 omega squared can be plus minus…in this case shldnt it be negative
thank you for this helpful video
thanks alot it was very useful
You beauty
Amazingly well explained
something is wong in process but still got the right answer
Carry on 🎉
is above same as time series trend line?
what is error bar?
The problem says that 12cm is the radius of the circle not the length of the string... soo I'm not sure...
SO GOOD EXPLAINING THANKS
Great lecture
Did you actually run the lab with several students , and did they do several trials ? Also, if you have a Longer Ramp, with Photo Gates from Vernier, did you set that up as well ?? Please let me know, as I have some Introductory Physics Classes who I want to run this type of lab ( Not IB or AP ) but still interested in Acceleration on a RAMP...... Thank you for your descriptions...
Jesus is king
An idea just hit me while watching your video. If you are trying to find a theoretical equation that does not have a model yet, you can change the initial coefficients in the original equation when trying to find it's antiderivative.
please can you explain this?
If the ramp is 100 cm for example, could we find the acceleration by measuring the speed in every 10 cm segment and comparing each segment's speed? We would see an increase in speed and would not this I indicate the acceleration? If needed would measure speed for every 5 cm etc. Is this method doable?
How come initial v becomes final v?
nice presentation
Thanks man this helped me out keep up the good work
I have been trying to understand these concepts for 5 plus hours. Your videos made it simple. I do have a follow up questions. We can assume that there is no vertical tension because the ball stays on the table or surface the entire time?
Hope Im not too late but yah. Because the Ball doesnt go up or down the tensión up and tensión down cancel each other out which makes the ball travel around in one position in the horizontal direction.
all the variables were incorrectly substituted in for the w part of the 2nd question.
In the first question, it was said that the length of the string was 85 cm and you've solved it as 85 m ??? + it was the diameter ( the whole string ), but not the radius...
The length of the string should make the radius I'm pretty sure.
The length of the spring equals to the radius of the circular motion
There was a "." in front of 85, so that makes it 0.85m, not 85m And secondly, when you spin something on a string, your hand is the centre of rotation, while however long the string is becomes the radius of motion. Hence, the radius is 0.85m, the length of the string.
You are a bad teacher in the world. How you explain one example in 12 min.
new education channel for math and science th-cam.com/video/TCv3GX4tTLI/w-d-xo.html Thanks
I love plug, chug, solve
definitiontions
Thanks so much!! I've been really confused about potential dividers for the better part of a year now and this video helped me understand a lot more about it :>>
Thanks. From Bangladesh.
A merry go round horse is encircling the ride at a speed of 6 m/s. If the diameter of the ride is 18.64 m, how much force is the horse exerting, provided that its mass is 152 kg? Can someone help me with this
A merry go round horse is encircling the ride at a speed of 6 m/s. If the diameter of the ride is 18.64 m, how much force is the horse exerting, provided that its mass is 152 kg? Can someone help me with this
since it moves in a horizontal circular path just solve for centripital force mv²/r
V=6m/s M=152kg d=18.64 r=18.64/2 = 9.32 Hence centrifugal force =Mv² / r =(152×6×6) ÷ (9.32)=587.12N Answer = 587.12N 😁😉
How to calculate tension? Plz explain
nice
I love you SO much thankyou thankyou thankyou
How would it be possible to achieve a tension force of 2883 Newtons ? like how do you decide to have a tension force of 2000 Newtons or a tension force of 2883 ?
well explained
I never expected u to say "unlinear"
I can't believe he would make us watch his youtube channel, clearly just trying to farm views for clout. smh my head
Thank you, Mr. THOMPSON
Thank you sir!