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how do you know that the angle formed between the origin and A is pi/4?

This is really helpful thanks :D Can I ask why at 4:06 you put 7/10 outside?

Nice video

nice video easy to understand

Excellent

hi, great video as I considered subscribing and liking. I do have a question, if there was no string pulling X (meaning no tension force) would the minimum force be just 6N?

1 + cis(2θ) = cis(θ)[cis(θ) + cis(-θ)] since cisα.cisβ = cis(α + β) and 1 = cis0. = 2cos(θ)cis(θ) since cis(θ) + cis(-θ) = 2cos(θ) |z| = 2cos(θ) since -π/2 < θ < π/2 Arg(z) = θ

very helpful!

Hi! Can you post videos of solving problems on the topic of conic sections and polar curves? This is not IB but it is taught in university... and your teaching style helps me the most!

this is so hard but you make it look easy. thank you sir.

Proof by induction is a great chapter.

Excellent explanation.

Very good explanation. Quite clearly illustrative for students.

thank you so much for this, bro is single handedly saving my midterms

my brain hurts

That's what I was looking for, thanks❤

Can you please include a picture of the question in the description when you post the videos

Reply please

I think you need to improve some things in your videos , i think we need to communicate once

Hi

Thank you very much. Your videos are extremely helpful.

Hi, in 1:00 why did you skip the 2sin(2theta) in the denominator and instead immediately wrote sin(2theta)??

I just want to say thank you for videos. For these past weeks of preparation they really helped me review on the material and help me pass on my exam (paper 2 still destroyed me though) Your content is very useful and well organized. Thank you for creating this channel!

thanks a lot sir it really helped

I did this paper a few days ago. Can I ask if you think was it easier relative to the other years or more difficult? Personally I thought it was manageable

27:07 Shouldn't it be negative 79/42?

so hard

This is incredibly helpful, thank you!

Your videos are very helpful. Thank you!

Thank you very much :)

Saved my life

the answer of the first question is not available in the options of the paper

please don't stop posting I have been really enjoying ur videos they are very helpful, even little descriptions on how to solve hard questions is making studying for exams way easier!

Thank you! Your videos are amazing revision before the exam

Can you solve Q7, 13 and 30 from Physics HL - 2023 May TZ1 Paper 1 ?

Love your maths videos

Can you solve Q11e) and Q12 from this paper please? AAHL May 2023 TZ1 P1

Thank you so much for the video, unfortunately my physics teacher has no idea of some of this topics and is unable to explain the answers to us so this is incredibly helpful 👍👍

Thank you!

by definition :)

Hello, can you solve question 7 on physics HL P1 TZ2 2022 ?

tysm!

Thank you for this video, there are no other solutions for this problem online

Excellent

hi sir, if it is said to find the area of the rectangular shape you draw in the argand diagram, what should we do?

An easier way to do part h ii would've been to let n = 2, in which case you would have the expression: f3(x) + f1(x) = 2xf2(x). I suggest this since f1(x) is rather straightforward, f2(x) has also been previously calculated, and thus f3(x) is very simply found (and you get to skip solving for f4(x) :D). Great video!

Thanks! I need this, please keep going to make another videos!!

thank you sir!

You're so helpful

THANK U