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Pete Penner
เข้าร่วมเมื่อ 6 ก.ย. 2013
I am a Civil Engineering Student at Texas Tech University. I do Statics, Dynamics, Solids, and Structural Analysis for fun. I enjoy finding easier ways to solve problems and I want to share them with everybody. I've seen videos where all they do is work examples and I try to provide insight as to why we do a certain procedure. I plan on putting some videos into playlists for the FE exam review by class so it will be easier to find certain videos. The videos I plan on doing are Surveying, Statics, Dynamics, Solids, Fluids, Structural Analysis, Principles of Design, Materials, Geotech, Environmental, and Economic Analysis.
Dynamics - Energy Method
Use energy method to determine kinetic and potential energy of the collar around the pipe.
มุมมอง: 80
วีดีโอ
Rigid Tank Thermodynamics
มุมมอง 5K6 ปีที่แล้ว
Determine the final temperature and pressure due to a energy increase within a rigid tank. I do not own this problem. Problem was taken from Thermodynamics: An Engineering Approach 8th ed. Y. Cengel
Deflected Shape Due to Concentrated Moment
มุมมอง 1966 ปีที่แล้ว
Determine the slope and deflection due to a concentrated moment using double integration method.
T-v Diagram With Piston Stops
มุมมอง 3.7K6 ปีที่แล้ว
Construct a T-v diagram and plot the states on the process line. We use values from the steam tables to determine the pressures, temperatures, and quality at each state. I do not own the rights to this problem. I am only showing how to solve this problem. Problem is taken from Thermodynamics: An Engineering Approach 8th ed. by Y. Cengel
Bi axial Bending Beam Design
มุมมอง 6866 ปีที่แล้ว
Design a beam based on ultimate moment and deflection limits.
Connection Design Part 2
มุมมอง 1236 ปีที่แล้ว
Finishing up from part 1, we determine the block shear and the yielding and rupture capacity of the lug plate based on the whitmore width. Determine weld capacity with and without load angles.
Connection Design Part 1
มุมมอง 626 ปีที่แล้ว
Determine limit states in connection design. This video deals with the yielding and rupture capacities of the double angles and lug plate. Also determine the bolt shearing capacity, and bolt bearing.
Solids - Normal and Shear Stress of a System in Double Shear Example 2
มุมมอง 4.7K7 ปีที่แล้ว
Determine the thickness of the member BC using normal stress. We also found the diameter of the pins at B and A. Pin B was in double shear, while pin A was in single shear I made a mistake in the video, I did not take the X component of the force at A into consideration when I did my calculation. We need to take the overall force that is acting on the pin at A. I caught the mistake but hopefull...
Solids - Normal and Shear Stress of a System in Double Shear Example 1
มุมมอง 3K7 ปีที่แล้ว
Calculated the normal stress in the rods having different diameters. Also found the shear stress in the pin connecting the two rods together.
Dynamics - Relative Motion Using Rotating Axes Example 2
มุมมอง 6857 ปีที่แล้ว
We need to find out what the absolute velocity and absolute acceleration are of the car C. We need to be careful in determining that the velocity of the car C with respect to point A is 0. Picture was taken from Dynamics 14th ed. by Hibbeler Problem 16-144
Dynamics - Relative Motion Using Rotating Axes Example 1
มุมมอง 7807 ปีที่แล้ว
We need to find the absolute acceleration and absolute velocity of the man walking on a bridge that is closing. We need to determine what is our relative acceleration and relative velocity and determine where to put our global coordinate system. Picture was taken from Dynamics 14th edition by Hibbeler, Problem 16-132.
Statics - Equilibrium of Rigid Bodies Example 1
มุมมอง 8427 ปีที่แล้ว
Use our moment equations to find the tensions in the cable. After that, we are able to find the x and y components of the pin. I think I stated the x and y component of the reaction at D but I never gave the magnitude which is 129.8 pounds. This video is part of a review for the FE exam for civil engineers Picture taken from Statics 10th ed. by Beer problem 4.29
Statics - Resultant Forces and Direction Cosines
มุมมอง 1.2K7 ปีที่แล้ว
The first problem is finding the resultant force of a block on an inclined plane. We use two different methods to solve. The second problem is breaking a force into it's x, y, and z components and finding the direction cosines. This topic is part of the FE exam review for civil engineers. Picture taken from Statics 10th Ed. by Beer problem 2.75 and 2.37
Fluids - Multifluid Manometer Example #2
มุมมอง 112K7 ปีที่แล้ว
Another multifluid manometer example. This time the end is not open to the atmosphere. Instead it is connected to a pipe that transports gasoline. All our fluids are given to us in specific gravity, which we can easily convert to density or specific weight. Picture taken from Thermodynamics 8th Ed. by Cengel Problem 1-112
Fluids - Multifluid Manometer Example
มุมมอง 16K7 ปีที่แล้ว
Find gage pressure inside the tank using a multifluid manometer. This example comes from a thermodynamics text Picture taken from Thermodynamics 8th Ed. by Cengel Problem 1-50
Structural Analysis - Moment Area of Beam With Internal Pin
มุมมอง 2.8K7 ปีที่แล้ว
Structural Analysis - Moment Area of Beam With Internal Pin
Dynamics - Minimum Distance Between Two Cars - Kinematics of Particles
มุมมอง 7K7 ปีที่แล้ว
Dynamics - Minimum Distance Between Two Cars - Kinematics of Particles
Dynamics - Forces and Acceleration on a Particle
มุมมอง 4767 ปีที่แล้ว
Dynamics - Forces and Acceleration on a Particle
Concentrated Moment - Shear and Moment Diagrams
มุมมอง 6557 ปีที่แล้ว
Concentrated Moment - Shear and Moment Diagrams
So the pressure of the air is still 370000Pa? Can i say the gas pressure is 370000Pa?
Thank you. great explanation.
Well explained thank you 🤝🏾
This video helped me relearn manometers for my FE Civil Review. Thanks!
Thank you so much the video is very helpful! God bless you!
Poor videos quality...the "teacher" speak like hes meditating,zero enthusiasm!!Im outta here
SIR , YOU CHANGED MY LIFE
How can at the time of collision both the velocities be equal?
What if we are given air ρ=1.2kg/m^3 then we take height into account?
Then you just used that given density. That doesn’t change the process shown in the video.
Thank you sir 🙏🏾
Thank you!
i love you man. no homo
Thank you so much! ㅠㅠ
Thank you so so so so so so so so so much :)
Thank u sir
Whyy is the sound sooo low :)
thanks for that
Simply thank you very much 🙏🙏
So helpful thank you!
How would you find the absolute pressure for this problem??
Thank you, Sir.
I finally figured out what I was doing wrong. I was using kPa in my calculations but now I know we must convert to Pa. Thank you!
That was very helpful tyyy♥️
I think it should be minus
Hi del
Thank you, I finally get it. Great way of showing what the short cuts are derived from!
Video a bit vague with all that scribbling, but once i did focus it was very helpful, Thank You!
Is dryness fraction doesn't change U1?
Hero. Saved me going mad trying to figure this out :-)
An inverted differential manometer is connected to two pipe A And B carrying water under pressure as shown in fig.2.26. the fluid in the manometer is oil of specific gravity 0.75 .Determine the pressure dufference between A and B
Thank you so much
thx pete
Thankyou very helpful 😊
Who’s has fluid test? 🤦🏻♀️
Was too late to see this.. Now I just got 60%
Did u have this question for your test lol?
In the future could you just zoom out instead of scrolling around
why don't you make your own video instead of hustling???
@@alexwalton2132 why are you mad over someone else's suggestion?
@@alexwalton2132 he has a right point.. main purpose of making video is to make people understand.. He was just giving suggestion..
Well explained congratulations.....!
please why did you multiply mercury and gasoline with 9.81 and didnt for others?
Nabeel lee I multiplied all liquids by 9.81 so I could find pressure. Pressure is the density of the fluid(rho)*gravity(g)*difference in height(h). The only term not multiplied by 9.81 is air since it is already given to us in pressure.
wow thank you for mentioning why we treat air and liquids differently, I was confused even though its obvious...such details are always helpful
Thank you! Very useful.
Vaguely done in writing form.. But the solution is really helpful... Thank you so much
thank sir
Nice sir
Thnx for the video exceellent
poor video quality sir!
thanks <3
Good job 👏🏻 doc
Thanks a lot, Very helpful. and i reccomend you to not write with big writing like one formula cover the entire screen. because sometimes we need to see the picture while we calculaton the formula.
Tnx for good explaining.Do you have advice how to approach to any problem in kinematics or dynamics.
When looking at this problem, you can tell that there are no outside forces acting on the car. Sure there is gravity but it does not change the direction of motion. So our equations (F=ma) does not work in this scenario. We need to specify the particles (cars) position, velocity and acceleration at a point in time and our kinematic equations allow us to find just that.