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Yes

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Okay sure

10 ml of solution from silica filtration (makeup volume 250ml). Please refer to the IS 4032: 1985 standard for cement chemical testing. Please check this link also th-cam.com/video/yuLrxto2ySs/w-d-xo.htmlsi=sUJ4oAOImMdzhwGE

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This process applies to cement and clinker; typical processes vary depending on the substance.

Yes

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(accurately weighed up to four decimal places) of oven dried sample’ for ‘Take 0.5000 g of the sample’

R2O3 is composed of Al2O3 + Fe2O3. Al2O3 is amphoteric (ie it will dissolve in an excess of either acid or base.) NH4OH is strongly basic. So, if you added too much NH4OH, it would dissolve some of the Al2O3 out of the R2O3 precipitate giving you a low result for Al2O3.

Min

What do you mean, I don't understand your question?

Prevents interference from many foreign ions as a Fe2O3 and hydrolysis of bismuth before or during titration with EDTA.

yes definitely

yes definitely

बुझा हुआ चूना या जला हुआ चूना

Yes definitely

Dual flamephotometer

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Fe2O3 test complete hone ke just bad Alumina Oxide test start karege So pahle 15 EDT add karege then aage ka test perform karege

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We have already created a video on F2O3, the link to which is provided below. th-cam.com/video/yuLrxto2ySs/w-d-xo.htmlsi=EYXwU4SYumFzzkEz

Thank you so much dear

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The density of a cement sample is 3.06, and the density of the standard cement used for the K factor is different. As a result, the weights of the two samples will be different.

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@@chemicalkiDuniya. Please which sample u analysis

Ordinary Portland cement -53

@@chemicalkiDuniya. But OPC iron 4.44% content too high

You can find Using this formula Equivalent weight= atomic mass/valency factor or molecular mass/valency factor

The value of S is given in the certificate of standard-certified reference material (CRM). The K factor is determined by substituting the value of S.

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Because I prepared 250-mL solution and took 25-mL sample for testing. So sample dilution factor is 250/25 = 10. So 25 is not mentioned in Al2O3 calculation. For cement chemistry test details, please refer IS 4032.

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MgO%=(V1-V2)×0.04032×0.01×250×100/Weight of sample×Volume of sample taken for titration MgO%=(V1-V2)×0.04032×0.01×250×100/0.5000×10 MgO%=(V1-V2)×0.04032×25/0.5000 Where-V1= MgO burette reading V2= CaO Test Burette reading 0.01= molarity of EDTA Solution I made a 250-ml solution and took a 10-ml sample for testing. So sample dilution factor is 250/10=25 geted. For cement chemistry testing details, please refer to IS 4032.

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Prepare 0.01 M EDTA in 1000 mL distilled water as per the calculation given below. Disodium EDTA dihydrate ; Molecular Weight. 372.24g/mol. So, Weight=(𝑵 ∗ 𝑬𝒒. 𝑾𝒕. ∗ 𝑽(𝒎𝒍))/𝟏𝟎𝟎𝟎 Weight=(0.01*372.24∗1000(𝒎𝒍))/𝟏𝟎𝟎𝟎 Weight=3.7224g

Yes definitely

@@chemicalkiDuniya. plz tell

Sir solution factor kaise nikalte hai

Yes possible, TH-cam launched an automatic translation feature to translate subtitles for any video on their platform. Follow these easy 5 steps to translate your favourite video: 1. Play the video you would like to translate. 2. In the bottom right corner, turn on the closed captions by clicking or tapping on the CC button. 3. You will see the automatically generated closed captions in English. Then go into settings and click or tap on Auto-translate. 4. Now you just need to pick the language that you would like for the subtitles and the tool automatically translates these captions into your chosen language. 5. In this example, we selected Arabic and we can see that the subtitles are automatically translated into this language.

Please refer to the IS 4032 : 1985 standard for cement chemical testing.

Okay

Please make alumian test

We have published the video of Al2O3 as per your request. Please follow the link. th-cam.com/video/ixfeSUQ6zlk/w-d-xo.htmlsi=FDqRMsH_9HXhTX6u

We have published the video of Al2O3 as per your request. Please follow the link. th-cam.com/video/ixfeSUQ6zlk/w-d-xo.htmlsi=FDqRMsH_9HXhTX6u

Please refer to the IS 4032 : 1985 standard for cement chemical testing. And Please visit this video link th-cam.com/video/yuLrxto2ySs/w-d-xo.htmlsi=MP3VKx4ojJoSmmoP I have explained there how much sample was taken.

Take 1 gram of the sample and add approximately 10 g of K2S2O7 (Potassium pyrosulfate) in a platinum crucible. Fuse the mixture over a Bunsen burner flame or muffle furnace. ( at around 1000deg C) Start heating slowly with constant stirring. When the melt becomes clear quench the crucible in cold water. Cool the crucible and its contents and dissolve the melt by heating with 150 to 200 ml of water in a 500-ml beaker. To the warm solution cautiously add approximately 12 g of sodium hydroxide pellets, a few at a time. This will dissolve the silicic acid formed during the fusion (the free silica is not transformed to silicic acid by the fusion). Digest on the hot plate for 1/2 hr at 80°C to 90°C. Filter quickly, using a close textured filter paper (Whatman 541 or 40). thoroughly scrub and wash the beaker with hot water. Wash the filter paper and its contents ten or more times with hot water to remove the sodium silicate. Dissolve the calcium sulphate and oxides of the metals that remain on the paper in 1.1 HCI. Transfer the residue completely in Whatman paper no. 40, wash t it with hot 1:1 HCI and with water till it is free from acid and ignite the paper and its contents in a platinum crucible at 1000°C for 2 hrs and weigh as free silica. Carry out HF treatment to ascertain the determination of free silica and report to the nearest 0.001 grams.

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​@@chemicalkiDuniya.What Can be replaced the bisulfate potassium?

Potassium bisulfate is used as a disintegrating agent in analytical chemistry or as a precursor to prepare potassium persulfate, a powerful oxidizing agent.

Oups! I don't have this product, but I have Na2SO4(sodium sulfate)

The nitro benzene or 3,5,5-Trimethyl-1-hexanol is added to coagulate the silver chloride precipitate so that it will not interfere with the titration of excess of silver nitrate by forming a layer over silver chloride and this avoids the need for titration.

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Calculation is already explained in this video.

Thanks you

Thank you

W = 0.500ρV W=0.500×3.06×1.86 W=2.84g ⍴= Density of test sample V= Bulk volume of bed of cement, cmᶾ, as determined above, e=Desired porosity of bed of cement (0.500±0.005) We request that you watch the video again without skipping. The calculation of the weight of cement has already been described there.

isse to bed of cement ka wt. aayega na test ke liye sample ka wt. kese niklega

1st time wt. of cement kese liya 4:40 pr or calculation 0.500×3.06×1.86 me 3.06 kha se aaya or is calculation se wt. of cement 2.84 aa rha h jbki video me 2.92g kha se aaya

Dost different sample ke liye different density hoga, 3.06 cement sample ka density hai Aur K factor ke liye jo standard cement use huwa hai uski density different hai isliye Dona ka weight diffrent hai,

2.8 anumanit wt kaise le rhe

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