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Erin Slade
เข้าร่วมเมื่อ 24 ส.ค. 2014
วีดีโอ
Simplifying Rational Expressions Part 3 (Adding & Subtracting)
มุมมอง 503 ปีที่แล้ว
Recorded with screencast-o-matic.com
Simplifying Rational Expressions Part 2 (Multiplying/Dividing)
มุมมอง 333 ปีที่แล้ว
Recorded with screencast-o-matic.com
Solving Systems of Equations Review
มุมมอง 2.7K3 ปีที่แล้ว
Solving Systems by Substitution & Elimination
Algebra in Entrepreneurship Virtual Open House
มุมมอง 184 ปีที่แล้ว
Algebra in Entrepreneurship Virtual Open House
Solving Systems of Equations by Substitution
มุมมอง 794 ปีที่แล้ว
Solving Systems of Equations by Substitution
I like how you use the wrapping paper idea to help me understand surface area more, tysm ❤
thank you so much this was very helpful
Can someone please help.... I have a problem that makes no sense at all. "A zoning ordinance requires that any property with impervious coverage that discharges more than 100,000 gallons of water in a 4-inch rain storm must have a retention pond. The subject property will have 260,000 s.f. of impervious surface. A cubic foot of water contains 7.48 gallons and a retention ponds can hold no more than 500,000 gallons for safety reasons. What is the amount of water being displaced." Can some solve and explain, major thanks, (I'm using a HP12c calculator).
My teacher in class argued that you didn't have to subtract the area of the base of that cone, but I knew I was right in saying that you did have to subtract it 😌. Thank you so much for this helpful video!
How did you know?
@@millicentwilson9567 hi! I just knew you had to subtract the base, since it was no longer on the outer surface of the object. Surfaces are no longer surfaces to be counted in surface area once they are inside the structure.
@@swoosh6801 Then why do you subtract it twice? When finding the formula you have to subtract it from the surface area of the cuboid AND the cone
@@millicentwilson9567 good question, it’s because there are now two surfaces inside the structure: a circular patch from the rectangular prism and another circular patch from the bottom of the cone, so you have to subtract both interior surfaces ( which are now irrelevant) from the total surface area.
@@swoosh6801 But you don't do that when you're finding the surface area of a barn or a house, or a loaf of bread either. You only subtract it by one shape rather than both. Why? Is it because one of the shapes are in half?
wow thank you you made me get 100% on my test! This is super appreciated thank you so much
thanks for making this video <3
Thx vid helped
Thank you so much. This video really helped.
helpful
Ms. Mancini you are one of most favorite teacher. I wish I had mathematics teachers like you when I was primary and high school student.
Idk, the one that holds the most volume....
BIG BRAIN
Very nice explanation
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Thanks
nice
"Most excellence leading video...!"
Can you please help me with my desmos project??
nice vid thank u very much
great job
Thank you!!!!
ty
Thank you so much! I’m a freshman and got into geo honors, this video really helped!
i came from mrs bajwa
huy does huy I came from mr Lau
Best anology ever!
edgy
I like donkeys
Do you have to subtract the surface area of the triangle from the cone too or am I mistaken?? I'm sorry... it's a little complicated for me... hope you'll make me understand..
LOL POTATOES 🥔
Ha you bum bum don’t know dat
🥔🥔🥔
no you just subtract the circle at the bottom of the cone because the surface area does not cover that
thank you
Hi
Always ask yourself... In there anything X cannot be when trying to find the range.
Function - One Outcome Relation - More than one outcome
Just like finding the hypotenuse
How often will this be used in Algebra 2 Honors? -Anna W.
Will we be using the Pythagorean Theorem in other ways in Algebra 2 than in geometry? -Catherine R.
How often will we use these formulas in class through out the year? -Kuper Imrem
How will we be using the distance and midpoint formula in Algebra2H?
In this video, the formula for distance between two points on a graph is taken apart. It is based on the Pythagorean theorem. Then, the formula for the midpoint is created and is found by finding the average of the coordinate pairs.
Its a review of the distance between two points, and also of all the formulas to find the distance between 2 points. Also theres a review on how to find midpoint
Rad vid bro
Rad vid bro👍
What's the answer to the last problem?