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Online Math Club
เข้าร่วมเมื่อ 9 พ.ค. 2021
The Online Math Club is an initiative to reach high school students interested in math and give them a platform to learn more and interact with others. The Club aims to increase exposure to olympiad mathematics and advanced mathematics. The format of the classes shows a great deal of diversity depending on the topic. Usually, they should be about 60-90 minutes in length and will be held over Zoom. You can join at sites.google.com/view/online-math-club/home.
Once you submit your application, you may join our discord server mentioned on the same, where you will find more details. We will take up to 48 hours to review your submission. The process to get verified on the server is automated, which you have to initiate yourself. Unlike before, please note that you will not receive any emails from us about your application.
Once you submit your application, you may join our discord server mentioned on the same, where you will find more details. We will take up to 48 hours to review your submission. The process to get verified on the server is automated, which you have to initiate yourself. Unlike before, please note that you will not receive any emails from us about your application.
Inequalities II by Atharva Sutar
OMC 2.0 is a reboot of the original club wherein we will be conducting weekly math olympiad sessions starting from basic topics in a sequential manner. We will also be providing you with Problem sets frequently. The new server will be invite-only (through a dedicated application procedure). You can find more information about the program on the website: sites.google.com/view/online-math-club
To apply to the program, please fill out the form - forms.gle/ZXwq5zC7j6tTKQs96
You can send all queries by mail to onlinemathclub2.0@gmail.com.
The Online Math Club is an initiative to reach high school students interested in math and give them a platform to learn more and interact with others. The Club aims to increase exposure to olympiad mathematics and advanced mathematics. And OMC is free for all!
#math #olympiad #IMO #mathclub #OMC
To apply to the program, please fill out the form - forms.gle/ZXwq5zC7j6tTKQs96
You can send all queries by mail to onlinemathclub2.0@gmail.com.
The Online Math Club is an initiative to reach high school students interested in math and give them a platform to learn more and interact with others. The Club aims to increase exposure to olympiad mathematics and advanced mathematics. And OMC is free for all!
#math #olympiad #IMO #mathclub #OMC
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An Introduction to Graph Theory by Nandagovind Anurag
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Angle Chasing Problem Solving Session by Kanav Talwar
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Extremal Principle by Atharv Harlalka
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Invariants and Monovariants by Rushil Mathur
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Invariants and Monovariants by Rushil Mathur
Sunaina hiii best counselor ever👋🏻👋🏻
Geometrix saar ors ors ors
Rushil is my fav teacher at omc
Debayu sir orz
I'm sorry for asking this here but can anyone from club members tell what should I fill in the awarding body of IGCSE and a-level exam in UCAS application
Are you from DPS, 19? I think you took my workshop for IOQM, RMO and INMO...
Freida Point
hehe MONT is also good for that
Tbh Rushil is one one the best teachers at OMC... The way he teaches...... Keep it up
awesome lecture :)
What is meant by length here?
An important concept taught by an IMO gold medallist....Lovely explanation Great job!!
is my reasoning correct in the first question that in second case the polynomial would have been a zero polynomial too if its roots have not cycled back so by a equation k^2^m=k^2^n we get absolute value of k is 1 or 0 hence by algebraicly proceeding towards the solution
elliot orz
I have only one doubt in the first question how absolute value of every root of p(x) is 1
god himself
Hello Kanav, for the first question, is there a solution using coefficient matching? Assume the coefficients are real, then (a_n)^2 = a_n, from the leading coeffecient, and so a_n = 1. Similarly a_0 = 0 or 1. Also, notice P(x^2) is composed completely of even powers, so we can set all odd-power coefficients to 0. Thus, the sum of roots of P(x^2) or a_2n-1 = 0. But notice, a_2n-1 = 2(a_n-1 + n). So the sum of roots of P(x) and P(x+2) is both n. Is this a feasible method?
why (an)^2=an you cant get this until some other statements are given
for example let n = 3x+4y and n=5m+9n so can you say without sufficient conditions that 3x=5m or 4y=9n Hope it helps
Let P(x) = a_nx^n + a_n-1x^n_1 . . . . . . . + a0. P(x+2) = a_n(x+2)^n + a_n-1(x+2)^n-1. . . . .a0. Notice, from the Binomial expansion, the coefficient of x^n is still a_n. Similarly for the RHS, the leading coefficient is also a_n. Thus a_n^2 = a_n.
As a better explanation P(x) and P(x+2) have the same leading coefficient, and P(x^2) = P(x)*P(x+2). We may equate the leading coefficients of both sides. Notice the leading coefficient of P(x^2) to be a_n. Why? As a_n(x^2)^n is the first term. Then equation the leading terms: a_n(x^2n) = a_n(x^2)*a_n(x^2). Thus a_n^2 = a_n and a_n = 1.
you cannot basicly compare any equations if you want i can prove
Loved this session Kanav bhayya , Ur a great teacher :D
Kanav Bhai Orz!!!
Hello
orz
First
I submitted my application a few days ago but no one has reached out to me, does that mean I got rejected?
Not necessarily. You can mail them about it. Even I didn't receive any mail so I asked them about it then I got accepted.
Can you please make a play list for graph theory
He is brilliant mind .
Why is x=2x'
?
I cannot believe this is a high school student teaching. Forget the technical depth, this guy’s patience and temperament humbles me. He was born to teach. Good luck in Oxford Mr Mathur.
many many congratulations to the entire Indian team
kutte ?
Umm can I attend these live classes?
Yes! Join the OMC 2.0 discord server by submitting your application at forms.gle/ZXwq5zC7j6tTKQs96. More information can be found on our website: sites.google.com/view/online-math-club.
❤
Thankssss for uploading the session 👍
The last game discussed was called Wythoff's Game. There is an expression to generate the numbers P(k) = k phi Q(k) = k phi^2 That's probably why you felt a Fibonacci connection. The closed form involves the golden ratio !
Kathlyn Wall
😂😂😂😂 good try continue
Thanks for this
Renee Creek
I’ll curse myself the entire life for not giving IOQM this year.
to much to learn before solving a diophantine😢
Hi can u give some suggestion regarding how to tackle a problem of rmo as i am first timer
Sir i am getting confirmed 40 marks in ioqm i am in class 10 in delhi can i clear it if yes what should i do for rmo
meme solve
like the way u guys approach to problems, really uplifting
Or you can just chase lengths and you ll get that distance of O1 O2 depends only on BC.