วีดีโอ

if there is a scenario that in student list there are just two students with same score then when we apply set and sorted methods there is just 1 element remaining in the list so when we use this approach to find second lowest number second_lowest = sorted_grades[1] then compiler gives error of out o range index because there is no any element with 1 indes there is just 1 element whose index is 0 so in this scenario we can add a check to find the length of list: if len(sorted_grades) >= 2: second_lowest = sorted_grades[1] else: second_lowest = sorted_grades[0]

Corrected code --if __name__ == '__main__': N = int(input()) my_list = [] for i in range(N): user_input = input().split() if user_input[0] == 'insert': my_list.insert(int(user_input[1]), int(user_input[2])) elif user_input[0] == 'print': print(my_list) elif user_input[0] == 'remove': my_list.remove(int(user_input[1])) elif user_input[0] == 'append': my_list.append(int(user_input[1])) elif user_input[0] == 'sort': my_list.sort() elif user_input[0] == 'pop': # If no index is provided for pop, just pop the last element if len(user_input) > 1: my_list.pop(int(user_input[1])) else: my_list.pop() elif user_input[0] == 'reverse': my_list.reverse()

Alhamdulliah, i did this without watching any video, but i used reversed(range(1,N,2)

nice explanation sir

and also when i did list(map(int, input().split())) it didn't even give me a number

When I did list(map(int, input())) as a habit, the value was 90 degrees, why?

What if i do like this If(n%2==0 and range (2,5)): Solution came right but test case 3 and 7 cames wrong while submit can you explain??

you don't need a for loop to access a dictionary when you already have the key!! hahaha. just print sum(marks[query]) / len(marks[query])

what if all number in arr are the same? I think it returns None, and that must be ok.

omg!! it was so easy. I was dealing with substrings and sets, and I got the solution, but it was slow for long strings (the problem says S could be up to 10^6 long). you open my mind! thanks!

you explained it really well!! the second loop is confusing for a beginner like me

great explanation sir !

you are awesome!!

Thank you so much for the videos they are really helpful, your efforts are much appreciated.

I understand that we first gotta select only the red channel/layer out of the image and then we can display it in grayscale using cmap, but I am still unable to understand why cmap = 'gray' wasnt able to show the image in grayscale?

arr = map(int, input().split()) new_sort=sorted(set((arr))) bro what about this?

great explanation!

The order of the column names changes in the input. For example, test case 0 has: ID MARKS NAME CLASS But test case 1 has: MARKS CLASS NAME ID How does the code handle that?

MARKS, CLASS, NAME, ID = input().split() I did not know you could do this. It seems it's automatically assigning a variable to each item in the list that split() returns. Very cool.

Your videos are extremely helpful. Thank you so much.

I loved that thanks a lot!!!

Two comments: 1) I think there is a small error in the code. Instead of "elif num in set_b" on line 11, it should be "if num in set_b". Otherwise, the happiness will not decrease if the number is in both sets. 2) I had to remove the function call in order not to get excessive timeout on running. I noticed in the video, you forgot to show the "submit code" at the end. You may have gotten an error also. No problems, you have great content.

I want to thank you for all of your great videos. I am teaching a basic Python class in my local community and your videos are very useful. Great Job.

bro i think you are from india

Tq for your information ❤

From @Sumayya45 in a reply comment: "The number of substrings starting at index i is equal to length - i." This is key to understanding the logic.

you are doing a great job keep it up

hello bro

damn, you taught me better than my college teacher

❤

this is different question and different solution

To understand why width = size * 4 - 3? let's say size = 3. If we see the max width in the middle, the total no. of the alphabet is 5(c, b, a, b, c), and so one dash is required in between these alphabets. so, the total no. of dashes is 4 in this case. so, if size = 3, the max width in the middle row is: 5 alphabets+4 dashes = (3+2) + (4) = (3 +2 ) + (5-1) = (3 + 2) + (3 + 2 -1) = (n + n-1) + (n + n - 1 - 1) {As n or size = 3} = (2n - 1) + (2n - 2) = 2n + 2n - 1 - 2 = 4n - 3 Therefore width = 4 * size - 3

i have a issue in parameter you set parameter in swap function s but used new_s which is not in parameter sir plz explain that

I am glad that I found your channel. Thanks a lot.

you are a great teacher

u the meshiah!

great sir big fan of you sir

Why did you use "str" after the return?

Amazing 👏

best explanation sir i watched almost 3 to 4 videos untill you. I clearly understood the concept from you. thanks

can u explain print(" ".join(map(str, final_dict[b])))

Why is this soo hard!!!!😢😢

thankyou so much fr ur explanation it helps me a lot to code and makes me feel confident

Thank you so much you saved me ! Amazing explanation

Thank you, Amir

How can we use loop while taking our output???

such a pretty explanation❤

Such beautifully explained!🍦

Awesome Explanation Amir sir, can you start a playlist for selected leetcode questions also??

how j loop working here ?