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Avikedu
เข้าร่วมเมื่อ 17 ต.ค. 2024
Welcome to Avikedu ..!
🟢 Here I will try my Best to Give You the Solution of ALL the Maths Problems in the Simplest and Easiest Way so that you can easily understand the solution of all the Problems.
✅ If you have any other easy method to solve those questions, then please give your solution in the comment.
Thank you
🤓 This channel obsesses over methods to make math easier!
Mathematics indeed a journey that only requires your passion and commitment.
My Videos will provide some guide as we take on this journey together.
Thanks For Reading 😎
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Thanks You 😊
🟢 Here I will try my Best to Give You the Solution of ALL the Maths Problems in the Simplest and Easiest Way so that you can easily understand the solution of all the Problems.
✅ If you have any other easy method to solve those questions, then please give your solution in the comment.
Thank you
🤓 This channel obsesses over methods to make math easier!
Mathematics indeed a journey that only requires your passion and commitment.
My Videos will provide some guide as we take on this journey together.
Thanks For Reading 😎
SUBSCRIBE Avikedu For the New Videos Notification
Thanks You 😊
🔥 Solving Exponential Equation 4^x = 20 | Solving Exponential Equation using logarithm @Avikedu
Solving Exponential Equation 4^x = 20 | Solving Exponential Equation using logarithm
🔥Solving Exponential Equation 5^x + 5^x = 90 th-cam.com/video/z78JCooEAw4/w-d-xo.html
🔥Solving Exponential Equation 4^x-2=15 th-cam.com/video/avOZmoR41EU/w-d-xo.html
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🔥Solving Exponential Equation 5^x + 5^x = 90 th-cam.com/video/z78JCooEAw4/w-d-xo.html
🔥Solving Exponential Equation 4^x-2=15 th-cam.com/video/avOZmoR41EU/w-d-xo.html
solving exponential equations using logarithmic properties
solving exponential equations using logarithms
solving exponential equations
solving exponential equations using logs
how to solve math olympiad exponential equation
solve exponential equation
learn how to solve exponential equation quickly
exponential equations
exponential equation
olympiad
math olympiad
olympiad mathematics
math olympiad training
mathematical olympiad
solving exponential equations
solve the exponential equation
math olympiad exponential equation
a nice olympiad exponential problem
a nice math olympiad exponential equation
math olympiad questions
solving exponential equations with logarithms
exponential equations
exponential
value of x
find the value of x
determining the value of x
solving logarithmic equations
find the value of x
how to find the value of x
what is the value of x
finding the value of x
how to find value of x
find the x value
find value of x
logarithms
exponential equation
solving exponential equations with different bases
#exponentialequation #maths #mathematics #solve #findthevalueofx #math #mathproblems #olympiad #logarithm #mathematical #matheducation #olympiadmathematics #mathvideos
🙏 Thank You For Watching 🙏
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มุมมอง: 4
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C. 676 - 576 √100 = 10
😮3x=6=>x=2ans
0,01•0,04= 0,0004%
√15^2-✓9^2 /2= ✓(15-9)(15+9) /2= ✓6•24 / 2= ✓3•24= ✓6•6•2= 6✓2.
(0.09)^1/2=(9/100)^1/2=3/10=0.3ans
Why not ? √-1 x √ -1 = √ -1 x -1 = √ 1 and = 1
Wrong...in the 2nd step
@@Avikedu √2 x √ 3 = √ 2x 3 right then √-1 x √-1 = √-1 x -1 it's also the same ... I'm right ?
@@logeshacc no , in case of postive number you can write √1 × √1 = √1×1 but in case of negative number you can't write √-1 × √-1 = √-1×-1 because √-1 = i (iota - imaginary number)
=>(26+24)×2}^0.5=100^1/2=10 ans.
(2^2)^2 × (2^3)^4 2^4 × 2^12 = 2^(4 + 12) = 2^16 2^(16/4) = 2^4 = 16
x^(1/2) / x = 3 => 1 / x^(1/2) = 3 => x^(1/2) = 1/3 => x = 1/9
let a=5^x.=>a^2-30a+125=0=>a^2-2.a.15+125+100=100=>(a-15)^2=10^2=>a-15=10=>a=25=>5^x=5^2=>x=2ans
a - 15 = + 10 or - 10 ✅
Letra C
A
but who told yu that x without root is positive , because i think should the two sides of the equation should be positive to power up them
(2^3)^x + (2^3)^x = 128 2(2^3x) =128 , 2^(3x + 1) = 2^7 3x + 1 = 7 , 3x = 7 - 1 = 6 x = 6/3 = 2
B. (2^2)^x = (2^2)^4 + (2^2)^4 2^2x = 2^8 + 2^8 = 2(2^8) = 2^9 2x = 9 , x = 9/2 = 4.5
√(4 × 5) + √(9 × 5) = 2 × √5 + 3 × √5 = 5 × √5 , answer is A
8^x+8^x= 128; 2^3x+2^3x = 2^6; 2×3xlg2= 5lg2×2. 3x= 5, x=5/3.
Проверка: 2^3•5/3+2^3•5/3= 128; 2^5+2^5=128; 64+64= 128, 128=128.
Проверка: 2^3•5/3+2^3•5/3= 128; 2^5+2^5=128; 64+64= 128, 128=128.
0.02
devided by 0 is undefined ; how x can b a zero?
Watch Full Video Boss...I don't include x = 0 in Answer... Answer will be only 1/9
x=1/9
d
Letra B
Koliko je ovo komplikovano, nikada ovo ne bih mogao da resim
(50^50)/((5^2)^25) (50^50)/(5^(2•25)) (50^50)/(5^50) (50/5)^50 10^50
Better
Letra B
x=9/2ans
La respuesta es x =4.5
Maybe for younger people but log is much simpler since only one calculation need
4/(4^2•8^4 ; 4/(2^2)^2•(2^3)^4) ; 4/(2^4+^12 ; 4/(2^16) ; (2^16)•1/4 =2^4=16
2^2х= 2•2^8, 2^2х= 2^9; 2хlg2= 9 lg2 | lg2 , х = 9/2.
3/10=0.3
✓х/х= 3; х не рав😊но 0; 😊😊✓х/х= 3; 😊(✓х/х)^2= 3^2; х/х^2= 9; 1/х= 9, 1= 9х, х= 1/9 .
✓0,09😊= ✓9/100 = 3😊/10.
You took the log too early... 2 . 5^x = 90 -> 5^x = 45 = 9 . 5^1 -> 5^x . 5^-1 = 9 -> 5^(x - 1) = 9 and now it is time for the logs (x - 1) . log 5 = log 9 -> x = (log 9 / log 5) + 1 ~ 2.37 not 2.36 😃
😊
?=-48
Letra B
Super
Answer 80 percent d is the correct option .
MARE BRÂNZĂ!
A. 1/4
0.5 is half , 1 ÷ 0.5 = 2 2 ÷ 0.5 = 4 , 4 ÷ 0.5 = 8 . 0.5^-3 is 8 (0.5^-3)^x = 0.5 , 0.5^(-3x) = 0.5 -3x = 1 , answer is A So x = 1/-3 or -1/3 😊 as you like .
Thank you 😊
Класс!
3^x+3^x=162 ; 3^x=162/2 ; 3^x=81 ; 3^x=(9)^2 ; 3^x=(3^2)^2 ; 3^x=3^4 ; X=4
?=(4/100)^1/2=2/10=20%ans
D
=/0.2•0.2 =(/0.2^2)=0.2
😂🤣😂🤣😂🙃
16
Какой то гон. Реально по -русски x=0.5 /8 и вся канитель ваша не нужна.
A. √(x + 1) = 1 x + 1 = 1 x = 1 - 1 = 0
Mksh ilmunya ka
16