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เข้าร่วมเมื่อ 12 ก.ค. 2017
STAAD Pro 01 Modelling of G+9 RCC building
This video will help all students who are learning STAAD Pro in modelling a G+9 RCC building. For more related videos stay tuned to this channel and keep learning.
มุมมอง: 63
วีดีโอ
Ferrari Method Q.5 Mathematics
มุมมอง 2.7Kปีที่แล้ว
This video will help viewers to understand the concept of Ferrari method.
Cardan Method Q.8- Theory of equations
มุมมอง 3.6Kปีที่แล้ว
This video will help viewers to solve questions related to cardan method and theory of equations.
DESCARTE METHOD Q.2- MATHEMATICS
มุมมอง 7Kปีที่แล้ว
This video will help viewers to understand a different type of solution for descarte's method.
Eigen Value & Eigen Vector Question GATE 2017(2 marks)
มุมมอง 5592 ปีที่แล้ว
This video will help students to solve questions related to eigen value and eigen vectors.
NIT AGARTALA (Awesome view from hostel)
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NIT AGARTALA (Awesome view from hostel)
UNIT DIGIT SHORT TRICK Solve in seconds
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This video will help students to solve questions related to calculation of unit digits in numbers having bigger powers.
ROOT TRICK(Root of Root)
มุมมอง 3203 ปีที่แล้ว
This question is kind of tricky. But these type of questions are solved by modifying them to 2ab, a^2 and b^2 .
Smart Equation(Solve if u r smart)
มุมมอง 5433 ปีที่แล้ว
If you are smart, solve this equation. I am giving the complete solution for this equation. Well this equation can be solved by simple hit and trial method if u r smart enough to do that.
FIRE SAFETY REGULATIONS(12th Schedule & Article 243-W)
มุมมอง 2183 ปีที่แล้ว
FIRE SAFETY REGULATIONS(12th Schedule & Article 243-W)
PM - KISAN SCHEME MAY 2021- 8th Installment
มุมมอง 883 ปีที่แล้ว
PM - KISAN SCHEME MAY 2021- 8th Installment
Supreme Court proceedings- Live Telecast! Right or Wrong? (Article 12 & 129)
มุมมอง 683 ปีที่แล้ว
Supreme Court proceedings- Live Telecast! Right or Wrong? (Article 12 & 129)
Cantilever Beam- SFD & BMD( Point Load, U.D.L. , U.V.L. )
มุมมอง 21K4 ปีที่แล้ว
Cantilever Beam- SFD & BMD( Point Load, U.D.L. , U.V.L. )
U.V.L.- SFD & BMD(Uniformily varying load on a simply supported beam)
มุมมอง 25K4 ปีที่แล้ว
U.V.L.- SFD & BMD(Uniformily varying load on a simply supported beam)
2025 attendence
Sir yaha pehle Y ka value kese nikala? Y= X-1 he yaha pe
Nice and informative
Bohat acha tha sir nyc explanation ❤
Sir bina calculator ke kaise values nikalenge
Sir vo 5:45 pe lambda ki values kaise nikalenge
After reaching at cubic equation, press mode in calculator, then press '5' for equation(5:EQN), then press '4' for cubic equation, then enter the respective values one by one by pressing enter & finally press enter for values. Or check my latest video on ferrari method Q.4
4:28 - the imp ones!
Thank you 😊 bhaiya love your teaching skills...❤❤
Life saver 🙏 bhai 😭
Your teaching is better than our teachers 😅
Thankyou dear
One line❌️any row or column✅️
Thnku so much sir
-27 k cube root ,-3,-3w,-3w^2
-27 ka cube root -3 kasa ha
Nice explanation sir ❤
Sir cubic eqn se lamda ki value kaise nikali j
After reaching at cubic equation, press mode in calculator, then press '5' for equation(5:EQN), then press '4' for cubic equation, then enter the respective values one by one by pressing enter & finally press enter for values. Or check my latest video on ferrari method Q.4
Sir can u pls solve this question x³-6x+4=0
Thank you very much ❤
Thank you sir
aur agar constant value prime agayi toh aagyi toh??
amazing video sir it will help me
Θα μπορουσες πολυ πιο γρηγορα να κανεις το εξης: η εξισωση γραφεται: [(χ^2)^2-2×χ^2×5χ+25χ^2]+10χ^2-50χ+24=0 (χ^2-5χ)^2+10(χ^2-5χ)+24=0. Θετεις χ^2-5χ=y και εχεις την εξισωση y^2+10y+24=0 etc. Μια μεθοδο που χρησιμοποιει ο infyκλπ
Just awesome explanation 👌👌👏
Only took less than 20 sec as a IIT JEE aspirant 😂 Hint: factor of 24 (1,2,3,4,6,8,12,24) Also the 24 is product of roots (here will be four roots as polynomial is biquadratic ) Now take any 4 factor with +/- sign ( which required) of 24 in a way such that it's sum will be 10 ( sum of roots ) I have taken 1,2,3,4 This method is only when leading coffecient is 1
Wow. Perfect.
Fantabulous
Bsc ke exam me calculator 😂😂😂
This is the most satisfying way ever to learn the cardan's method sir please make more videos on bsc mathematics syllabus.😅
Lemda ki value kese nikali
After reaching at cubic equation, press mode in calculator, then press '5' for equation(5:EQN), then press '4' for cubic equation, then enter the respective values one by one by pressing enter & finally press enter for values. Or check my latest video on ferrari method Q.4
Sir lambda ki value nikalne ka method nhi h kya koi?
After reaching at cubic equation, press mode in calculator, then press '5' for equation(5:EQN), then press '4' for cubic equation, then enter the respective values one by one by pressing enter & finally press enter for values. Or check my latest video on ferrari method Q.4
@@civiluptodate1580 bro exam me calculator allowed nhi h 🙏
That was so much needed ❤
😂😂😂
We can use cubic formula derived by using Cardano Method for lambda
Thank you so much sir. Finally understood the concept. Yours was the only explanation that helped me.
😊😊
Thanks bhai meri jindagi safal kar di
Thanks sir very useful
How to calculate lamda without calculat
10000! Kya hoga
Cubic equation par artificial intelligence🤖🔬 ka use karwa do phir sari duniya💻 following💻 karegi🎉🎉🎉
Rgpv university
Jab apan cardanos method lagate h... tab phle solution jo rhta h vo toh real rhta jabki baaki ke do bache hue solutions mh complex number bhi aata h naa .
Bhaai lemda ki value 7 or 21/2 bhee daal sakte the or itni jaldi lemda kee cubic equation ko solve kese kar liya ??
Lengthy process
Are Bhai b=4ac kese kiya
D = 0 B^2 - 4ac = 0
Sir ji vvi question m2 ka aur solution kijiena aap pls sir ji
Final answer is wrong sir, it's not 16 a2/3 , it is 64 a4/3
This is only for cubic equation with all integral roots so it would be handy in some questions but in olympiads it can't be used as there all roots used to be imaginary
Sir cab you make a video of polynomial and theory of Equation. Before my exam I can't understand the methods.
Sirji humne discarte method me t ki value 4 kaise maanli sir i have doubt please bata do aap