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@@fashionista_2009 thanks a million for that awesome feedback!! Motivates me a great deal to continue making relevant content!! 😊😊😊👍👍👍

@@EnjoyMath You desrve alot of subs Respect for you beautiful young lady ❤️🔥

@@rashahashir3856 hello, pls can u share your question... I will surely try my best to help u out... 👍👍

@@EnjoyMath Can I get your insta id ma’m? So that I can send or email address or anything

instagram.com/enjoymath111/ Insta I'd is also mentioned in the description tab of enjoy math channel

That's awesome!! Very glad to be of help!! 👍👍👍

@@orjiprosper4974 all the very best for your exam 👍👍👍

@@Mage_Natan very interesting question... One way could be to club class intervals in such a way that we get equal width class intervals... For example- 5-8 freq 7, 8-10 freq 3 , 10-15 freq 9 etc... We may regroup them as 5-10 freq 10, 10-15 freq 9 and so on... Then we can proceed.... Pls let me know if you have any questions...

Thank you so much for the wonderful compliment...!!! So good to know that the video has been of help to you!! 😊😊👍👍👍

Thank you so much for the wonderful comment... really happy to be of help!! 😊😊👍👍

Thanks so much for the awesome feedback... really means a lot!! 😊😊👍👍

Most welcome!! Very happy to be of help!! 😊😊👍👍

Congratulations aapko 👏👏 👏👍👍👍 Ok .....point note kar liya hai 😀😀

@@googledog1627 thank you so much for the appreciation!! Really means a lot to me!! So happy to be of help.... 😊😊👍👍

@@rshardwaresragu3633 most welcome!! Very glad to be of help!! 😊😊👍👍

Most welcome!! Really happy to be of help!!👍👍👍

@@Abdihamid2024 all the very best for your exam 👍👍👍

@@HimanshuSharma-cs3fg most welcome!! Really so glad that you found the video helpful!! And all the very best for your test!! Do let me know how it went.... 😊😊👍👍👍

@@aparnajena7466 wow... Thank you so much for the compliment... You've made my day!! 😊😊👍👍

@@aparnajena7466 thank you so much for the appreciation!! 😊😊👍👍

@@MrStrangerr2002 thank you so much for the wonderful encouraging feedback!! Hope to continue making relevant and useful content !! 😊😊👍👍

Here, the equation is Median = 40+ (15*20)/32 In the video, I just cancelled the common factor 4 present in 20 and 32. Median = 40+ (15*4*5)/4*8 Did u observe that the 4 was inside 20 and 32...so to make calculations easier,we cancel 4 from numerator and denominator,that's it...however,you can get the same answer without the cancellation, Median = 40+ (15*20)/32 = 40 + (300/32) = 40 + 9.375 = 49.375 Pls let me know if you have any questions....

Thank you so much for the wonderful comment.... really means a lot....very happy to be of help!! 😊😊👍👍👍

Thank you so much for the appreciation!! Happy to be of help 😊😊👍👍

@@max-ws5fw thank you so much for the wonderful feedback!! Really happy to be of help!! 😊😊👍👍

@@jobtech7422 thank you so much for the wonderful comment.... So happy that you found the video helpful!!😊😊👍👍

Thank you so much for the support and encouragement... Really means a lot!! 😊😊👍👍👍

I agree ,this is just to give a visual imagery..and how you may link similar pattern formulae ...👍👍👍

@@EnjoyMath yeah true

@@naveedahmad9337 which coefficient?

@@EnjoyMath coefficient of quartile deviation

@@naveedahmad9337 coefficient of quartile deviation = (Q3-Q1) /(Q3+Q1)

@@naveedahmad9337 coefficient of quartile deviation = (Q3-Q1) /(Q3+Q1)

I can surely help you out...pls share the questions

@@TambuwalAcademy in exclusive class intervals as given in the videon example, class boundary and class limits are same, incase we have inclusive class intervals, we will use class boundary... Pls let me know if you have any questions..

Nice try,but that's not the correct answer....what is the value of Sigma(xi-mean)² that you got?

Thank you so much for the lovely compliment!! You've made my day with your encouraging comment!! 😊😊👍👍

@@awantikabhatt3423 thank you so much for the wonderful comment!! Really gives me motivation to keep going !! 😊😊👍👍👍

Most welcome!! Really so glad that you found the video useful!! 😊😊👍👍

Hello, good try...but not correct answer...what is the value of Sigma(xi-mean)² that you got?

Thank you so much for the wonderful comment....really means a lot !! 😊😊👍👍👍

Here we have inclusive class intervals,so both lower limit value and upper limit value are included in each class interval,so h= upper limit value - lower limit value + 1. For exclusive, h= upper limit value - lower limit value,because upper limit value is excluded, but for inclusive,we add 1 because upper limit value is included So here h= 105-101+1=5 Pls let me know if you have any questions...

@@UsernameXYZ947 thank you so much for the appreciation!! 😊😊👍👍 s=ut+1/2at², where s is displacement, a is acceleration due to gravity, u is initial velocity.... Here, u=0, a=9.8, Therefore, s= 9.8t²/2 s= 4.9t² Pls let me know if you have any questions...

@@niveds2031 thank you so much!! Really happy that you found the video useful 😊😊👍👍

Sorry, I would like to do in hindi too, par jab meine channel start Kiya tho English mein start kar diya, aur kafi videos English mein banaye hain,toh abhi change karna problem ho jayega...🙏🙏🙏🙏

@@user-xf5sg7ze1h that's so great to know!! Congrats!! Really happy that the video helped you!! Thank you so much for the awesome comment!! 😊😊👍👍👍

Thank you so much for the wonderful comment....glad to know that you found the video useful!! 😊😊👍👍

Most welcome!! Really happy that you found the video useful!! 😊😊👍👍

Most welcome!! Really happy that you found the video useful!! 😊😊👍👍

Most welcome!! Really happy that you found the video useful!! Thank you so much for the wonderful comment 😊😊👍👍👍

Hello sir, In the linear equation 20x+25y=1000 We are putting the value of x =20 and y= 24 So 20x= 20x20= 400 And 25y= 25x24=600 Therefore 20x+25y=400+600=1000 Pls let me know if you have any questions sir...😊😊👍👍

My one more doubt about this problem is how many guests are expected while planning a party and is it planned to give each guest one pizza and one donut? Because some one may like only a pizza or a donut then we shall have to have some more items than expected! Secondly 20x + 25 y= 1000 statement is misleading (as it does not fulfill the equation),as our next step is 20x+ 24 y= 1000. Instead it would be wise to omit 20x +25 y=1000.but an additional note that if you know the number pizzas required you can get the number of donuts from the equation i.e. the cost of pizzas(20×20)+ y, (cost of donuts)= Rs1000/-. 2hd step is y= 1000- 400 =Rs.600/- 3rd step is 600/25= 24 donuts, to remain inside the budget of Rs.1000/- I hope I make myself clear about the difficulties of our hypothetical upcoming party!Regards.😊 dr.s.r.latkar

@suhaslatkar9007 First question - The question says that for the party,budget is rs. 1000. And 2 items on the menu are pizza costing rs. 20 each , and donut costing rs.25 each. So how many donuts and pizzas can to be ordered so as to be within budget... If x is the number of pizzas and each pizza costs rs.20,then 20x denotes the total cost of pizzas. If y is the number of donuts and each donut costs rs.25,then 25y denotes the total cost of donuts. Hence total cost of both pizzas and donuts will be 20x + 25y and that has to be equal to 1000. Hence the equation is 20x+25y= 1000 . how many guests are expected? That is not given explicitly in the problem statement. But we can add it as an interesting restriction..also how many maximum pizzas and donuts are to be served to each guest? That will make the question even more realistic... However,in the video example,I have only chosen a simple scenario to show how linear equation is useful.... Second question - I am sorry if it's misleading sir, will surely try to make it more clear in future videos...thanks for the feedback...but the essence is that there are infinite solutions to this linear equation....but ofcourse if u want to avoid decimals and fractions for number of pizzas and donuts ,there will be fewer number but still good number of alternatives for the hypothetical party 😊😊

Many, many, thanks, I must be the most dense student you ever had!😊 How will it be if we use X( prime x) for a total value of x pizzas (Rs.20× *some number of pizzas one chooses to buy as per the number of guests*) and Y(prime y)= total value of y donuts(25× any number dependant upon x pizzas to be purchased ) and we write the equation as X(cost of pizzas)+Y( to be derived)= 1000( the limiting budget figure)! So if only 10 pizzas are decided to be purchased( you know very well that in our party most guests hate pizzas, that's why only 10 piz.😊), then 200(X)+ Y=1000. next step Y=1000-200= 800. 800÷25=32 donuts. So now we can confidently buy 10 pizzas and 32 donuts and if some one asks for one more pizza(!),we say sorry only 10 pizzas were available 😊. I hope this will increase your hopes in me as an ok ish student material to teach me derivatives to calculate the instantaneous speed of the car at the next (dreadful)5th second given by dy/dx=2x.( these days this perplexing problem haunts me even in my dreams).pl.do not forget to send me your link on derivatives. with great regards, dr s.r.latkar😊

@@suhaslatkar9007 that's an awesome explanation sir of the party question.... Great going 👏👏👏👏 th-cam.com/play/PLUeuL5HZSlHzpUVz0nzncVuGaQLy476lj.html&si=ScK8GHG6Dr2VvgQB Above is the link with videos on calculus- hope you will find them useful.... I am working now on a video on integration .... Hope that too will be of help.... Your interest in the subject is really infectious sir 😊😊👍👍👍

Thank you so much for the wonderful feedback!! Really means a lot!! 😊😊👍👍👍

@@EnjoyMath maam can you make a similar video for integration

@that.guy.09 yes , will try my best...will take some time,but will definitely make it...thanks a lot for the suggestion 👍👍👍

Most welcome!! Really happy to be of help!! 👍👍👍

Most welcome!! Really happy that you found the video useful!! 😊😊👍👍

I did not understand your question, h is class size , f is frequency....can u pls elaborate?