David Vision
David Vision
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Determine the reaction at the supports A and B
Determine the reaction at the supports A and B.
Is It look to hard to solve❓🤔
In this video, we are showing you the simple way to determine the reaction at the supports A and B. So this is example that we made for the first learner of Analysis of Statically Determinate Structures.
This video made from problems in Structural Analysis - Eight Edition 📓
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In this video, you gonna learn some and i hope it can help you out.
Study, Because You Still Have a Chance.
Thanks for Watching 🌟
#FrameStructures #Reactions #DavidVision
มุมมอง: 204

วีดีโอ

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Determine the loading on the beam

ความคิดเห็น

  • @gifttituschisunka1180
    @gifttituschisunka1180 29 วันที่ผ่านมา

    Well explained

  • @adamkats2515
    @adamkats2515 หลายเดือนก่อน

    youre the GOAT

  • @cht5086
    @cht5086 2 หลายเดือนก่อน

    HI, What about Fy and Dy reactions?

    • @DavidVision
      @DavidVision 2 หลายเดือนก่อน

      You just apply directly by writing the moment equation of equilibrium about FD. Hope you learn some.

  • @math_withme_rathana
    @math_withme_rathana 6 หลายเดือนก่อน

    អរគុណច្រើនបង🙏

  • @merc9315
    @merc9315 6 หลายเดือนก่อน

    can you explain why you divide by 2 in the sum of forces in vertical directions please??

  • @usermbark
    @usermbark 8 หลายเดือนก่อน

    Thanks! But there is a mistake at Moment A, the Cy distanice should be: Cy(5 + 3cos30) By the way you write the write answer it is 11.845 kN but by your equation it should be 20 kN.

    • @DavidVision
      @DavidVision 2 หลายเดือนก่อน

      Glad you found out the error 👏🏼 Hope you learn some.

  • @DavidVision
    @DavidVision 9 หลายเดือนก่อน

    ⚠️ There are ERROR at Segment ABC. Please check at : Sigma of Moment at A, There is (2kN × 6m) × (6 ÷ 2) - (By × 4m) - (2kN×6m) = 0 Hence, By = 6kN. Sigma of Force along Y axis, There is Ay + 6kN + 2kN - (2kN/m × 6m) = 0 Hence, Ay = 4kN.

    • @moatlhodibagayi-vk5gt
      @moatlhodibagayi-vk5gt 7 หลายเดือนก่อน

      Thats right...even after resolving for external reactions from seg CDE AND seg EF beam can be considered as whole and taking moments about A to get By

  • @lewisqiu5960
    @lewisqiu5960 9 หลายเดือนก่อน

    can you please explain more about grid ABCD. how is the 6.42kn/m from. thanks

    • @ghofranahmed9194
      @ghofranahmed9194 8 หลายเดือนก่อน

      did you know the answer?

    • @sam7483-q8v
      @sam7483-q8v 4 หลายเดือนก่อน

      @@ghofranahmed9194 is 1.5*12.84/2= 9.63kn/m

    • @paulelias1312
      @paulelias1312 2 หลายเดือนก่อน

      He took the load 12.84 times the area of the triangle and he will find 19.26 as a single load but as a distributed load divide by 3 so do not include the horizontal length !! and therefore you will find 6.42 :)

  • @usermbark
    @usermbark 9 หลายเดือนก่อน

    High quality solution

  • @Sero-iraq
    @Sero-iraq 11 หลายเดือนก่อน

    Thanks my friend ❤❤

    • @DavidVision
      @DavidVision 11 หลายเดือนก่อน

      Welcome 😊

  • @kimsabellano9249
    @kimsabellano9249 ปีที่แล้ว

    I've viewed the solution manual of this problems but I couldn't understand where does those numbers come from.. thank you for clearing my confusions

  • @aalii33
    @aalii33 ปีที่แล้ว

  • @theunknown9557
    @theunknown9557 ปีที่แล้ว

    Can you continue to explain the book excercises? is great explanation, im learning more here than with my teacher

  • @jesikaidris5552
    @jesikaidris5552 ปีที่แล้ว

    where do you get = 47.43 kN?

    • @DavidVision
      @DavidVision 2 หลายเดือนก่อน

      Glad you found the error 👏🏼 The real Answer is By = 60.35 kN. Hope you learn some.

  • @engmohamedessehassan8412
    @engmohamedessehassan8412 ปีที่แล้ว

    Thnks you helped me😍

  • @mohamedabdullahi1676
    @mohamedabdullahi1676 ปีที่แล้ว

    thanks eng

  • @dylansmith2709
    @dylansmith2709 ปีที่แล้ว

    thanks!!!

  • @JEVELAVTAHADLANGIT
    @JEVELAVTAHADLANGIT 2 ปีที่แล้ว

    the total load is not 2.284 Kn/m, it should be 1.663 Kn/m

    • @DavidVision
      @DavidVision 2 หลายเดือนก่อน

      Glad you found out the error 👏🏼 You are correct 💯 Hope you learn some.

  • @hwan00ju
    @hwan00ju 2 ปีที่แล้ว

    hello, i was not able to get the value for xb =0.2536 how did u get it. thankyou 💗

    • @DavidVision
      @DavidVision ปีที่แล้ว

      0.6m - (0.1732m × 2)=0.2536m

  • @Abdulaziz-ie8dr
    @Abdulaziz-ie8dr 2 ปีที่แล้ว

    Thank you! how can I calculat the steel reinforcement for the newjersy?

  • @civil-mind
    @civil-mind 2 ปีที่แล้ว

    Sir why are u not uploading new videos. Your way of teaching is so simple and good

  • @vincentcabado4746
    @vincentcabado4746 3 ปีที่แล้ว

    Thank you, this really helped!

    • @DavidVision
      @DavidVision 3 ปีที่แล้ว

      It's my pleasure.

  • @tgza1331
    @tgza1331 3 ปีที่แล้ว

    Why the area of the steel you put 0.01 ? it must be 0.005 right?

    • @DavidVision
      @DavidVision 2 หลายเดือนก่อน

      There is cold form steel that has diameters of 10mm.

  • @din-wa3949
    @din-wa3949 4 ปีที่แล้ว

    Good

  • @ARALArchitect
    @ARALArchitect 4 ปีที่แล้ว

    Cool !

  • @topfit1596
    @topfit1596 4 ปีที่แล้ว

    Nice

  • @helenllona7659
    @helenllona7659 4 ปีที่แล้ว

    Thanks you for sharing this.

  • @sophatthong4324
    @sophatthong4324 4 ปีที่แล้ว

    Thanks for sharing

  • @din-wa3949
    @din-wa3949 4 ปีที่แล้ว

    This video is very helpful 👍🏻😍

  • @soksokhomchannelofficial1752
    @soksokhomchannelofficial1752 4 ปีที่แล้ว

    Good bro

  • @NewTasty
    @NewTasty 4 ปีที่แล้ว

    Nice video

  • @seavhongrenofficial
    @seavhongrenofficial 4 ปีที่แล้ว

    បកស្រាយបានល្អណាស់

    • @DavidVision
      @DavidVision 4 ปีที่แล้ว

      អរគុណច្រើន។

  • @CookingWithMinea
    @CookingWithMinea 4 ปีที่แล้ว

    very nice bro

    • @DavidVision
      @DavidVision 4 ปีที่แล้ว

      Thanks you so much 🥰

  • @DavidVision
    @DavidVision 4 ปีที่แล้ว

    សំណួរសួរវិញថា ហេតុអ្វីបានជាកប៉ាល់អណ្តែតលើទឹកដូចទឹកកកដែរ?