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Stephen Willshaw
Hong Kong
เข้าร่วมเมื่อ 25 มี.ค. 2013
วีดีโอ
IB Physics May 2021 TZ2 SL Paper 1 Question 6
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IB Physics May 2021 TZ2 SL Paper 1 Question 6
IB Physics Lecture: C4.2. Standing Waves in Strings and Pipes
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IB Physics Lecture: C4.2. Standing Waves in Strings and Pipes
IB Physics Lecture: C4.1. What Are Standing Waves?
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IB Physics Lecture: C4.1. What Are Standing Waves?
Hi what about if the question asks for what force equals?
@daniilsolopov2764 thank you for the question. the best answer for this is the rate of change of momentum, however that is not in the GCSE spec. for this level you might be able to use the formula F = ma to answer it. I don't think I've seen that in a paper, however it could come up!
Hi Dr. Stephen! I think you have made a mistake here, sin α should be h/r : )
i am sure you are right! when I get a second I will check 😊
I have a question. Do the x axis error bars play a role in the uncertainty of the gradient?
@ekaansharora5776 good question! yes they do. typically in A-LEVEL or IB you will be given error bars in just one axis, hence this video. if you had two sets you would need to fit your lines of best fit through error bars in both dimensions
really helpful, thank u
@BorisNVM my pleasure, if there's any other subjects you'd like to see covered let me know!
nice!
(M+m)a = Ma - mgu Ma+ma-Ma= -mgu ma= -mgu a = gu
Hard topic made to sound easy by good padagogy! Great job!
@@FisicaDirectoaoAssunto that's very kind of you, thank you!
YEAAAAAHHHHHHHHHHHH
Very clear explanation. Thank you!
is there a way to know this without drawing it out?
good question - it would be enough to remember that, for example, the central point never stays as a node/antinode...
and that A + N is always odd
Beautiful video, quick and concise, thank you.
that's very kind of you. feel free to let me know if there are any other topics you'd like to see covered
😊😊😊
Is the force of the load on the elevator ma + mg? Which is the reaction force of the elevator on the load.
yes, assuming m is the mass of the load!
@@stephenwillshaw7481nice, thanks for your video
my pleasure, let me know if you have other questions, or if there's an MCQ you are stuck on!
How do you calculate the gradient of the linear regression?
I didn’t understand why -F was added to G’s tail? (great video tho, thank you!)
hi there, glad you enjoyed the video! I believe -F has been added as the question states that F is reversed, so F becomes -F. hope that clears things up, and let me know if you have any more questions!
Thank you, it was really helpful
My pleasure!
he's the reason i'm not failing physics
abbreviation. Britannica Dictionary definition of QED. - used to say that something (such as a particular fact or a logical statement) proves what you were trying to prove. ◊ QED is an abbreviation of the Latin phrase “quod erat demonstrandum,” /ˌkwɑːdˈeɚˌɑːtˌdɛmənˈstrændəm/ which means “which was to be demonstrated.”
Latin abbreviation for quod erat demonstrandum: "Which was to be demonstrated."
Very good mister!
love it😍
Very educational video 😮
🤩😍❤🤩😍❤🤩😍❤🤩😍❤🤩😍❤
He he he ha
🐐👍
Great lesson Mr Willshaw!
Thanks Arthur! Hope you are well!
Love your content Mr WIllshaw
thanks James! I unfortunately never taught you guys how to juggle...
Do you know anything about radioactivity?
first
very possibly! thanks for pointing this out - I'll have a check and see what I can do about a change if required
in minute 3:50 isn´t the uncertainty 10/580 rather than 10/680? thanks
thank you sir!!
great video from a great teacher!
Thank you so much!!!!
You're welcome! if there are any other skills you would like to see explained feel free to let me know
hashtagmrwillshawoutthehood
Great video as always Mr. Willshaw!
Thanks Mattia! Expect more, and feel free to watch and remind yourself of how much physics you have learnt! hasthagphysicsnightclub
I would just like to say thank you very, very much for your extremely useful past paper explanations for 0654. There is a real shortage of material available for that course and your physics explainers are really valuable. Thanks again.
My pleasure Nick. I've taken a short break from 0654 however am looking at building up some more content soon. If you have any particular requests, let me know!
great video
more videos plsssss
Sure thing, what would you like to see?
@@stephenwillshaw7481 organic chemistry and more paper solving about 0654 and 0620 the seperate chemistry course
Acctually this is so helpful, thank you. Keep it on!!!
My pleasure! If you have any other equations you would like to see explained, let me know.
Thankyou so much!!
No prob!, I'll be uploading a few more today. Hope they are useful!
Great Video!
First
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