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Ryan Heinrich
เข้าร่วมเมื่อ 31 มี.ค. 2020
Assistance with AP Classroom FRQs and Released FRQs for AP PHYSICS 1 and 2.
Net Force Test Prep
Learn the essentials of net force physics probelms in this comprehensive guide! We'll explore how to draw free body diagrams, identify forces accelerating a system, and calculate net force. Discover how to determine acceleration, find normal force, and use it to calculate friction. Perfect for students and enthusiasts looking to deepen their understanding of mechanics!
มุมมอง: 24
วีดีโอ
Quarterback Projectile Motion Problem (no initial velocity given)
มุมมอง 572 หลายเดือนก่อน
In this video, we tackle projectile motion. Given a launch angle and the horizontal distance traveled, we aim to find the maximum height achieved by the projectile-even without knowing the initial velocity. Join us as we break down the concepts of projectile motion step by step. We’ll explore how to use the horizontal distance and angle to calculate the time of flight and then use that to deter...
Projectile Motion Problem, Golf Ball (Initial Velocity Not Given)
มุมมอง 1362 หลายเดือนก่อน
In this video, we tackle a projectile motion problem! Given a launch angle and the horizontal distance traveled, we aim to find the maximum height achieved by the projectile-even without knowing the initial velocity. Join us as we break down the concepts of projectile motion step by step. We’ll explore how to use the horizontal distance and angle to calculate the time of flight and then use tha...
Ch. 3 #17 College Physics Serway and Vuille
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Ch. 3 #17 College Physics Serway and Vuille
Ch. 3 #13 College Physics Serway and Vuille
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Ch. 3 #13 College Physics Serway and Vuille
AP PHYSICS 2: Unit 5 FRQ 1 (AP Classroom)
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AP PHYSICS 2: Unit 5 FRQ 1 (AP Classroom)
AP PHYSICS 2: Unit 2 FRQ 2 (AP Classroom)
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AP PHYSICS 2: Unit 2 FRQ 2 (AP Classroom)
AP PHYSICS 2: Unit 2 FRQ 1 (AP Classroom)
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AP PHYSICS 2: Unit 2 FRQ 1 (AP Classroom)
AP PHYSICS 1: Unit 7 FRQ 1 (AP Classroom)
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AP PHYSICS 1: Unit 7 FRQ 1 (AP Classroom)
AP PHYSICS 1: Unit 6 FRQs 1 and 2 (AP Classroom)
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I was cut off at end of video. Take your 320N/m spring constant and plug into Period equation along with given mass 0.4 kg top solve for period equaling 0.22 s/cyc
AP PHYSICS 2: Unit 3 FRQ 2 (AP Classroom)
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In part B the final expression for the velocity of the electron should have a square root. Oops.
AP PHYSICS 2: Unit 5 FRQ 2 (AP Classroom)
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AP PHYSICS 2: Unit 5 FRQ 2 (AP Classroom)
AP PHYSICS 1: Unit 5 FRQ 2 (AP Physics Classroom)
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AP PHYSICS 1: Unit 5 FRQ 2 (AP Physics Classroom)
AP PHYSICS 1: Unit 5 FRQ 1 (AP Classroom)
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AP PHYSICS 1: Unit 5 FRQ 1 (AP Classroom)
AP PHYSICS 2: Unit 4 FRQ 2 (AP Classroom)
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AP PHYSICS 2: Unit 4 FRQ 2 (AP Classroom)
AP PHYSICS 1: Unit 4 FRQ 2 (AP Classroom)
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AP PHYSICS 1: Unit 4 FRQ 2 (AP Classroom)
AP PHYSICS 1: Unit 4 FRQ 1 Part 2 (AP Classroom)
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AP PHYSICS 1: Unit 4 FRQ 1 Part 2 (AP Classroom)
AP PHYSICS 1: Unit 4 FRQ 1 Part1 (AP Classroom)
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AP PHYSICS 1: Unit 4 FRQ 1 Part1 (AP Classroom)
AP PHYSICS 2: Unit 3 FRQ 1 Part 2 (AP Classroom)
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AP PHYSICS 2: Unit 3 FRQ 1 Part 2 (AP Classroom)
AP PHYSICS 2: Unit 3 FRQ 1 Part 1 (AP Classroom)
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AP PHYSICS 2: Unit 3 FRQ 1 Part 1 (AP Classroom)
AP PHYSICS 1: Unit 3 FRQ 2 (AP Classroom)
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AP PHYSICS 1: Unit 3 FRQ 2 (AP Classroom)
AP PHYSICS 1: Unit 3 FRQ 1 Part 1 (AP Classroom)
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AP PHYSICS 1: Unit 3 FRQ 1 Part 1 (AP Classroom)
AP PHYSICS 1: Unit 3 FRQ 1 Part 2 (AP Classroom)
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AP PHYSICS 1: Unit 3 FRQ 1 Part 2 (AP Classroom)
AP PHYSICS 1: Unit 2 FRQ 2 Part 2 (AP Classroom)
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AP PHYSICS 1: Unit 2 FRQ 2 Part 2 (AP Classroom)
AP PHYSICS 1: Unit 2 FRQ 1 (AP Classroom)
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AP PHYSICS 1: Unit 2 FRQ 1 (AP Classroom)
AP PHYSICS 1: Unit 2 FRQ 2 Part 1 (AP Classroom)
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AP PHYSICS 1: Unit 2 FRQ 2 Part 1 (AP Classroom)
AP PHYSICS 1: Unit 1 FRQ 1 Part 2 (AP Classroom)
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AP PHYSICS 1: Unit 1 FRQ 1 Part 2 (AP Classroom)
AP PHYSICS 1: Unit 1 FRQ 2 (AP Classroom)
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AP PHYSICS 1: Unit 1 FRQ 2 (AP Classroom)
AP PHYSICS 1: Unit 1 FRQ 1 Part 1 (AP Classroom)
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AP PHYSICS 1: Unit 1 FRQ 1 Part 1 (AP Classroom)
🗣️🔥
Thank you kind sir
Any time
Thank you Mr Heinrich. Subbed 🗣️
Can someone please explain to me why the units work out to rad/s rather than sqrt(rad)/s. Isn’t cos theta also under the square root?
Hello and thanks for the question. Cos theta is under the square root, but cosine is a ratio of triangle sides and therefore has no unit. Ex. Adj/hyp = 3m/5m = 0.6 (no unit). Therefore, the cos theta has no bearing on the final unit. In addition, it should be stated that a radian is just a placeholder unit that may be used when it makes physical sense and disregarded when it does not, much like the unit "cycle". For instance when finding the velocity of a wave... (v=fλ). Ex. find the velocity of a wave that has a frequency of 2 cyc/s with a wavelength of 8m. v = 2cyc/s*8m = 16 m/s. You can see the cyc is disregarded and removed from the final unit. m*cyc/s should not be used. So back to the original question: √((m/s^2)/m) = √(1/s^2) = 1/s. While 1/s is correct, it is not the clearest physical representation...So we put radian in the numerator and say radian/second (rad/s).
4 years and still you're saving lives thank you for this
Just saved my life. Thank god!
pls can you either record horizontally or make the screen bigger so that we can read the whole text? Super useful videos otherwise!
🐐🐐🐐🐐🐐
5 am and I found this. My day is saved!
thank you so much for all of these videos, i was out for a week sick and they are really helping me catch up
Thank you so much for this! I found it really helpful
The key that is provided to teachers by AP Classroom says the H.A. is R/T^2, and the vertical axis is tan(theta), which I could not understand. Thank you for confirming my suspicions!
I love you
This helps sooo much
uhm so where do i find the correct answers for part d)?
can someone explain why in part c) the upward velpcoty at position 2 and the downward one are equal? I didnt quite get what he meant.
The reasoning is that on way the way up the velocity gets slowed down until it becomes zero by accelereation at a constant rate of -10m/s^2. This all happens within a certain amount of time. so it goes from max velocity to zero on the way up. On the way down it's basically the opposite where velocity goes from 0 to max because accleration of -10 now speeds in up in that same time frame.
the goat
If Branch B gets 12 amp current that means branch A also gets 12 amps of current in the orginal circuit. However would that not conflict with the loop rule, as the loop created with the battery and branch A do not add up to 0?(80 volts and -60volts dont add up to 0)
Thank you so much sir (୨୧•͈ᴗ•͈)◞♡ Wish you the happiest physics journey~
THE GOAT
In what case would the center of mass be speeding up?
You have to square root the answer for question b 5:17
Ths vidio hilping me so much rthanks. you!!!!
Thanks
On the ap exam, in the questions like part d, can you take down as positive? Do you need to announce it somewhere before doing it? Because I've done the constant negative slope for v graph and straight line on -10 for acceleration
good stuff, thanks so much man
if you see this comment i just want you to know that your work is greatly appreciated. unfortunately i wasnt lucky enough this year to get a very good physics teacher and reviewing these videos has really helped me to fully grasp the concepts, and the way you explain things makes all this information much easier to digest and understand. hope you enjoy teaching
Figure*
For part bii, couldn't you just do F=ma F=mv/t v=Ft/m v=(2.4N)(0.5s)/(0.4kg)
This dude is the goat
Really helpful, but I can't seem to find the second part to this FRQ.
shouldn't it be an elastic collision because it's a bounce?
Yes I think it’s an elastic collision. However, I think he was considering only the ball as a system. In that case, the momentum would be loss and not conserved since it experience a force from the ground, which was not part of the system.
I love you ❤
Appreciate all the help fr
bro I owe you my life thank you so much i want to name my children after you
😭
As u shouldd
Thank you so much
This guy is great
Heinrich is the goat
I'm a bit confused about part C. If you use the equation or displacement (yf-y0= v0t +1/2 at^2) and since displacement is 0, if you solve for t, you end up with t= 2v0/g. Why would this answer be wrong?
I’m not an expert but my teacher said for some problems the kinematic equations can be interchangeable if all variables are present
I love you
For part a ii) why wouldn’t you include tension in the FBD?
this is very late but I think it’s because block 2 was at rest on top of block 1, so the tension force wasn’t necessarily acting on it. I could be wrong!
i have zero idea how i would pass without you 🙏🙏 common heinrich W 🔥
1/19/23 MS.Blach class period 4 Gracias me amigo.
W Mr. Heinrich
Why there isn't a normal force acting on the block?
Normal force only applies when an object is on a surface
3:55 lol
physics? more like physically about to fail my class.
I love this guy
do you do online tutoring
could you also use t=sqrt(2h/g) and substitute the hmax equation (vo^2/g) into the time equation and get vo/g?
Yes, you can! That is what I did. h = 1/2at^2t = sqrt(2h/g) t = sqrt (2v0^2/2g/g) t = sqrt ( 2v0^2/2g^2) The 2 cancels out. And the rest can be removed using square root. t= v0/g
thank you