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Kindly drop the actual question here. Perhaps we made a mistake in the values used. The question will confirm you or us right

No sir you are Right sir it’s only the first equation it is 4a+ 12b not negative sir.Wrong computation but similarly working God bless sir

You are welcome

It's well

Share this video to others before asking of other numbers

Kindly read your books

Kindly read your books

Read read read!!

Ok. Teachers don't submit values or range of values to WAEC or NECO in physics practicals unlike chemistry, where they submit end point. Let no person make you frightened. Physics practicals are marked with respect to expected variations. That is whether your values are increasing or decreasing uniformly as expected. This means that no set of values is taken as the standard marking scheme but how correct are your values to what is expected. If your teacher tells you that he submitted values to WAEC or NECO, tell him I said it is a white lie.

@@bestsciencebrain thank you sir for releasing me from thinking too much. I so much appreciate

It is like you are not a subscriber to this channel and has not been following our updates

12 hrs to the time

Sir please what of physics theory

Remind us your question please

Ok

@@bestsciencebrain ok sir so what about my question

Your Teacher is the one that would fill the report form that would be packaged with your scripts and used by the examiner (marker) to judge all the students in your school. So your end point " VA " must agree with your teacher's own. If your teacher was not in school the examination day then he must have given the values to a colleague to fill for him. In a situation where the teacher forgets to include the report form, then the examiner (marker) must go through the whole scripts in your school and choose the average of the most random "VA " as the end point to judge all the students in a given school. Now see how it is marked: If your teacher's end point (VA) is 20.30 cm3 Then a student's whose VA is 20.30 + or - 0.10 cm3 scores maximum 8 marks on the table. That is a student whose VA is 20.20 or 20.30 or 20.40. A student whose VA is 20.30 + or - 0.20 cm3 (ie 20.10 or 20.50) scores 6 marks on the table A student whose VA is 20.30 + or - 0.30 cm3 (20.00 or 20.60) scores 4 marks A student whose VA lies 20.30 + or - 0.40 (19.90 or 20.70) scores 2 marks A student whose VA lies 20.30 + or - 0.50 (19.80 or 20.80) scores only 1 mark Any student whose VA lies outside the above mentioned limits ie from 0.60 of the teacher's end point scores zero on the table. Whether you scored maximum 8 marks on the table or zero does not affect your marks on the calculations that follow provided you used the right steps and formula to solve accurately. You guys have been advised over and over again to subscribe to the channel, turn your notification button on and be vigilant and not to start having regrets after the examination. You can never see our videos or post unless you have subscribed and have your notification button turned on. Then tune to the channel as from 10 pm to 11 midnight before the exam date.

@@bestsciencebrain no sir I mean in physics

Yes

Amen. Thanks

Yes it is

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We appreciate. Thanks a lot

Very wrong. Concentration must be to three significant figures.

We appreciate

We appreciate

Stay there and be asking questions

Thanks alot u really helped me today

We appreciate

Thanks a lot

You are welcome

You are welcome

You are welcome

You are welcome

If you are not given end point, start with number 2 and number 3. While solving them keep your ears open. The subject teacher will be in the hall. You will see him going round to inspect you guys. He will be frustrated on the kind of results he is seeing that he will give an idea of the end point to someone and you will capture it. If he says that end point lies between a range for instance 20.10 to 20.60. Then list all the values in this range on your rough work 20.10, 20.20, 20.30, 20.40, 20.50, 20.60 Cancel a value Infront and another at the back repeatedly until you reach the middle value and use it to prepare your table as the end point. In this case 20.30 and 20.40 are at the middle then choose any of them to prepare your table as the end point. Avoid cancellation of your table or altering figures because you will loose marks if you do so. However, if at the long run there is no end point given to you, then use ours

But 😢 I did it and I got my average volume of acid as 21.50😭 does it mean i will fail because in the report form the range of values were 20.40 20.60 and 20.80

Sir please answer me na😢

Amen🙏🏽

Amen. God bless you too.

You are welcome

You are welcome

You are welcome

You are welcome

They would still give you a reading. It's their duty.

But if we use this mans own it's okay right?

But if we use this mans own it's okay right?

Use your teacher's end point. If he doesn't give you on time, start with number 2 and 3, he will most likely say it in the hall

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Depends u can do that as well

You can do it like that too but just make sure you refill your burreteaftet each reading

You can do that. Everyone in the hall can have the same end point but different values as initial and final. However, I will advise you to avoid using 0.00 as your initial all through except for the rough. Not only would it look like pure manipulations but almost every one will do that thereby creating suspicion for malpractice. Assuming for titration 1. Let your initial be 1.00, volume of A used be 20.30 (end point), then add the two to get final as 21.30 For titration 2 , assume your initial is 5.00 and volume of A used (end point) is 20.30, then final becomes 25.30. For titration 3, assuming the initial is 10.00 and volume of A is 20.30 (your end point) then Volume of A used is 30.30. You can take the initial of your rough as 0.00. Choose values randomly as your initial to build your table especially from 1 to 15. Don't use higher values as your initial to avoid having a final value above 50 because the burette capacity is 50.

Thanks

Thanks a million times

Thanks a lot

It's legit

Its real

We have a name

Are those the actual questions??

@@Riley-p2t yes they are

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Not at all

Where's the calcium ion coming from please? I thought D is solution of powdered milk.

@@kelechiezeorah4619where did u see calcium?

@@Footballites check where you described miller test. You mentioned calcium salt which wasn't given.

My confusion is calcium

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Are you saying something practicable or what you think??

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We appreciate

AgNO3: 1.7 g in 500 cm3 of water NaOH: 2 g in 250 cm3 of water NH3: 10 ml in 20 ml of water. You can still increase the volume of water but make the NH3 solution moderately concentrated for effectiveness. Reagents especially NaOH and NH3 should be prepared freshly as they are required for optimum results while AgNO3 should be stored in amber coloured reagent bottles to minimize light decomposition

​@@bestsciencebrainthanks A million.

Hope 2M is OK for making acid bench reagents.

4 g of NaOH in 500 cm3 of water will give you a moderately concentrated solution of 0.2 M. Prepare freshly at the time of use due to it's deliquescent nature.

Can we also use this 0.2M concentration to prepare other aqueous reagents?

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