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Andrew
เข้าร่วมเมื่อ 15 มิ.ย. 2006
Third Form of Curvature
Curvature is defined in terms of the rate of change of the unit tangent vector with respect to an arc length parameter (first form). If access to an arc length parameter is not possible, the second form, which still still requires the derivative of the unit tangent vector, can be used. In the third form, we replace the unit tangent vector with a cross product of the first and second derivatives of the space curve. In this video, we use the third form of curvature to compute the curvature of a space curve and the curvature of a cycloid.
This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
มุมมอง: 8
วีดีโอ
Curvature Using the Second Form
มุมมอง 1114 วันที่ผ่านมา
We compute the curvature of a space curve using the second form of curvature which does not require an arc length parameter. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
Curvature of a Line, Circle and Helix
มุมมอง 1214 วันที่ผ่านมา
We use the curvature formula related to the arc length parameter, s, to compute the curvature of a line, circle and helix. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
Arc Length Parameter
มุมมอง 1214 วันที่ผ่านมา
The arc length parameter is a special parameter that keeps track of how far a point has moved along a space curve. In this video, we re-parameterize a curve in terms of the arc length parameter. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
Arc Length of a Space Curve
มุมมอง 182 หลายเดือนก่อน
We compute the arc length of two space curves by integrating the speed of the curve over a time interval. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
The Derivative of a Composition with a Vector-valued Function
มุมมอง 102 หลายเดือนก่อน
We find the derivative of the composition of a real valued function with a vector-valued function using the chain rule for vector-valued functions. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
The Derivative of a General Scalar Triple Product
มุมมอง 232 หลายเดือนก่อน
We use the product rules for the dot and cross products to find the derivative of the scalar triple product of three vector-valued functions. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
The Derivative of a Special Scalar Triple Product
มุมมอง 152 หลายเดือนก่อน
We use the product rules for the dot and cross products to find the derivative of the scalar triple product of a vector-valued function with its derivative and second derivative. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
The Derivative of a Cross Product
มุมมอง 62 หลายเดือนก่อน
We use the formula for the derivative of a cross product to derive a formula for the derivative of the cross product of a vector-valued function with its derivative. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
The Derivative of the Magnitude of a Differentiable Vector-valued Function
มุมมอง 342 หลายเดือนก่อน
We derive the formula for the derivative of a differentiable vector-valued function using the product rule for the dot product. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
Integrals of Vector-valued Functions
มุมมอง 412 หลายเดือนก่อน
We compute an indefinite integral and a definite integral of a vector-valued function. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
Unit Tangent Vector
มุมมอง 112 หลายเดือนก่อน
We find the unit tangent vector to a space curve and we find the vector form of the tangent line. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
A Line Segment in Space
มุมมอง 52 หลายเดือนก่อน
We write a line segment in space as a vector-valued function. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
Identifying a Space Curve From its Vector-valued Function Form
มุมมอง 52 หลายเดือนก่อน
We present a vector-valued function and identify the graph as a curve in space. The curve happens to be a line, making the identification relatively simple. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
Expressing a Line in Space as a Vector-valued Function
มุมมอง 132 หลายเดือนก่อน
We express a line in space through a given point with a given direction vector as a vector-valued function. This video corresponds to a problem given in the book Calculus III found at: ximera.osu.edu/math
The Distance Between a Line and a Plane in Space
มุมมอง 183 หลายเดือนก่อน
The Distance Between a Line and a Plane in Space
The Distance Between Parallel Planes in Space
มุมมอง 43 หลายเดือนก่อน
The Distance Between Parallel Planes in Space
The Intersection of Two Planes in Space
มุมมอง 113 หลายเดือนก่อน
The Intersection of Two Planes in Space
The Equation of a Plane in Space Given Three Points
มุมมอง 123 หลายเดือนก่อน
The Equation of a Plane in Space Given Three Points
The Distance Between a Point and a Line in Space
มุมมอง 123 หลายเดือนก่อน
The Distance Between a Point and a Line in Space
Sketching a Region in the Complex Plane
มุมมอง 273 หลายเดือนก่อน
Sketching a Region in the Complex Plane
Residue Theorem with Two Singularities
มุมมอง 94 หลายเดือนก่อน
Residue Theorem with Two Singularities
Extended Deformation of Contour Theorem
มุมมอง 204 หลายเดือนก่อน
Extended Deformation of Contour Theorem
hello...so for the circle r(1,r) and (-1,r) do you choose an abitrary radius for them?? or how do you determine their radius
Choose r small enough so that none of the circles intersect (any r < 1 will work in this problem)
Dr. Incognito, you rock..thank you!
N
Thank you!
What do we do in case we have two different unknown values? f(x,y)=.... ?
is your last name actually incognito?
Interesting fact: The null space of a matrix is a subspace of Rn and the column space of a matrix is a subspace of Rm with the matrix being defined as m x n matrix. This tells us that the null space of a matrix is a subspace of Rn or the number of columns and the column space is a subspace of Rm or the number of rows. That is why the null space has the same number of entries as the amount of columns while the column space has the same number of entires as the number of rows is what he is trying to say. Basically Dim(colA) = number of pivot colums and dim(nulA) = number of free variables, thus number of pivot columns + number of free variables = total number of columns
Ah perfectly explained, tyvm
Your video was a big help, thank you!
best video about row space so far.
Hey Dr. Incognito -- I'm a high school student that stumbled on your videos by serendipity, but you're helping me get through my linear class! Your videos are much more comprehensive than any others I've found :)
Really helped me!!
thank a lot Dr. incognito :D
Thanks for the clear explanation! Still a bit unclear about certain stuff, but this certainly did help :)
Oh yes because exponentials are never equal to zero.. But I can't solve this question with your method.. Can u help? Qns: Is y=3e^-2x an increasing or decreasing function?
y' = -6e^(-2x) which is negative for all values of x. Hence your function is decreasing for all x, i.e. on the interval (-infinity, infinity).
Why can't we use the exponential e^-x in the last example to obtain our x values? Can it be used?
A good explanation, clear and concise, but you need to turn off the cameras auto focus as it's distracting. Cameras find focus by contrast so if you have a plain colored surface like a whiteboard it will be difficult for the camera to know where to focus. Set it manually and then turn it off.
Thank you, I was waived into Calc 1 and your resources along with Dr. Dahal have been extremely helpful .
His wardrobe is boring.
you are the best sir. i learnt most of linear algebra in 3 days partly because of you
u r carazy good man
Epic. You made it easy for me. Thanks.
Wow very informative, clear, simple and understandable! Thank you so much.
I heard the grudge
keep up the hard work man! good video.
Not sure if Incognito is actually your name, but if it's not, it's great! This is a great series. It's actually quite a bit better than the more popular math-help videos.
Great explanation, its I was finding it hard to reconcile both these concepts side by side until i heard this.
Thanks a lot for the very clear explanation. Helped me a lot :)
Easy to follow, thanks!
Great example, thanks for sharing.
Thank you so much for your video. It really clears my doubt
Just what i needed , Thanks a lot
Good video real explanatory thanks
nice video, very helpful. thanks!
Amazing thank you!
but i was actually looking for a video on orthogonal complements of an inner product subspace..
great lecture! explained so many things that my prof didnt emphasize!!!!! Thank you Dr. Incognito!
VERY useful, thank you! It saddens me this has got such a little amount of views, its a great thing that you upload these lessons for free for everybody This is a very clear and concise explanation :)
Good explanation, odd name...
I agree. thanks for posting this. Really cleared things up for me.
x = 2 at the end, not 1 :)
@themrdaydreamer Since the numerator can have degree one less than the degree of the denominator (but not more), we must make sure that each of our partial fractions has that same property. Otherwise, there would be some fractions which we would not be able to decompose.
I LOVE YOU
please invest in a headset. You are a good teacher, but this vid needs an audio boost!
Thanks. That explanation helped out a lot.