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Yes, you can do that. It will give you the angle made by force with horizontal.

It is 75cos(-180) = -75 and 75 sin(-180) =0. By the way I have done it differently, Since 75 is acting towards negative direction of x-axis , it has only -ve x- component, that is -75 in x-direction and no y-component that is 0 in y- direction. Please go through the video, y will understand easily.

I have already given the proof. Kindly refer the video.

I need to contact you@

@@Engineer.Yousifplease message on : easyscienceprep@gmail.com

Please refer strength of materials by R K Rajput

Please refer sign convention explained in the beginning, you will easily understand.

Yes

easyscienceprep@gmail.com

Thanks and welcome

There was a writing error, I have made a modified video for Example -2, please check in the video list.

There was a typo error in the question, actually E for Aluminum is approx. 10^5 N/sq. mm. I have solved by taking correct value of Ea. Thanks and regards.

Thank you

Thankyou

Thank you

Cross sectional area of cone is of circular shape, hence area of circle is used in the expression, hope it clears your doubt.

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Thanks you

If we take a plane which makes an angle from AB plane in counter clockwise (theta=40 degrees) then we will get shear stress on that plane as negative.

Angle made by F4 with y-axis (Vertical axis) is 35 degrees hence F4y= F4 x cos35 and F4x= F4xsin35

Angle made by F4 with y-axis (Vertical axis) is 35 degrees hence F4y= F4 x cos35 and F4x= F4xsin35

yes

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𝞺=mass density=Mass/Volume; ω=weight density=Weight /Volume: therefore, ω=(mass x g)/Volume=(mass/Volume).g=𝞺.g, ω=𝞺.g. Here, in the problem weight density (ω) was not given hence we found mass density(𝞺) first and substituted in the expression.

It is a normal question prepared, not from any book. Hope it was helpful. Thanks

Ok

Similar procedure can be adopted to solve it. You have make deformation equal for each type of bar and total load would be shared by each bar. Hope it answers your question.

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Since value of shear stress on the inclined plane is calculated as 'positive', therefore, as per sign convention it is counter clockwise. Please refer the sign convention explanation in the video.

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Elongation is WL/2AE only Here, A=Cross section Area of base of cone. If you get it as WL/6AE, then A= Average Cross section area = 1/3(Cross section area of base)

Please recheck the video you are referring, elongation is WL/2AE here A= Cross section area of base of the cone.

Since plane is inclined in clockwise direction, we must draw it in clockwise sense in Mohrs circle otherwise we will get different values. Please follow the procedure you will get correct value of stresses on inclined plane.

Why shear stress formula got + Txycos2theta it should be -ve

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Yes, you are right

Thank you

Once you understand the concept, calculation can be done

@@easyscienceprep7445 I understood concept but wrong calculation I got it sir

Thanks

Thanks

Please have look at table , I have taken X-component positive towards right(i.e. positive direction of X-axis ) and vice versa, Similarly for Y-Component positive towards upward(i.e. positive direction of y-axis) and vice versa. since ΣFx and ΣFy both are positive the resultant force is in first quadrant. I will take some question where resultant will be in 2nd or 3rd quadrant, then it will be more clear. Thanks for showing interest in the video.

Thank you for the clarification 👍🏻