CX-RIDE
CX-RIDE
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วีดีโอ

23 February 2024
มุมมอง 2366 หลายเดือนก่อน
Helicopter Principles of Flight - Roll Induced Drag
Helicopter Principles of Flight - Retreating Blade Stall
มุมมอง 6346 หลายเดือนก่อน
Helicopter Principles of Flight - Retreating Blade Stall
Helicopter Principles of Flight - Autorotation in Forward Flight
มุมมอง 3.9K2 ปีที่แล้ว
Helicopter Principles of Flight - Autorotation in Forward Flight
Helicopter Meteorology - Stability
มุมมอง 1.4K2 ปีที่แล้ว
An introduction and simple method for describing stability. Treat yourself Steve D.
Cx-Ride FLARE EFFECT - Helicopter Principles of Flight
มุมมอง 2.1K3 ปีที่แล้ว
Cx-Ride FLARE EFFECT - Helicopter Principles of Flight
CX-RIDE INFLOW ROLL Helicopter Principles of Flight
มุมมอง 4.5K3 ปีที่แล้ว
I’m aware this one is poor and will make more clear shortly.
CX-RIDE FLAPPING TO EQUALITY Helicopter principles of flight
มุมมอง 6K3 ปีที่แล้ว
CX-RIDE FLAPPING TO EQUALITY Helicopter principles of flight
CX-RIDE POWER Helicopter Principles of Flight
มุมมอง 1.8K3 ปีที่แล้ว
This is particularly long on,y because of the extra side bars of background understanding and explanation. It should only take 12 mins.
CX-RIDE LIFT Helicopter Principles of Flight
มุมมอง 1.6K3 ปีที่แล้ว
CX-RIDE LIFT Helicopter Principles of Flight
CX-RIDE AUTOROTATION Helicopter Principles of Flight
มุมมอง 7K3 ปีที่แล้ว
CX-RIDE AUTOROTATION Helicopter Principles of Flight
CX-RIDE VORTEX RING Helicopter Principles of Flight
มุมมอง 2.6K3 ปีที่แล้ว
CX-RIDE VORTEX RING Helicopter Principles of Flight
Cx-Ride Limits to Forward Speed - Helicopter Principles of Flight
มุมมอง 2.2K3 ปีที่แล้ว
Cx-Ride Limits to Forward Speed - Helicopter Principles of Flight
Cx-ride Translational Lift- Helicopter Principles of Flight
มุมมอง 3.2K3 ปีที่แล้ว
Cx-ride Translational Lift- Helicopter Principles of Flight
Ground Effect - Helicopter Principles of Flight
มุมมอง 4.9K3 ปีที่แล้ว
Ground Effect - Helicopter Principles of Flight
The Vector Diagram explained - Helicopter principles of flight
มุมมอง 6K3 ปีที่แล้ว
The Vector Diagram explained - Helicopter principles of flight

ความคิดเห็น

  • @parivashhajiani
    @parivashhajiani 11 วันที่ผ่านมา

    Saw the play of autorotation

  • @orchidahussuhadihcro9862
    @orchidahussuhadihcro9862 20 วันที่ผ่านมา

    I always thought the angle of attack on the advancing blade was pulled down by the mecanical link on the main rotor mast. As the blade is allowed to move up thanks to an hinge. This movement also forces its angle to reduce, thus achieving equality ? Is it a wrong explanation ? I must admit I didn't really get the induced airflow shown in the video. I must watch again

  • @nguyenvantinh449
    @nguyenvantinh449 2 หลายเดือนก่อน

    Why does driven section move inboard when we raise the collective level ?

  • @pylaterreur
    @pylaterreur 2 หลายเดือนก่อน

    Thanks, I think explaning it as a continuous action and a rate of flapping makes it easier to grasp, compared to many other explanations just giving states/snapshots.

  • @picopilot
    @picopilot 3 หลายเดือนก่อน

    The drag vector component always seems arbitrary not only in this video but in every drawing including the FAA materials. How is the drag vector component length determined and how can its accuracy be determined? Can it be calculated? Is it irrelevant as long as a drag vector is shown/included?

  • @Kkross90
    @Kkross90 3 หลายเดือนก่อน

    Beautiful explanation 😊

  • @msvijayendrarao4150
    @msvijayendrarao4150 4 หลายเดือนก่อน

    Great job, thanks

  • @neomayad
    @neomayad 4 หลายเดือนก่อน

    Traffic!! Perfect analogy

  • @heli35
    @heli35 4 หลายเดือนก่อน

    A marvelous job!

  • @biblewaytolive
    @biblewaytolive 5 หลายเดือนก่อน

    Do your drawings bigger and before video makes videos shorter .

  • @Grumpy412
    @Grumpy412 5 หลายเดือนก่อน

    So when a helicopter pilot flies without knowing this, actually his mind has made these calculations unconsciously along with other things like moments, dissymmetry of lift, adverse pressure gradient, all kinds of powers like required, available, profile, induced, parasite, and all those forces like centrifugal twist, inertia etc?

  • @simonallen1064
    @simonallen1064 5 หลายเดือนก่อน

    Love all your videos. Perhaps worth mentioning the centre of pressure on your first diagram and how it fits (or doesn’t) on your main diagram?

  • @husseinabdelhamid5124
    @husseinabdelhamid5124 5 หลายเดือนก่อน

    The best explanation I have seen on this topic. Thank you very much and keep going

  • @Grumpy412
    @Grumpy412 5 หลายเดือนก่อน

    add the transverse flow roll or inflow roll to this shit and make things more clearcut lol..

  • @Grumpy412
    @Grumpy412 5 หลายเดือนก่อน

    then they say why are helicopter pilots so complicated!!

  • @biblewaytolive
    @biblewaytolive 6 หลายเดือนก่อน

    Why and how does the inter blade move slower than the outer blade??? It is one solid attachment from one end to the other. Does not make physical sense.

    • @ericray7173
      @ericray7173 4 หลายเดือนก่อน

      They’re probably connected through a planetary gear of a different ratio or something.

    • @ilovett11
      @ilovett11 หลายเดือนก่อน

      You are now discovering the difference between angular velocity and linear velocity. They have the same angular velocity. The entire blade rotates 360 degrees in the same amount of time, but since the tip of the blade is farther from the center, it must move faster to cover a greater distance in the same amount of time as the root. The root moves around the center in a small circle while the tip moves in a much bigger circle, but it takes the same amount of time. Angular velocity is degrees over time, or rotations over time (RPM). Linear velocity is distance over time. Time is constant but the distance covered is much higher for the tip than the root due to a higher radius from the center. This results in a much higher linear velocity for the tip.

  • @coolguystuff4265
    @coolguystuff4265 6 หลายเดือนก่อน

    Great explanation. Thank you for doing these videos!

  • @oleksiysokolov3510
    @oleksiysokolov3510 6 หลายเดือนก่อน

    A dumb question from a non-helicopter guy - is the rotor blade airfoil symmetric or does it have some camber?

    • @cx-ride9136
      @cx-ride9136 6 หลายเดือนก่อน

      I’m not entirely sure. As it is a high speed blade I would expect to be symmetrical however I would also assume all blades are different depending on the intended aircraft weight and rotor speed

  • @wswift7611
    @wswift7611 7 หลายเดือนก่อน

    As a helicopter pilot for 35+ years as well as an instructor for 25 years, your videos on PoF have given me immense joy to watch and reminded me so much of my good time in Bristow Redhill. Well done.

    • @heli35
      @heli35 4 หลายเดือนก่อน

      Haha, I also had some good time with Bill Barrow in Redhill.

  • @prince2179
    @prince2179 7 หลายเดือนก่อน

    To simple thanks❤

  • @djamelmeddahi4227
    @djamelmeddahi4227 8 หลายเดือนก่อน

    ealaa majhudatik The best people are those who learn knowledge and teach it. Thank you for your efforts

  • @ragiramachandran7085
    @ragiramachandran7085 9 หลายเดือนก่อน

    Great explanation

  • @merijnvanschaik4989
    @merijnvanschaik4989 9 หลายเดือนก่อน

    Eyeopener. I understood that on side would Flap up and the other would flap down. But I always thought that (flapping up, for example) would explicitly decrease the angle of attack due to the linkage staying "stationary" and forcing the angle of attacht to decrease. But now I understand it actually initiates a vertical airflow.

    • @orchidahussuhadihcro9862
      @orchidahussuhadihcro9862 20 วันที่ผ่านมา

      I find the original explanation more easy to understand. I don't really understand the induced airflow, but I was teached that the mecanical link pulled back the AoA of the blade as it was naturally getting up.

  • @wcottee
    @wcottee 9 หลายเดือนก่อน

    A little confused...why looking at points A, B, C, D do we assume that the lift vector has the same magnitude at each? Using the lift proportional to 0.5*p*V^2, V is increasing going toward the tip yielding (all things being equal like lift coefficient at each station), higher lift. What am I missing?

  • @jacklathey5223
    @jacklathey5223 10 หลายเดือนก่อน

    Brilliant 👍

  • @felipegelain6342
    @felipegelain6342 11 หลายเดือนก่อน

    Good afternoom my frien...first of all I would llike to thank you for your videos. It is beeing very enlighting. I am from Brazil and noticed that you didnt make anymore...what happened? I am looking foward to watch more of them. I wish you all the best.

    • @cx-ride9136
      @cx-ride9136 9 หลายเดือนก่อน

      Apologies, I’m about to start again in the next week or so as I just haven’t had the time to get these done.

  • @gt_inspired7311
    @gt_inspired7311 ปีที่แล้ว

    Legend 💪🏻

  • @binna_98
    @binna_98 ปีที่แล้ว

    can you describe the speed where the translational lift occurs in the graph?

    • @cx-ride9136
      @cx-ride9136 11 หลายเดือนก่อน

      Looking at the left side of the curve you can see that it rises slightly as you move from the hover. This rise in power requirement is due to the aircraft moving away from the ground cushion and losing the benefit of the big high pressure cushion beneath. This is between 0-12 Kts approx. At about 12-20 Kts the airflow across the disc is sufficient enough to start effecting the induced flow and reduce its effect. This is the point where the power required starts to drop off due to translational lift and the power curve changes direction and goes downwards.

  • @felipegelain6342
    @felipegelain6342 ปีที่แล้ว

    Hello there, First of ALL o would like to thank tou for your vídeos, everything is Very enlightening... Why did you stop? I am looking forward for more vídeos... my best regards

  • @mrbeto3777
    @mrbeto3777 ปีที่แล้ว

    allow me to download all your videos and share to others sir, thanks in advance.

  • @robhaylock7742
    @robhaylock7742 ปีที่แล้ว

    Sorry, your vector diagrams are wrong. You correctly showed the changes in Induced Flow due to flapping up and flapping down, but you left off the more important vector - the change in airflow. The RHS diagram needs an extra length added to the horizontal line (the rotational flow) for the extra airflow on the advancing side, and a negative length on the retreating side. On the RHS, if the IF stayed the same, the extra horizontal line will give a resultant vector coming in at a shallower angle, adding to the angle of attack, and on the retreating side, the shorter airflow line brings the IF arrow closer, elevating the resultant vector and reducing the AoA. But the flapping changes the IF line, adding to the RHS and subtracting from the LHS, so the AoA remains essentially the same. BUT the shorter horizontal vector means that there is more lift on the advancing side. Along comes Phase Lag - the rate of upward acceleration is at the max at 3 o'clock, but the mass of the blade means that the blade takes time to move, and the resultant high point is correctly shown at 12 o'clock. Remember that this is not gyroscopic precession, because the rotor system is not a gyroscope. The phase lag is usually around 90 degrees, but for light blades, like the R22, it is only 72 degrees.

    • @cir9968
      @cir9968 ปีที่แล้ว

      Yes, but that is not that big mistake. Are you sure that phase lag is 72 degrees for R22. I taught that phase lag is dependant of flapping hinge offset, and for R22 (semi rigid), there is not offset.

    • @badri149
      @badri149 ปีที่แล้ว

      can you pls explain the difference in phase lag angle for a heavier blade and lighter blade?

    • @cx-ride9136
      @cx-ride9136 6 หลายเดือนก่อน

      I have added a longer vector on the adv side but the increase change of AoA is not relevant for flapping to equality as the aim is to show that the disc does not roll to the retreating side but instead flaps back because the thrust reduces slowly as the blade lifts. Phase angle is something different I’m afraid and is more related to inputs from the cyclic and the reaction in relation to the control orbit. Flapping to equality does take place then but it is not due to phase lag. Phase lag is always 90 degrees but your advance angle might be different on different helicopters.

  • @russellgrundy8534
    @russellgrundy8534 ปีที่แล้ว

    Hi More video please. I am doing my instructor rating and would like some more of your excellent video to use inconjunction with the AP3456 notes. They are excellent. thanks for your time and effort.

  • @saunjeevthamilchelvan5792
    @saunjeevthamilchelvan5792 ปีที่แล้ว

    Tqvm!!!

  • @tactcom7
    @tactcom7 ปีที่แล้ว

    Finally! Someone proficiently explains why flapping up reduces the aoa and vice versa. Thanks.

  • @alexanderyasa3721
    @alexanderyasa3721 ปีที่แล้ว

    You're the best (detailed, complete, concise, clear) when it comes to aviation vector diagram! Can't believe this channel doesnt have millions of subscribers! Keep it up you're so helpful.

  • @RussellSneddon
    @RussellSneddon ปีที่แล้ว

    Love the videos, any chance of you doing one on recirculation. Thanks

  • @giorgosgalanikas6490
    @giorgosgalanikas6490 2 ปีที่แล้ว

    Amazing analysis

  • @makemyselfyoung1978
    @makemyselfyoung1978 2 ปีที่แล้ว

    You are such a great explanations about the theory. Thanks a lots

  • @markthomasson5077
    @markthomasson5077 2 ปีที่แล้ว

    Sorry, but I think this is rubbish. Forget all your diagrams, take a model airplane propeller, hold it against an airflow, it will spin with a negative incidence. Try spinning it the opposite way round, it will slow down and spin the opposite direction. Rotors of gyrocopters have a negative 1.5deg incidence. Think of the rotors as glider wings, instead of going forward they spin in a circle. And as we know gliders wings point downwards, otherwise they would stall. Basically your diagrams are incorrect. Firstly it would be more clear if you show the centre of forces going through the centre of the spar. The force on the foil should be shown at right angles to the plane of the foil. You will then see that in all the cases the drag is always backwards

    • @gkooistra91
      @gkooistra91 2 ปีที่แล้ว

      This explanation is not rubbish. It is very much correct. The lift force should not be drawn at right angles from the plane of the foil, but at right angles from the relative wind, like he has done. Together with the drag it will create the resultant force. He is always drawing the drag backwards in his diagrams, however, with the angle of the lift pointing forwards enough (90 degrees of the relative wind) the resultant force is pointing forward, dragging the rotor forward driving the rotordisk. This is a correct explanation and I would advise you to watch it again and maybe find some other explanation which will show you very much the same thing.

    • @gkooistra91
      @gkooistra91 2 ปีที่แล้ว

      The rotation of the rotor is one part of the relative wind, the other is the air coming from below due to the descending profile during a autorotation. This relative wind is at an angle causing the lift vector to point forward. Due to it being a rotor the outward part of the rotor is experiencing a much higher horizontal velocity the the part closer to the rotorhub. Due to this difference in speed at the ends of the rotor the resultant aerodynamic force (combination of drag and lift) point to the rear, decelerating the blade. However, closer to the rotorhub the horizontal airflow velocity is less, however the vertical velocity remains the same. This increases the angle of the relative wind causing the lift vector to point more forward. The resultant force will therefor still be pointing forward, even though the drag is still pointing to the rear, accelerating the blade. Setting the correct pitch on the rotorblade will cause a equilibrium between the driving and driven part of the rotor. You are trading altitude for rotorspeed.

    • @markthomasson5077
      @markthomasson5077 2 ปีที่แล้ว

      I finally got my head round this. What I know understand is that the aerodynamic neutral plane of an aerofoil is perhaps 3 deg down from the geometric plane. Therefore a positive incidence to the aerodynamic neutral plane is in fact a negative 1deg. I define the aerodynamic neutral plane of an aerofoil is when the foil goes neither up nor down in an airflow.

  • @wiwipapillon6928
    @wiwipapillon6928 2 ปีที่แล้ว

    Very clear and concise explanations, even for a newbie like me. Congrats

  • @JohnDoe-js5cq
    @JohnDoe-js5cq 2 ปีที่แล้ว

    Excellent video!

  • @buythedip463
    @buythedip463 2 ปีที่แล้ว

    Why transition on forward flight to hover

  • @nicholasbarbier3310
    @nicholasbarbier3310 2 ปีที่แล้ว

    that is the best explanation I have ever had. thank you so much for this tutorial.

  • @abdellahchihab585
    @abdellahchihab585 2 ปีที่แล้ว

    Good explanation thanks Please what do you mean by TR ( Thrust Reduction )and TQ.

    • @cx-ride9136
      @cx-ride9136 2 ปีที่แล้ว

      Apologies. Poorly annotated. It should just say TQ not TR. the TQ comes down twice. TQ is always coloured yellow in my diagrams.

  • @ernestocheguevara4032
    @ernestocheguevara4032 2 ปีที่แล้ว

    Great explanation,does the highest and lowest points have something to do with the gyroscopic precession?

    • @cx-ride9136
      @cx-ride9136 6 หลายเดือนก่อน

      No gyroscopic precession no. The high and low points are due to the 360 degree nature and that an input on one side has an equal and opposite input on the other side of the disc. The high and low will be opposite each other and the points at which they reach the top and bottom is simply due to the inability for the blade to instantaneously move to the furtherest extent.

  • @tusharbali8932
    @tusharbali8932 2 ปีที่แล้ว

    some videos regarding phase lag and advance angle also.

  • @tusharbali8932
    @tusharbali8932 2 ปีที่แล้ว

    you videos are highly appreciated

  • @tusharbali8932
    @tusharbali8932 2 ปีที่แล้ว

    please add videos about zero speed auto rotation, loss of tail rotor effectiveness, functioning of tail rotor. thanks

  • @johnbelvedere4521
    @johnbelvedere4521 2 ปีที่แล้ว

    Great explanation, thanks.

  • @matthewmcclune7855
    @matthewmcclune7855 2 ปีที่แล้ว

    Brilliant video, thanks! Do you have an email I could contact you on with some questions? Thanks!