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เข้าร่วมเมื่อ 20 ธ.ค. 2023
Clear Math Concepts
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X = 22 and Y = -2...Easy
boring solution 😢
x = a+b, y = a−b x+y = a+b+a−b = 2a = 20 ⇒ a = 10 xy = (a+b)(a−b) = a²−b² = 44 ⇒ b² = a²−44 = 56 ⇒ b =±2√14 x = 10±2√14, y = 10∓2√14.
it is Hungary.
Actually this spelling came in vidiq . So I wrote the same.
This isnt Algebra tho????
Живу и учусь в России. У нас на первом курсе университета по математике очень любят просить найти производную функции f'(x) = x**x**x**x. Очень хотелось бы посмотреть на ваш вариант решения задачи)
Good explanation
Use GP sum formula to solve. Answer=(8^6-1)/7=37449
Good question
Only one of infinite many answers if complex numbers are included.
Good solution
great video, but, can you add delay next time before the youtube video suggestions? i could barely see the end part.
Easy method...... Thank uu for this ....
good explaination
Nice solution
good 👍
I think there's a mistake around the 6:00 minute mark. The 1 shouldn't be in the numerator.
This video was super helpful!!
Don't make videos anymore, idiot.
No positive solutions. I want to point out any attempt to use irrational-base numbers is "illegal", since it invites the unwanted consistency of a black-hole.
Very well explained 💌
Good solution
Excellent
nice
Good question
Why so serious _joker laugh_
Good Equation....
Graphical solution method. Draw a radius-10 circle centered on the origin of the complex plane. The first root m_0=10 is the point where the circle intersects the real axis. Mark six equally spaced points on the circle, m_0 through m_5, starting with the above point m_0. Done.
How do you type questions for your Thumbnail?
I typed on PowerPoint and took SS and then paste on canva
I must say it is easier(at least for me) to just make a variable(let's say t, for example) and t=the square root of x(written as sqrt(x) in C++), therefore the ecuation becomes t*t+t*sqrt(5)=10, also written as t^2+t*sqrt(5)-10=0. Here you just calculate delta(I'm going to write it as d) with the formula d=b^2-4ac, where a=1, b=sqrt(5) and c=-10. After the calculations, d=45. Then we calculate t with the formula (-b+sqrt(d))/(2*a) or (-b-sqrt(d))/(2*a), depending on which root of the ecuation we try to go for first. After that, t takes the values sqrt(5) and -2*sqrt(5). Because at the begining we defined t as sqrt(x), therefore t>=0 (the sign ">=" it means "is bigger than or equals" in programming). Also, because we have sqrt(x) and x is a real number, not complex, x>=0. Because the roots of our binomial ecuation is sqrt(5) and -2*sqrt(5) and t>=0, that means that -2*sqrt(5) is not a solution for t, therefore sqrt(5) is the only solution for t. That means that sqrt(x)=sqrt(5), from which x=5.
Frankly is the same way you did it, but I just shortened it out. This method helps in case of time crisis on an exam or on a deadline
I really like your way of teaching
I really like your way of teaching
Good question 😊
my exam became easier thanks!!
Are you an Indian?
No
6:25 i didn’t understand this part
Here I apply the algebraic identity a^2 + b^2 +2ab= (a+b)^2 So here a value is (a^2+b^2) And b value is ab Now I hope you understand Thank you so much for watching my video.
@@CMathC oh ok thanks, i thought you were replacing the expression with a and b if different value
Good
❤😅
No! The third and fourth solutions are not m=n, but instead the relation is m+n+1=0, so if m3=-6, then n3=5 and if m4=5, then n4=-6 (yes, of course the two solutions are mirroring each other, since m and m are indistinguishable in the problem).
good effort
your solution is not complete, there are infinite many branches of complex log, thus we would expect 2 times infinite many solutions. suggest -1 = exp(-i *pi ) * exp(2 i * n* pi) with n being any integer number -oo < n < oo
LHS: exp(ln5+i(2n+1)pi x) RHS: exp(ln5 +i 2m pi) we have 2 integer independent parameters n, m in the solution
Proper Content
Education best way to go
Nicely explained
X = 4
I dont like your brute force method ! You must be clever with this kind of problem Let me know to explain to you how to approach this problem !
Explain please
@@CMathC I will explain the approach to you, it's up to you to continue... Let x = √2 -1 → x^2 = (√2 -1)^2 = 3-2√2 = 1-2x → x^3 = x^2*x = (1-2x)*x = x-2x^2 = x -2(1-2x) = 5x-2→ x^5 = x^2 * x^3 = (1-2x)*(5x-2) = 29x -12 x^10 = x^5*x^5 ...→ x^12 = x^10*x^2 ... → Compute the product of factors finction of x and substitue x by his value at the end... Method based on the progressive calculation of powers of x function of x
Your channel very helpful maam
Good expression
x=√2-1; x^2=3-2√2=1-2x; x^3=x(1-2x)=x-2+4x=5x-2; x^6=(5x-2)(5x-2)=25x^2-20x+4=29-70x x^12=(29-70x)(29-70x)=29^2-2*70*29x+70^2x^2=29^2+70^2-2(70*29+70^2)x=5741-13860x=0.000025508902624 Check: x^12=(√2-1)^12=0.000025508902624
Nice solution maam
good stuff!!!