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DrDynamics
เข้าร่วมเมื่อ 19 มี.ค. 2014
Screencasts of Dynamics lectures (and other interesting videos) for Engineering Dynamics at the University of Denver (Spring 2014).
Bradley Davidson, PhD
Bradley Davidson, PhD
วีดีโอ
2021-09-29 Motion Constraints; Rolling.MP4
มุมมอง 15ปีที่แล้ว
2021-09-29 Motion Constraints; Rolling.MP4
2021-03-08 Diagonal and Triangular Matrices mp4
มุมมอง 2ปีที่แล้ว
2021-03-08 Diagonal and Triangular Matrices mp4
2021-03-01 Graphical Methods of Solving Algebraic Equations mp4
ปีที่แล้ว
2021-03-01 Graphical Methods of Solving Algebraic Equations mp4
2021-02-26 Linear Algebraic Equations mp4
มุมมอง 2ปีที่แล้ว
2021-02-26 Linear Algebraic Equations mp4
2021-02-19 Open Methods Newton Raphson mp4
มุมมอง 8ปีที่แล้ว
2021-02-19 Open Methods Newton Raphson mp4
2021-02 -15 Bracketing Methods Bisection mp4
มุมมอง 5ปีที่แล้ว
2021-02 -15 Bracketing Methods Bisection mp4
2021-01-29 Unknown Iterations, tolerances mp4
มุมมอง 8ปีที่แล้ว
2021-01-29 Unknown Iterations, tolerances mp4
2021-01-11 Command Window and Workspace Basics
มุมมอง 36ปีที่แล้ว
2021-01-11 Command Window and Workspace Basics
Two-Dimensional Plotting and Annotations
มุมมอง 3473 ปีที่แล้ว
Two-Dimensional Plotting and Annotations
Particle Dynamics 14.2 - Generalized Angular Momentum Form of Newton’s 2nd Law
มุมมอง 2117 ปีที่แล้ว
Particle Dynamics 14.2 - Generalized Angular Momentum Form of Newton’s 2nd Law
Particle Dynamics 14.1 - Generalized Angular Momentum
มุมมอง 3357 ปีที่แล้ว
Particle Dynamics 14.1 - Generalized Angular Momentum
Particle Dynamics 13.3 - Simple Pendulum EOM using Angular Momentum
มุมมอง 1.2K7 ปีที่แล้ว
Particle Dynamics 13.3 - Simple Pendulum EOM using Angular Momentum
Hello, thank you so much for the very complete video on mechanics. I have a question: at 26:29, you have written the expression of inertial velocity in terms of versors of the moving frame. I know that this is possible because in the end inertial velocity is just a vector and can be expressed in any base we want but... how is it physically possible? I mean, the moving frame cannot really "see" such a thing as the inertial velocity, so it feels quite impossible to express inertial velocity in terms of moving frame versors, because by the point of view of a moving observer, this vector doesn't exist at all!
thank you sir i am a nanotech student and this was really helpfull to me for my homework
7:56 How is the fact that the length of the displacement vector remains constant enough to imply that its components remain constant? Surely this is implied by the fact that you have a reference frame that is fixed relative to the rigid body.
HUGE HELP💯💯👏
great💥💥💥
Thank you, but can it be explained more because I can't understand why some equations are put there sometimes
Your Particle Dynamics playlist is a life saver. Thanks for videos. They are very helpful
Thanks a lot for your lectures. could u please give us a title book for this suject
Thank you. Very concise.
You didn't "solve" the problem. You didn't solve for the tension force in terms of the state variables, and you didn't state an equation of motion in terms of that solution.
6:59 at this point of proving the equation i realized that all your unit vectors are b, which are the basis of the body coordinate system, does that mean that the results of transport theory are in the body frame.
6:43 can the center of rotation or the position of the resulting (resulting after the summation ) axis of rotation be determined ? 8:08 what book ?
Thank you!
Thank you Dr Dynamics! This is such a well structured course, it is unfortunate I didn't stumble upon these lectures 5 years ago. I'm taking notes and following along quite happily :) Best wishes and much thanks from Canada!
Thank you sir for the complete , thorough and excellent explanation of this topic! I look forward to completing this and your other lectures.
Thanks for this awesome playlist. Will there be any continuation of this series to 3 dimensions?
Thanks for this excellent set of tutorials. Did you by any chance make any more on further topics in the book on dynamics in 3 dimensions?
I've been working on a problem for a few hours now - without doubt, this video allowed me to see from a different perspective. Much thanks for this video. Very clear and concise.
This was quite possibly the most unnecessarily complicated explanation for something that should be extremely simple. Idk why it has so many likes
Mechanics moet beter les gaan geven.
Add infinitum "Thank you". Specially for normalizing the angulur momentum.
Thank you, thank you, thank you! I've seen so many videos looking for exactly that. I am enormously thankful. Very well explained.
bro, if you reference an "earlier example" could you perhaps link to said video?
Free Body Diagram is totally wrong!!, both springs are exerting the force on the mass in the same direction!!!!! - (k1*x1) - (k2*x2) = m*a
Thank you!! This is helpful > - <
Thank you. It helped a lot
or.. you could factor the r^4/4 and use a more useful identity cos^2(theta)+sin^2(theta)=1 :)
Why is it that when you take d/dt(e_t) you end up with a positive e_n and not negative?
If these kind of videos had a billion views imagine where our world would be today.
nice
Thank Mr
Beautifully described! Thank you :)
@ DrDynamics: Can you please post the final equation. I would like to verify with mine. Also, I would appreciate if you could suggest references on where to find the solution for the nonlinear diff eqn obtained (WITHOUT) any simplifications. Thanks.
Christophe, this is explained in a screencast from the particle dynamics course that sets up polar frame. Linked here: th-cam.com/video/5ollsV9u5B0/w-d-xo.html For context, it may be helpful to watch the screencasts preceding it (7.1 through 8.1). I'll embed this info in the video itself so that others with this question can track down the info. Thanks for watching! The Transport Equation is one of the best discoveries ever for developing kinematics related to a noninertial reference frame!
DrDynamics thanks for making this video! It is helpful. However, i'm trying to look for an explanation of how we jump from x * d(i)/dt, to w x r? I'm not sure how the position times the derivative of the unit vector translates into omega_b cross product r_p/o'? You said you proved it in another video of yours? That would be really helpful. Thanks!
@Oskar, Thanks for the complement. I'm glad people are finding it. This screencast is from the Rigid Body Dynamics course I teach at the University of Denver. Its based on the excellent textbook "Engineering Dynamics: A Comprehensive Introduction" by Kasdin and Paley. www.amazon.com/Engineering-Dynamics-A-Comprehensive-Introduction/dp/0691135371 My class accesses it through another website (EdPuzzle); and it looks like TH-cam doesn't count those views. Feel free to share these screencasts with others you think could use it.
that' s very helpfull. thank you.
Hey Dr., at 26:09, does the car slip inwards or outwards? Because in reality, the car should slip outwards, but the acceleration in en is facing inwards!
It's going to slip outward. However, recall that it will slip because the friction needed to stay on the curve is no longer there. When the car slips, the dynamics change. It is no longer going around the curve, but going in straight line motion and there is no normal acceleration.
at 19:08, maybe the eb = et *en inestead of eb = et*eb
Yes. The correct expression is: e_b = e_t x e_n
Hey Dr, I think that at 30:45, you missed to multiply acceleration with time when finding final velocity!!
At 14:55, there should be underline for vector rp/o(t)