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aanandit151096 @ gmail . com remove space and send your updated cv

aanandit151096@gmail.com

aanandit151096@gmail.com

aanandit151096@gmail.com

aanandit151096@gmail.com

Apka number de diya hu required hone par contact kiya jayega

Apka number aur apka qualification de diya hu supervisor ko Vo apse contact karenge jab required hoga

@@Electrical_Supervisor ok sir ap apna contact number de dijiye sir

Ambernath, Maharashtra, India

@@Electrical_Supervisor ok sir a jaye ge ap apna number send kar dijiye sir

Electrical Engineer

Ambernath, Maharashtra

Kitni salary expect kar rahe ho ?

Aur work experience kitna hai ?

We use upto 300 sqmm 3.5C

400 sq mm cable 3.5 cor full Amps ???

Electrical supervisor work under electrical engineer. And electricians work under electrical supervisor

63 mm

75

Ultratech

Ok

For theory, look at the Contactor diagram and then go to the controlling panel and do the practical with an experienced person.

Method -1 We talk about 3 phase, heavy load, and Aluminium cable. According to Ampere load = near by available cable size Example-1, 60A load, here available cable near below 60 are 50 sqmm and 35 sqmm If the cable length below 100 mtrs we use 35 sqmm If the cable length above 100 mtrs we use 50 sqmm cable. Example-2, 300A load, here available cable near 300 are 300 sqmm and 240 sqmm If the cable length below 100 mtrs we use 240 sqmm cable and if the cable length above 100 mtrs we use 300 sqmm cable. You may use 2 run of 150 sqmm cable against 300 sqmm single cable. Similarly for 1000A load We use 3 run of 300 sqmm cable For 1600A load we use 5 run of 300 sqmm cable. For Copper cable multiply the Ampere by 1.2 and use above method. Method -2 For below 30A load and copper cable ...we just use Below 1KW load - 1.5 sqmm 2-3 KW load - 2.5 sqmm 3-5 KW load - 4 sqmm 5-9 KW load - 6 sqmm 9-12 KW load - 10 sqmm 12-16 KW load - 16 sqmm 16-25 KW load - 25 sqmm For aluminium cable Divide the load(KW) by 1.2 and use above method ☝️

If you want to use formula then I recommend use formula Power in KW(Load) = Volt x Current x power factor Example 3 phase load given 8 KW So, 8 KW = 8000W = 415(volt) x I(current) x 0.8 (pf) You Get I (current ) = 8000/(415*0.8) = 24A Now for safety I = 24 x 1.5 or 2 = 36 to 48 A Now search on google current capacity of Cu cable If you found 6 sqmm cable capacity = 33 A 10 sqmm cable capacity= 45 A And you calculate your current capacity= 36A to 48A According to your calculation 10 sqmm cable better for safety but you may use 6 sqmm cable too.

Number kis liye chahiye bhai

InshAllah jald hi banaunga