I don't think you've made your diagrams small enough because I can still see them albeit with my glasses on. If your aim was to make sure we didn't see the diagrams on youtube then you failed because I can still see them with my glasses on or with an electron microscope, you need to make your diagrams even smaller that way nobody can ever see what the fuck you're doing.
@@coolwinder No, is not. The gain factor on a Jfet is its transconductance and it is dependent of the current in the drain. The gain of the first excercise explained is Vout = Vin*gm*R ... all this assuming it is not connected to any load in witch case the final expression will be Vout = Vin*gm*(R//Rl). One more thing, you might see gm as Yfs. Same thing, different name.
Amazing video! We're building a community to help young engineers get ready for their technical interviews and would really appreciate your support! th-cam.com/channels/7h3PROcX7Zgx00alQokJ-w.html
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👍 I am New, thank you😊 vout2/vin=Av=GM*Rout=-gm1*ro...answer vout1/vin=gm/1+gmRs..answer vout/vin=GM*Rout=0..answer
thank you
I don't think you've made your diagrams small enough because I can still see them albeit with my glasses on. If your aim was to make sure we didn't see the diagrams on youtube then you failed because I can still see them with my glasses on or with an electron microscope, you need to make your diagrams even smaller that way nobody can ever see what the fuck you're doing.
sir make more questions like this
thank you sir
This was so much fun! Pls continue :)
The circuit on the left is source degenerated so the effective gm will be gm/(1+gmR). And the gain will be gm effective *ro
@pragz92 my answer is the same as You
You're wrong! The small signal voltage gain of that circuit is not equal to zero.
It's not wrong, check this video: th-cam.com/video/P0OjpBJsLOE/w-d-xo.html
It is correct. Unless the model is different then the one showed. Pls grasp whats your model.
@@coolwinder Totally nonsense!
@@coolwinder No, is not. The gain factor on a Jfet is its transconductance and it is dependent of the current in the drain. The gain of the first excercise explained is Vout = Vin*gm*R ... all this assuming it is not connected to any load in witch case the final expression will be Vout = Vin*gm*(R//Rl). One more thing, you might see gm as Yfs. Same thing, different name.
Groups of 3,3,2 is very smart.
Amazing video! We're building a community to help young engineers get ready for their technical interviews and would really appreciate your support! th-cam.com/channels/7h3PROcX7Zgx00alQokJ-w.html
i failed.... lol
I support ur channel. Plz upload circuit design related videos for interviews
Hi Shanmukha, check us out for engineering interview related questions. We'd love to hear your feedback! th-cam.com/channels/7h3PROcX7Zgx00alQokJ-w.html
nice