วีดีโอ

9^n - 4^n = 65. *. 65 = 81 - 16 = 9x9 - 4x4 = 9^2 - 4^2 **. n = 2./.

N^2 - N^3 = 2 *. 2 = 1 - (-1) = (-1)^2 - (-1)^3 ** N = -1./.

2X^2 + X - 6 = 0 *. X^2 + 0,5X + 3 = 0 3 = 1x3 = 1,5x2 2 - 1,5 = 0,5 = (b') **. 2: 2(2x2) + 2 - 6 8 + 2 - 6 # 0 -2: 8 - 2 - 6 = 0 ** 1,5: 2(1,5x1,5)+1,5-6 4,5 + 1,5 - 6 = 0 *** X' = 1,5 , X" = -2./.

3X + Y = 9, 2X - 3Y = -5. *. 3X + Y = 9 = 6 + 3 = 3x2 + 3. ** 2X - 3Y = -5 = 4 - 9 = 2x2 - 3x3. ***. X = 2, Y = 3./.

X + Y = 7 , 3X - Y = 5. * X + Y = 7 = 4 + 3 . **. 2X - Y = 5 = 2x4 - 3 = 8 - 3 . ***. X = 4 , Y = 3./.

X^2 - X^3 = 150. *. 150 = 25 + 125 = 5x5 + 5x5x5 = (-5x-5) - (-5x-5x-5) = (-5)^2 - (-5)^3 **. X = -5./.

3X + Y = 13 , X + 2Y = 1. *. 3X + Y = 13 = 15 + ( -2) = 3x5 + (-2) **. X + 2Y = 1 = 5 + 2(-2) = 5 - 4 . ***. X = 5 , Y = -2./

X^2 - 9X + 18 = 0 *. 18 = 2x9 = 3x6 3 + 6 = 9 = (b) **. 3: 3x3 - 9x3 + 18 9 - 27 + 18 = 0 6: 6x6 - 9x6 + 18 36 - 54 + 18 = 0 *** X' = 6 , X" = 3./.

I used a more efficient method; (x - 2)(x - 4) = 0, x = {2, 4}.

x(x² - 2x - 3) = 0, x(x - 3)(x + 1) = 0; x = {-1, 0, 3}.

Ans is x minus 3

Mc you ruined my time 🤬🤬

पागल अच्छे से तो समझा

Thanks man! This was really helpful and concise

I used the Magic X method and got the same answers.

Bro this is literally the easiest problem, the thumbnail isn't even clickbait

XX - 6X + 8 = 0 * 8 = 1x8=2x4 2 + 4 = 6 = (b) ** 2: 2x2 - 6x2 + 8 4 - 12 + 8 = 0 ** 4: 4x4 - 6x4 + 8 16 - 24 + 8 = 0 *** X' = 2 ,X" = 4./.

2XX + X - 15 = 0 *. XX + 0,5X - 7,5 = 0 7,5 = 1,5x5= 2,5x3 3 - 2,5 = 0,5 = (b') ** 3: 2(3x3) + 3 - 15 18 + 3 - 15 # 0 -3: 18 - 3 - 15 = 0 ** 2,5: 2(2,5x2,5) + 2,5 - 15 12,5 + 2,5 - 15 = 0 ***. X' = 2,5 , X" = -3 ./.

XX + 6X + 9 = 0 * 9 = 1x9=1,5x6= 3x3 3 + 3 = 6 = (b) ** 3: 3x3 + 6x3 + 9 9 + 18 + 9 # 0 -3: 9 - 18 + 9 = 0 *** X' = X" = - 3./.

XX + 3X + 4 = 0 * 4 = 1x4 = 2x2 4 - 1 = 3 = (b) **. 4: 4x4 + 3x4 + 4 16 + 12 + 4 # 0 -4: 16 -12 + 4 # 0 ** 1: 1x1 +3x1 + 4 1 + 3 + 4 # 0 -1: 1 - 3 + 4 # 0 *** XX + 3X (-) 4 = 0

2XX - 3X + 1 = 0 *. XX - 1,5X + 0,5 = 0 0,5 = 1x0,5 = 2x0,25 1 + 0,5 = 1,5 = (b') **. 1 : 2(1x1) - 3(1) + 1 2 - 3 + 1 = 0 ** 0,5: 2(0,5x0,5)-3(0,5)+1 0,5 - 1,5 + 1 = 0 *** X' = 1 , X" = 0,5./.

VERY INTERESSING KEEP UPLOADING BRO YOUR GONNA BE BIG ONE DAY

Hello mr am your student town campus DME/N/1782/09/23 And have subscribe 🙏

thanks sir alot

thx sir

Where is the (x+h)^3 coming from

Interesting! This is the first time I am hearing of hexadecimal 😅. You explain the concepts very well Calvince! And the handwriting is very neat! 👌

Do we have to write the base on the answer

must you prove or it's okay when you get the answer.

Solve for 6x+40=31x

XX + 4X - 5 = 0 * 5 = 1 x 5 = 2,5 x2 5 - 1 = 4 = (b) ** 5 : 5x5 + 4x5 - 5 25 + 20 - 5 # 0 -5 : (-5x-5) + 20(-5) - 5 25 - 20 - 5 = 0 ** 1 : 1x1 + 4x1 - 5 1 + 4 - 5 = 0 *** X' = -4 , X" = 1 ./.

* XX - 6X + 8 = 0 * 8 = 1 x 8 = 2 x 4 2 + 4 = 6 = ( b) * 2 : 2 x 2 - 6 x2 + 8 4 - 12 + 8 = 0 * 4 : 4 x4 - 6 x4 + 8 16 - 24 + 8 = 0 *** X' = 2 , X" = 4 ./.

* 2 XX + 3X - 9 = 0 XX + 1,5 - 4,5 =0 * 4,5 = 1 x 4,5 = 1,5 x 3 3 - 1,5 = 1,5 = ( b' ) * 3 : 2x3x3 + 3 x3 - 9 18 + 9 - 9 # 0 -3 : 2(-3 x-3) +3(-3) - 9 18 - 9 - 9 = 0 * 1,5 : 2(1,5 x 1,5) + 3x1,5 - 9 4,5 + 4,5 - 9 = 0 *** X' = 1,5 , X" = - 3 ./.

* XX + 5X - 6 = 0 * 6 = 1 x 6 = 2 x 3 = 6 - 1 = 2 + 3 = 5 = ( b) * 6 : 6 x6 + 5 x6 - 6 36 + 30 - 6 # 0 -6 : (-6 x-6) + 5(-6) -6 36 - 30 - 6 = 0 * 1 : 1 x1 + 5 x1 - 6 1 + 5 - 6 = 0 *** X' = 1 , X" = -6./.

* XX - 2X - 899 = 0 * 899 = 900 - 1 = (30+1)(30-1) = 31 x 29 31 - 29 = 2 (b) ** 31 : 31 x 31 - 2 x 31 - 899 961 - 62 - 899 = 0 * 29 : 29 x 29 - 2 x 29 - 899 841 - 58 - 899 # 0 - 29 : 841 + 58 - 899 = 0 * X' = 31 , X" = -29 ./.

very,very good, I got it from the first

Love this

😍

Love it

Thanks

Very well articulated. Thanks

I find that if you move first √x to the right side ,getting √(x - 11) = 11-√x, and then square the two sides, you simplify your calculation a lot.

Heres my thought process 1. (6+2i)(3-4i) can be simplified to 3(6+2i)-4i(6+2i) 2. 3(6+2i)-4i(6+2) = (18+6i)(-24-8i²) 3. Using foil, we get -48i³ - 288i² - 432i 4. Find the gcf, so we get -48(i² + 6i + 9) 5. Simplify again, so it's -48(i+3)(i+3) 6. Simplify once again, so it's -48(i+3)²

You forgot to do a check! 3x+y=13, 3(5)+(-2)=13, 15-2=13, 13=13 x+2y=1, 5+2(-2)=1, 5-2(2)=1, 5-4=1, 1=1

Yes I can, by simple examination and common sense. These are binary numbers (powers of two) meaning one of them has to be 128. That leaves twenty (20), which must be 16 + 4. 2^7 = 128 2^4 = 16 2^2 = 4 2, 4, 7 About a minute to a minute and a half. By the way that would be the binary number, 01001010.

Bro voice bhot hi Kam ha Asa lagta ha ka mute ki hoa ha

I solved this equation in about 5 minutes. a=7, b=4, c=2. First, set a as high as possible not to exceed 148, then set b as high not to exceed 148. So a=7, b=4, that's 144. Only thing left is to set c=2, so 2^2 is 4. That is: 144+4 equals 148. Simple as that, no equations necessary. This video was 15 minutes long, I solved the equation in third of the time, by just experimenting with a calculator. Elementary, my dear Watson!

Thanks this has helped me out

Unaeza Fanya ya division of hexadecimal