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Calvince Online Math
Kenya
เข้าร่วมเมื่อ 8 มี.ค. 2023
This channel provides tutorial videos on General Mathematics, algebra, trigonometry, precalculus, calculus and sciences such as Physics and Chemistry.
Math Olympiad Exponential Problem | Very Easy Solution | m=?
An interesting approach to solving this Olympiad Exponential Problem.
#maths #matholympiad #education #mathematics #mathoperation
#maths #matholympiad #education #mathematics #mathoperation
มุมมอง: 12
วีดีโอ
Math Olympiad | A Nice Algebra Problem
มุมมอง 82 ชั่วโมงที่ผ่านมา
This is a nice algebra problem with very interesting concepts!
A Nice Math Olympiad Algebra Equation | Germany Math Olympiad
มุมมอง 144 ชั่วโมงที่ผ่านมา
This video tutorial displays an amazing way of tackling a German Olympiad math question. Various mathematical concepts are also displayed in the process.
Matrix Method | Solving Simultaneous Equations | How to Solve Simultaneous Equations Using Matrices
มุมมอง 6712 ชั่วโมงที่ผ่านมา
This video tutorial explains how to solve simultaneous equations using matrix method.
Definite Integrals | Evaluating the Value of Definite Integrals | Calculus
มุมมอง 2612 ชั่วโมงที่ผ่านมา
This video tutorial explains how to evaluate definite integrals.
Quotient Rule
มุมมอง 1312 ชั่วโมงที่ผ่านมา
This video focuses on applying the Quotient Rule to differentiate.
Basic Differentiation
มุมมอง 2214 ชั่วโมงที่ผ่านมา
This video focuses on applying basic differentiation techniques to polynomials.
Scalar Multiplication of Matrices | Matrix Addition | Matrix Subtraction | Square of a Matrix
มุมมอง 6914 ชั่วโมงที่ผ่านมา
This video tutorial focuses on scalar multiplication, matrix addition, matrix subtraction and square of a matrix.
Differentiation from First Principles | Derivative
มุมมอง 5514 ชั่วโมงที่ผ่านมา
This tutorial video focuses on differentiation from First Principles. derivative #differentiationfromfirstprinciples #calvinceonlinemath #reasoning #calculus #excellenceacademy #derivatives #jonahemmanuel #riverstateunivesity #function #limit #substitution #precalculus #firstprinciple #putme #jambnigeria #nigeriantutors
Floating Point Representation | Single Precision | Discrete Mathematics
มุมมอง 18วันที่ผ่านมา
In this video tutorial, we explain how to convert a fraction decimal number to binary in a single precision floating point representation. We start by converting the whole number portion to binary by dividing by the base (2) while noting the remainders. We then convert the fraction portion by multiplying by 2 while noting the remainders. Next, we combine the two and move the decimal point compl...
Can You Solve? A Nice Math Olympiad Problem
มุมมอง 33วันที่ผ่านมา
This video tutorial explains how to solve the nice Olympiad Math problem. We begin by splitting -5 into -1 and 5, then we rewrite -1 as i-squared before we apply laws of logarithms. #viralvideo #viralmathvideo #viralmathproblem #viralolympiadproblem #viralmath olympiadquestion #funnymatholympiad #simpleviralvideo #bestviralvideo #viralvideo #mathvideo #matholympiad #matholympiadproblem #calvinc...
Floating Point Representation | Single Precision | Discrete Mathematics
มุมมอง 74วันที่ผ่านมา
In this video tutorial, we explain how to convert a fraction decimal number to binary in a single precision floating point representation. We start by converting the whole number portion to binary by dividing by the base (2) while noting the remainders. We then convert the fraction portion by multiplying by 2 while noting the remainders. Next, we combine the two and move the decimal point compl...
Math Olympiad | Logarithms | A Nice Olympiad Math Logarithm Problem | VietNam Math Olympiad
มุมมอง 15วันที่ผ่านมา
This video tutorial explains in a step by step manner, how to solve a VietNam Math Olympiad problem. We are required to find the sum of all real roots. vietnam math olympiad, vietnam, vietnam math, olympiad, math olympiad, trending vietnam math video, vietnam viral video, how to solve vietnam college math, vietnam university math, vietnam common entrance exam, vietnam college math problem, viet...
Median Quartiles | Lower Quartile, Upper Quartile, Percentiles | Statistics | Calvince Online Math
มุมมอง 235วันที่ผ่านมา
Median Quartiles | Lower Quartile, Upper Quartile, Percentiles | Statistics | Calvince Online Math
Math Olympiad | A Nice Math Olympiad Algebra Problem.
มุมมอง 33วันที่ผ่านมา
Math Olympiad | A Nice Math Olympiad Algebra Problem.
Quadratic Equations | Using Quadratic Formula
มุมมอง 184วันที่ผ่านมา
Quadratic Equations | Using Quadratic Formula
Quadratic Equations Completing the Square
มุมมอง 5314 วันที่ผ่านมา
Quadratic Equations Completing the Square
Quadratic Equations Factorization Method
มุมมอง 6714 วันที่ผ่านมา
Quadratic Equations Factorization Method
Binomial Expansion, Pascal's Triangle, Finding Coefficients, Algebra
มุมมอง 13714 วันที่ผ่านมา
Binomial Expansion, Pascal's Triangle, Finding Coefficients, Algebra
Olympiad Math | A Nice Exponential Problem
มุมมอง 30514 วันที่ผ่านมา
Olympiad Math | A Nice Exponential Problem
Math Olympiad Style Exponential Problem
มุมมอง 9421 วันที่ผ่านมา
Math Olympiad Style Exponential Problem
Mastering the Laws of Logarithms: Simplify and Solve with Confidence | Must-Watch Tutorial!
มุมมอง 5128 วันที่ผ่านมา
Mastering the Laws of Logarithms: Simplify and Solve with Confidence | Must-Watch Tutorial!
Quadratic Equations | Completing the Square Method
มุมมอง 42หลายเดือนก่อน
Quadratic Equations | Completing the Square Method
Laws of Logarithms - Solving logarithmic Equations
มุมมอง 44หลายเดือนก่อน
Laws of Logarithms - Solving logarithmic Equations
Matrices - Multiplication of 2x2 Matrices
มุมมอง 19หลายเดือนก่อน
Matrices - Multiplication of 2x2 Matrices
I solved this equation in about 5 minutes. a=7, b=4, c=2. First, set a as high as possible not to exceed 148, then set b as high not to exceed 148. So a=7, b=4, that's 144. Only thing left is to set c=2, so 2^2 is 4. That is: 144+4 equals 148. Simple as that, no equations necessary. This video was 15 minutes long, I solved the equation in third of the time, by just experimenting with a calculator. Elementary, my dear Watson!
Thanks this has helped me out
I am glad
Unaeza Fanya ya division of hexadecimal
Very clean and elegant solution. 👍 What about the factors 1 and 65 ? X+Y =65 X-Y= 1 X=32 Y=31
Thank you
Remember the bases were squares, so we pick a product that yield squares for us to get an integer solution.
49/5=9.8
I did it without a calculator.
Brilliant
Input 49^(2 - 0.25 log(7, 25)) = 480.2 Result True Logarithmic form (2 - 0.25 log(7, 25)) log(49, 49) = log(49, 480.2)
Input 49^(1 - 0.25 log(7, 25)) = 9.8 Result True Logarithmic form (1 - 0.25 log(7, 25)) log(49, 49) = log(49, 9.8)
Will you please give the course outline of GENERAL MATHEMATICS
What level of study?
@@CalvinceOnlineMath diploma
Thank you sir 😊❤
My pleasure
(2^x)/(2^x) = 1/(2^x) => 1 = 2^(-x) => 2^x = 2^(-x) => x = 0
25
Thank you sir for your cooperation.
It's my pleasure
Nhi hua
bhai kuch bol to
🙏🙏
🙇🙇🙇
I got it right first try 😎 not a hard problem
I’m glad
2
By inspection 4x3=12 and 2x9=18, therefore x=2 and y=1. Took about 1/5 of the time
It all depends on the intent, the long way displays more concepts
طريقة صحيحة
Please which software are you using to edit your thumbnail video
Canva
Clearly done, but no need to work out both scenarios. From (1) / (2) you got x - y = 1 Just plug it back into (1) 2^(1-y) x 3^y = 12 so 2^y x 3^y = 6 6^y = 6 => y = 1, so x = 2
Good insight
Bro really 💀
The boy used a clickbit
Why divide by 2? Instead I multiplied it first by 2, then by 4 (so times 8 overall) thus avoiding fractions in my working until the last step.
Completing the square method requires that you make the coefficient of x squared be 1
Ok good one
Ok good one
where is 4 coming from
Which 4 are you referring to please?
It. Can. Do. Medilturm. Fraction. For. X.
Nice explanation
Thank you so much
Well solved
Thank you
Thanks I also have a channel: youtube.com/@charlesokuom8747?si=biUQfDG5NFGiDJnh
Thanks I also have a channel: youtube.com/@charlesokuom8747?si=biUQfDG5NFGiDJnh
Division 1-i -1
Multiplication 34-13i 5i-3
Subtractions 6+4i _2+12i
5+2i 4+13i
Easily factored instead of completing the square: (2x - 3)(x + 3) = 0, so x = 3/2 & -3.
X= 2 y=1
0 , -1 , 3
Nice video
Thank you
X=3 or -1
Pythagorean theorem
After x=2 at 0.48 by elimination, substitute for x into either equation and solve for y. No need for a second elimination process. 🇦🇺
2*5√2 = √2x 10√2=√2x 100*2=2x 200=2x x=100
3x^2+3x+4x+4=0 3x(x+1)+4(x+1) (3x+4)(x+1) x=-4/3 dan x=-1
😢 "PromoSM"
Wonderfully done!
Thank you so much Jared
THANKS PROFESOR !!!, VERY INTERESTING !!!
ANYTHING 'to the power 0' = 1 So x = 0
True
5x-y=4 2x+y=10 5x+2x-y+y=4+10 7x=14 x=2 5(2)-y=4 10-y=4 -y=-6 y=6 2(2)+y=10 4+y=10 y=6 (x, y)=(2, 6) ❤